I have many folder like data_1,data_2, data_3 etc, that will be generated during program running. I want to copy these folders into .tar file named full_data.tar in a specified folder.
How can I insert folders named data_1,data_2, data_3 etc into full_data.tar in MATLAB by using UNIX commands?
As #kedarps already proposed I would also use the command line. The matlab command to execute command line arguments is:
status = system(command)
It is documented under this link:
system documentation
So if I take the unixcommand from #kedarps this should work:
system('tar -cvf full_tar.tar data_1 data_2 data_3')
I hope this helps
Related
I've just created a script file in MATLAB, but can not run it. The name of my script is getEnvFiles.m. When I first tried to run it, I got the following result:
>> getEnvFiles
'getEnvFiles' is not found in the current folder or on the MATLAB path, but exists in:
\\wsl$\ubuntu\home\me
Change the MATLAB current folder or add its folder to the MATLAB path.
So, I added this directory (which is actually the current directory) to the search path, but still got the same result:
>> addpath('\\wsl$\ubuntu\home\me')
>> getEnvFiles
'getEnvFiles' is not found in the current folder or on the MATLAB path, but exists in:
\\wsl$\ubuntu\home\me
Change the MATLAB current folder or add its folder to the MATLAB path.
When I check the path, it looks like this directory is on the path:
>> path
MATLABPATH
\\wsl$\ubuntu\home\me
I can further verify that this directory is my present directory:
>> pwd
ans =
'\\wsl$\ubuntu\home\me'
and that getEnvFiles.m is in this directory:
>> ls
. .emacs.d HarborData
.. .emacs~ RawHarborData
.bash_history .landscape at
.bash_logout .motd_shown getEnvFiles.m
.bashrc .profile test.m
.bashrc~ .sudo_as_admin_successful
.emacs
Is the issue that I'm using wsl (Windows Subsystem for Linux), or do I have some other misunderstanding?
Type rehash and then try running your script again. Even though you have added the new directory to your path, you need to update the path cache so that it knows about the new scripts it can see.
The problem seems to lie in WSL's ability to add new files to the directory. When I create a new script within MATLAB, and try to run it, I get the problem discussed above. However, running already existing files is not a problem. For now, my only solution is to close MATLAB after creating a new script and reopen it. Then, I can run it. Although, oddly, I can't open it in MATLAB's editor.....
This may or may not help, but ...
Sometimes you have to prepend execution with .\ in order to run scripts in PowerShell or from within the command prompt (in Windows, I'm not sure about other operating systems).
I get this error quite often, especially when not in Admin mode.
Does this work?
% Get path of executing script.
filePath = matlab.desktop.editor.getActiveFilename; % Note that this isn't necessarily the same as the output of 'pwd()'.
% Or: filePath = mfilename('fullpath')
% Make sure all nested directories of filePath are on the path, then tell MATLAB where you're working.
addpath( genpath( filePath ) ); % If this fails, try one folder up the tree:
% addpath( genpath( fullfile( filePath, '.' ) );
cd( filePath );
Alternatively, it looks like you might have written and saved the script, and then typed it into the command window to execute. If it's not a special type of script (Function/Class/GUI/etc.) then you can simply click 'Run' in the Editor tab (or the F5 key) and MATLAB should prompt you with a 'Change Folder' option, to which you should acquiesce.
If you're running this script through the WSL terminal, try my suggested code.
I see no way to set destination directory or file here: http://www.cs.cmu.edu/~quake/triangle.switch.html
Actually, the program places result file in the same directory, even if current directory is different.
Why? Is ti possible to change?
The output files for the program are generated from the input file names. You can see this from the source code on line 3586
strcpy(b->outnodefilename, b->innodefilename);
...
strcat(b->outnodefilename, ".node");
strcat(b->outelefilename, ".ele");
...
Because of that I don't think there is a way to set the output directory as an option. It seems you will need to manually copy the output files to a different directory
cp output.node your/output/dir/output.node && rm output.node
Setup:
Windows 7 Enterprise.
Matlab 7.10.0 (R2010a).
mcc compiler: Microsoft Visual C++ 2008 Express.
What's happening:
My project runs fine when running it through Matlab, but when trying to run the .exe through the command prompt after using mcc to compile, the command prompt generates an error.
The mcc command I issue is:
mcc -m -v STARTUP1.m -o EXE_REDUC
The error I receive in the command prompt is:
??? Error using ==> textscan
Invalid file identifier. Use fopen to generate a valid file identifier.
I have a file called LoadXLS.m that loads and reads a .csv file using:
fid = fopen(file,'r');
temp_data = textscan(fid,...args...);
And then I process temp_data.
