Sort multiple condition MongoDB - mongodb

Question

I have collection of user, and this is the following of documents :
{ "_id": 1, "name": "A", "online": 1, "like": 10, "score": 1 },
{ "_id": 2, "name": "B", "online": 0, "like": 9, "score": 0 },
{ "_id": 3, "name": "C", "online": 0, "like": 8, "score": 1 },
{ "_id": 4, "name": "D", "online": 1, "like": 8, "score": 0 },
{ "_id": 5, "name": "E", "online": 1, "like": 7, "score": 1 },
{ "_id": 6, "name": "F", "online": 0, "like": 10, "score": 1 },
{ "_id": 7, "name": "G", "online": 0, "like": 5, "score": 0 },
{ "_id": 8, "name": "H", "online": 0, "like": 13, "score": 0 }
{ "_id": 9, "name": "I", "online": 0, "like": 6, "score": 0 }
I want to show the list of users with some of criterias and ordering with some conditons, online users and most liked in the top of the list,after online user list is show offline users with most scored & most liked. The following of rules :
If online is 1 must be sort by descending of like.
If online is 0 and score is 1 must be sort by descending of score.
If online is 0 and score is 0 must be sort by descending of like.
So, the result can be like :
{ "_id": 1, "name": "A", "online": 1, "like": 10, "score": 1 },
{ "_id": 4, "name": "D", "online": 1, "like": 8, "score": 0 },
{ "_id": 5, "name": "E", "online": 1, "like": 7, "score": 1 },
{ "_id": 6, "name": "F", "online": 0, "like": 10, "score": 1 },
{ "_id": 3, "name": "C", "online": 0, "like": 8, "score": 1 },
{ "_id": 8, "name": "H", "online": 0, "like": 13, "score": 0 }
{ "_id": 2, "name": "B", "online": 0, "like": 9, "score": 0 },
{ "_id": 9, "name": "I", "online": 0, "like": 6, "score": 0 },
{ "_id": 7, "name": "G", "online": 0, "like": 5, "score": 0 }
I have finished until point 2, my query following :
db.users.aggregate([
{
$project :
{
"id" : 1,
"name" : 1,
"online: 1,
"like" : 1,
"score" : 1,
"sort" : {
$cond:
{
"if" :
{
$eq : ["$online", true]
},
"then" : "$like",
"else" : "$score"
}
}
}
},
{
$sort :
{
"online" : -1,
"sort" : -1,
"id" : 1
}
},
{
$skip : 0
},
{
$limit : 9
}
])
But I have the current result following :
{ "_id": 1, "name": "A", "online": 1, "like": 10, "score": 1 },
{ "_id": 4, "name": "D", "online": 1, "like": 8, "score": 0 },
{ "_id": 5, "name": "E", "online": 1, "like": 7, "score": 1 },
{ "_id": 6, "name": "F", "online": 0, "like": 10, "score": 1 },
{ "_id": 3, "name": "C", "online": 0, "like": 8, "score": 1 },
{ "_id": 2, "name": "B", "online": 0, "like": 9, "score": 0 },
{ "_id": 7, "name": "G", "online": 0, "like": 5, "score": 0 },
{ "_id": 8, "name": "H", "online": 0, "like": 13, "score": 0 }
{ "_id": 9, "name": "I", "online": 0, "like": 6, "score": 0 },
You can see, based on point 3, instance { "_id": 8, "name": "H", "online": 0, "like": 13, "score": 0 } should be on top with score is 0

Answer 1

First create additional column call point with value (1 - online)*score
After this sort data by:
online desc
point desc (online = 1 pointbe always 0, online is 0 point is score)
like desc
You can use this query
db.yourtable.aggregate(
[
{ $project:{
"id" : 1,
"name" : 1,
"online": 1,
"like" : 1,
"score" : 1,
point: { $multiply: [
{$subtract: [1,"$online"]}
, "$score"
]}
}
}
,{ $sort : { online: -1, point : -1, like : -1 } }
]
);

Answer 2

Please check below query :
db.getCollection('yourTable').aggregate([
{
$project :
{
"id" : 1,
"name" : 1,
"online": 1,
"like" : 1,
"score" : 1,
onlineSortLike: {
$cond: {
if: { $and: [{ $eq: ['$online',1 ] }] },
then: '$like',
else: 0,
},
},
sortOfflineScore: {
$cond: {
if: { $and: [{ $eq: ['$online',0] }] },
then: '$score',
else: 0,
},
},
sortOfflineScoreLike: {
$cond: {
if: { $and: [{ $eq: ['$online', 0] }] },
then: '$like',
else: 0,
},
},
}
},
{
$sort :
{
"online" : -1,
"onlineSortLike" : -1,
"sortOfflineScore" : -1,
"sortOfflineScoreLike" : -1
}
},
{
$skip : 0
},
{
$limit : 9
}
])