I currently have a dataset where the range of results span between the dates: 15-01-2017 to 30-04-2018
So therefore, my min(date) would be 15-01-2017.
However, I want to return results whereby if my min(date) is not a complete month, it should give me the results from next full month onwards (i.e.: 01-02-2017 to 30-04-2018).
Hoping to get some direction
Thank you
This will return the start of the next month unless it's the first of the month:
trunc(add_months(min(datecol)-1,1), 'mon')
Add one month to the day before the min date (i.e. only the 1st will result in the previous month), then get the 1st of that month.
Depending on your actual query you might filter using
qualify datecol >= trunc(add_months(min(datecol) over (partition by ??)-1,1), 'mon')
Related
I want to get the whole day of the week depend on the date, my query is working and getting the result that I want but when the date value is Sunday, result changes.
I'm starting the result from Mon to Sunday.
Examples below:
My Code:
SELECT UserID,Scdl_TkIN as TimeIn, Scdl_TkOut as [TimeOut]
FROM EmployeeTimekeeping
WHERE CONVERT(DATE,Scdl_TkIN) >= dateadd(day, 2-datepart(dw, '2022-04-23'),CONVERT(date,'2022-04-23'))
AND CONVERT(DATE,Scdl_TkIN) < dateadd(day, 9-datepart(dw, '2022-04-23'), CONVERT(date,'2022-04-23'))AND UserID ='15020009'
ORDER BY CONVERT(DATE,Scdl_TkIN)
1st display is correct, but when I change the value into '2022-04-24' , the result is now the second pic but I want the result still 1st pic.
If I got it right you want the whole week of data given a single date.
I'm not 100% sure about your date logic and I'd rather use the WEEK as a filter as it seems clearer, that said the issue you have is the value of SELECT ##DATEFIRST.
By default its value is 7, meaning that Sunday is considered the first day of the week, that's why you get that "unexpected" result.
here is my solution, but just setting SET DATEFIRST 1; should give you the expected result.
SET DATEFIRST 1;
SELECT
UserID
,Scdl_TkIN as TimeIn
,Scdl_TkOut as TimeOut
FROM EmployeeTimekeeping
WHERE
DATEPART(WEEK,Scdl_TkIN) = DATEPART(WEEK,'2022-04-23')
AND YEAR(Scdl_TkIN) = YEAR('2022-04-23')
AND UserID ='15020009'
ORDER BY
Scdl_TkIN
Note: if you decide to use WEEK for filtering you will have to choose between WEEK and ISO_WEEK
Edit: when using week you must also consider the year in the filter
I am having trouble with a task in Tableau. I need to pull in a value for each month, but the value originates in the following month (month + 1). For example, in January, I need to pull a beginning value from February, and then in February I need to pull a beginning value from March. The idea is to take the beginning value from the following month to calculate the difference from the ending value from the current month. The data I have is snapshot based, so there is one column which is the Date column, which can be 1/1/2020, or 2/1/2020 etc. (its done by month, not days).
My instinct is to create a calculated field and say something along the lines of 'where snapshot = snapshot (current) + 1 month, take in this value' but that does not work because they are not equal. I need to create a separate column or LOD for the future month I think? or a parameter?
ex.
{fixed [date], [ID]: SUM( [Date] = Dateadd('month',1,[Date]) Then [Begin Value] End)}
I found the answer. I needed to use the LOOKUP() function.
I have a date column which I am trying to query to return only the largest date per month.
What I currently have, albeit very simple, returns 99% of what I am looking for. For example, If I list the column in ascending order the first entry is 2016-10-17 and ranges up to 2017-10-06.
A point to note is that the last day of every month may not be present in the data, so I'm really just looking to pull back whatever is the "largest" date present for any existing month.
The query I'm running at the moment looks like
SELECT MAX(date_col)
FROM schema_name.table_name
WHERE <condition1>
AND <condition2>
GROUP BY EXTRACT (MONTH FROM date_col)
ORDER BY max;
This does actually return most of what I'm looking for - what I'm actually getting back is
"2016-11-30"
"2016-12-30"
"2017-01-31"
"2017-02-28"
"2017-03-31"
"2017-04-28"
"2017-05-31"
"2017-06-30"
"2017-07-31"
"2017-08-31"
"2017-09-29"
"2017-10-06"
which are indeed the maximal values present for every month in the column. However, the result set doesn't seem to include the maximum date value from October 2016 (The first months worth of data in the column). There are multiple values in the column for that month, ranging up to 2016-10-31.
If anyone could point out why the max value for this month isn't being returned, I'd much appreciate it.
You are grouping by month (1 to 12) rather than by month and year. Since 2017-10-06 is greater than any day in October 2016, that's what you get for the "October" group.
You should
GROUP BY date_trunc('month', date_col)
I am creating a view where i have multiple records showing up for each month.
Example: January is showing 20 records and February is showing 30 records. I only want the last record of EACH MONTH to show up. So i want to see 1 record for each month.
I have already tried the first() and last() table calculation, but it does not filter by month, but by column.
If you just apply first and last on the dataaset then you won't get the correct output, If you need for every month then you need to divide the partition to year and month and then apply the max on the specific partition.
Try this way:
Place the order date in Exact date format and change the property to discrete
Now extract the year and month in separate calculated fields and place in detail.
Year:
year(Date)
Month:
Month(date)
Now create one more calculated field and write below code:
WINDOW_MAX(MAX([Order Date]),FIRST(),LAST())
Try This
1 Calculated Field - DateMonth
Datetrunc('month',Date)
2 Calculative field - LastDate
{ FIXED DateMonth: max(Date)}
3 Calculative Field- Filter
if lastDate=Date then 'Yes' else 'No' end
I've been working on this problem for a while now. Basically I have a simple set of data with UserId, and TimeStamp. I want to know how many distinct UserId's appear each week, the catch is my week is measured in Sunday-Saturday, NOT Monday - Sunday, which is what Weekofyear() uses.
Right now I'm hardcoding each week and running the query:
SELECT
count(distinct UserId)
FROM data.table
where from_unixtime((CAST(timestamp as BIGINT)))
between TO_DATE("2016-06-05") AND TO_DATE("2016-06-12")
I'm trying to find a way to shift the timestamp back a day to trick weekofyear into thinking my Sunday is actually a Monday, but have not been successful. My latest futile attempt looked like:
SELECT
count(distinct UserId), weekofyear(date_sub(from_unixtime(CAST(timestamp as BIGINT)),1))
FROM table.data
where from_unixtime((CAST(timestamp as BIGINT)))
between TO_DATE("2016-06-01") AND TO_DATE("2016-06-30")
group by weekofyear(date_sub(from_unixtime(CAST(timestamp as BIGINT)),1))
This results in the same numbers as if I didn't subtract a day. I not sure why this isn't working. I feel like there should be a way to manage this. Right now if I wanted to pull all the data by week WHERE X is true, I'd have to manually do each week, that won't be sustainable. Any suggestions on how to work smarter?
Thank you.
Simple Solution
You can simply create your own formula instead of going with pre-defined function for "week of the year"
Advantage: you will be able to take any set of 7 days for a week.
In your case since you want the week should start from Sunday-Saturday we will just need the first date of sunday in a year
eg- In 2016, First Sunday is on '2016-01-03' which is 3rd of Jan'16
--assumption considering the timestamp column in the format 'yyyy-mm-dd'
SELECT
count(distinct UserId), lower(datediff(timestamp,'2016-01-03') / 7) + 1 as week_of_the_year
FROM table.data
where timestamp>='2016-01-03'
group by lower(datediff(timestamp,'2016-01-03') / 7) + 1;