mongo deleteOne not a function [duplicate] - mongodb

This question already has answers here:
How to delete documents by query efficiently in mongo?
(5 answers)
Remove only one document in MongoDB
(9 answers)
Closed 4 years ago.
I have a simple action I'm trying to take to delete a single record in my db. I'm following the instructions to the letter:
db.users.deleteOne({login:"theUsersName"})
But for some reason I'm getting the following error:
TypeError: Property 'deleteOne' of object synctup.users is not a function
What am I missing here????

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PostgreSQL IN matches any value in list - how do I match all values in list? [duplicate]

This question already has answers here:
PostgreSQL where all in array
(9 answers)
Closed 2 years ago.
In PostgreSQL IN can be used to match any value in a list. What if I need to match all values in a list? Is there a way to do this in PostgreSQL?
try = ALL (subquery) instead of IN (see manual)

mongo db how to use cursor function to find a condition with if statement? [duplicate]

This question already has answers here:
How do I perform the SQL Join equivalent in MongoDB?
(19 answers)
MongoDB return True if document exists
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Closed 4 years ago.
Hi guys I have created a cursor in mongo db to find a condition which is shown below
var mycursor = db.catalog.find({})
mycursor.forEach(function(x)
{if(x.book.find({"publisher":{"$exists":true ,"$ne" : ""}})
{print("Publisher","Empty", " publishes book ",
x.book.title, "published at", x.book.publish_date)}})
What i want my function to do is find all publishers whose value is " " and then print the values respectively I know my if statement is incorrect I am just confused as to how i would write one for this case if anyone can point me to the right direction I will be grateful

Is there anyway to use mongodb to search for ANY instead of omit the query? [duplicate]

This question already has answers here:
Programmatically build dynamic query with Mongoose
(3 answers)
Dynamic queries in MongoDB and Node.js
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Closed 5 years ago.
Is there anyway to use mongodb to search for ANY instead of omit the query.
Example
db.users.find({country:"Vietnam", gender:ANY}).pretty()
instead of
db.users.find({country:"Vietnam"}).pretty()

MongoDB only removing first field from the collection [duplicate]

This question already has answers here:
Why this update query only update one record once
(3 answers)
Closed 7 years ago.
I'm a beginner in MongoDb.I wanted to know what is the query to remove a field in Mongo DB Collection.I have tried with
db.Component.update({},{$unset: {vendor:""}}).
Its was updating only first document.So How to remove field Completely from Collection?
Try this-db.Component.update({},{$unset: {vendor:""}},false,true)
Here false

In Mongo, how do I display the indexes of a collection? [duplicate]

This question already has answers here:
A list of indices in MongoDB?
(7 answers)
Closed 8 years ago.
I just want to display all the indexes in the shell.
If you want raw access to the indexes, you can query the db.system.indexes collection:
> db.system.indexes.find()
To find the indexes for a specific collection, you can do:
> db.collection.getIndexes()
See this question.