The csv file I'm trying to load is called spec.csv. It is located two directories down from where I have STARTUP1.m stored. The location of STARTUP1.m is also the place that the mcc generated files are stored to. I have used the pathtool to "Add with subfolders" this location, but am aware that those locations are not transferred to mbuild when compiling.
What I've Tried:
I have gone in and added print statements to print the value of fid to make sure it is valid. When I run it in Matlab, it has a valid value, however when I run in the command prompt it always returns an invalid value of -1.
I have removed all addpath() calls, I have tried adding the STARTUP1.m directory to the mcc ctf archive using:
mcc -m -v -a 'C:\Users\...path...\STARTUP1.m_location' STARTUP1.m -o EXE_REDUC;
However when I do this, I get a different error when running in the command prompt:
Cannot open CTF archive file
'C:\...path...\AppData\Local\Temp\mathworks_tmp_7532_28296'
or
'C:\...path...\AppData\Local\Temp\mathworks_tmp_7532_28296.zip'
??? Undefined function or variable 'matlabrc'.
To fix this, I've tried adding the pragma
%#function matlabrc
to the top of STARTUP1.m to try and enforce its inclusion, but had no success.
I also copied the spec.csv file to a new directory in the ctfroot and changed
fid = fopen(...)
to:
[tempFile, message] = fopen(fullfile(ctfroot, 'Added Config Files', ad.spec_file));
The message is:
message is: No such file or directory
Objective:
Rearranging file locations is a sufficient workaround while the exectuable only runs on my computer, however the idea is to take this standalone and distribute it to multiple people on many different computers. I would like to be able to have a top folder with a startup file and within this folder, have as many subfolders as the package requires. The startup file should be able to access all subfolders and files within them as necessary.
I read something about the exectuable actually running from a "secret location" on the machine here: http://matlab.wikia.com/wiki/FAQ
I would just like to be able to group one entire folder tree with all its files into a package containing the executable and be able to run it anywhere.
More info:
When I put the spec.csv file in the same directory as STARUTP1.m, it finds it fine using mcc without the -a 'path' option and using the following in the LoadXLS.m file:
[tempFile, message] = fopen(ad.spec_file,'r');
This project contains GUIs, generates PDFs, generates plots, and also creates a zip directory.
Thank you in advance.
I have three files 1.zip, 1.z01 1.z02. I would like to extract and join them into a file.
In Ubuntu command line I'm using zip -FF name.zip --out name_joinde.zip
I would like to do this in Matlab, but with the zip command I'm getting an Invalid zip file error. How can I joint this files?
You cannot do it in one shot. But it is easy to do systematically using the zip and unzip commands:
%% Unzip files into "tempdir" directory (will create the directory if needed)
unzip('MyFruits.zip', 'tempdir')
unzip('MyColors.zip', 'tempdir')
%% Zip all files in "tempdir" directory into Joined.zip
zip('Joined.zip', '*.*', 'tempdir')
%% Delete the "tempdir" directory and all of its subdirectories
rmdir('tempdir', 's')
Try using the
unzip(..)
command first, and then
zip(..)
How about just using ! or system to call the Ubuntu command directly from within MATLAB?
I am using the system command in MATLAB as follows (with the current directory being 'scripts'):
[status, result] = system('cd ..\\TxtInOut')
However, invoking the system command does not seem to work. It returns status = 0 and result = ''.
Any suggestions?
If you want to change directories, you should use the CD command. The argument can be either a full path or relative path:
cd('c:\matlab\toolbox'); %# Full path to a directory
cd('scripts'); %# Move to a subdirectory "scripts"
cd('..\TxtInOut'); %# Move up one level, then to directory "TxtInOut"
If you want information about a directory, you should use the DIR command. DIR will return an m-by-1 structure of information for a directory, where m is the number of files and folders in the directory. Again, the argument can be either a full path or relative path:
data = dir('c:\matlab\toolbox'); %# Data for a full path to a directory
data = dir('scripts'); %# Data for a subdirectory "scripts"
NOTE: When working on different platforms (i.e. Windows or UNIX), you will have to pay attention to whether you use the file separator \ or /. You can get the file separator for your platform using the function FILESEP. You can also build your file paths using the function FULLFILE.
Any command executed by "system" is external to MATLAB. A command shell is generated, executes your request, and then returns the result. The 0 result indicates successful completion: the command shell changed its current directory as requested and then returned. (Command shells use non-zero to indicate an error, because there are usually many more ways that a program can fail than succeed.) Unfortunately that only affects the command shell's current directory - see gnovice's answer for how to actually change the directory.
you can use cd, dir, ls, etc directly in matlab without call system functions.
You can also use the underlying operating system commands by preceding them by an exclamation sign.
For instance:
!dir will show you the current directory contents in Windows
!pwd will show you the current directory in Linux/Mac
But calling cd does not change the current directory!