Given the following JSON, I'm trying to get all documents that match "myemail#domain.com". I need a case insensitive filter. I thought if I added i to the value it would perform the search but no luck.
I'm very new to MongoDB so excuse me if this is a simple issue.
{
"_id" : ObjectId("5aecc56d2a7e7a408c9767e3"),
"Children" : [
{
"Email" : "MyEmail#Domain.com",
"Children" : [
{
"Name" : "Some name",
"Value" : "some value",
}
]
}
]
}
var email = "myemail#domain.com";
var filter = Builders<Subscription>.Filter.Eq("Children.Email", $"/{email}/i");
return await context.Subscriptions.Find(filter).ToListAsync();
There's a dedicated class BsonRegularExpression which can be used as a parameter of Regex method. Simple Eq will try to perform regular equality comparison here. Try this:
var email = "myemail#domain.com";
var filter = Builders<Subscription>.Filter.Regex("Children.Email", new BsonRegularExpression(email, "i"));
return await context.Subscriptions.Find(filter).ToListAsync();
Related
I'm struggling to create a find query that finds nodes that contain "Item1".
{
"_id" : ObjectId("589274f49bd4d562f0a15e07"),
"Value" : [["Item1", {
"Name" : "John",
"Age" : 45
}], ["Item2", {
"Address" : "123 Main St.",
"City" : "Hometown",
"State" : "ZZ"
}]]
}
In this example, "Item1" is not a key/value pair, but rather just a string that is part of an array that is part of a larger array. This is a legacy format so I can't adjust it unfortunately.
I've tried something like: { Value: {$elmemmatch:{$elemmatch:{"Item1"}}}, but that is not returning any matches. Similarly, $regex is not working since it only seems to match on string objects (and the overall object is not a string, but a string in an array in an array).
It seems like you should use the $in or $eq operator to match value.
So try this:
db.collection.find({'Value':{$elemMatch:{$elemMatch:{$in:['Item1']}}}})
Or run this to get the specific Item
db.collection.find({},{'Value':{$elemMatch:{$elemMatch:{$in:['Item1']}}}})
Hope this helps.
var data = {
"_id":"ObjectId('589274f49bd4d562f0a15e07')",
"Value":[
[
"Item1",
{
"Name":"John",
"Age":45
}
],
[
"Item2",
{
"Address":"123 Main St.",
"City":"Hometown",
"State":"ZZ"
}
]
]
}
data.Value[0][0] // 'Item1'
Copy and paste on repl it works.
There was an error on structure ofr your data
I know this is a bit of newb question but I'm having a hard time figuring out how to write a query to find some information. I have several documents (or orders) much like the one below and I am trying to see if there is any athlete with the name I place in my query.
How do I write a query to find all records where the athleteLastName = Doe (without case sensitivity)?
{
"_id" : ObjectId("57c9c885950f57b535892433"),
"userId" : "57c9c74a0b61b62f7e071e42",
"orderId" : "1000DX",
"updateAt" : ISODate("2016-09-02T18:44:21.656Z"),
"createAt" : ISODate("2016-09-02T18:44:21.656Z"),
"paymentsPlan" :
[
{
"_id" : ObjectId("57c9c885950f57b535892432"),
"customInfo" :
{
"formData" :
{
"athleteLastName" : "Doe",
"athleteFirstName" : "John",
"selectAttribute" : ""
}
}
}
]
}
You need to use dot notation to access the embedded documents and regex because you want case insensitive.
db.collection.find({'paymentsPlan.customInfo.formData.athleteLastName': /Doe/i}
how can I return a specific value for a specific document in MongoDB? For example, I have a schema that looks like:
{
"_id" : "XfCZSje7GjynvMZu7",
"createdAt" : ISODate("2015-03-23T14:52:44.084Z"),
"services" : {
"password" : {
"bcrypt" : "$2a$10$tcb01VbDMVhH03mbRdKYL.79FPj/fFMP62BDpcvpoTfF3LPgjHJoq"
},
"resume" : {
"loginTokens" : [ ]
}
},
"emails" : {
"address" : "abc123#gmu.edu",
"verified" : true
},
"profile" : {
"companyName" : "comp1",
"flagged" : true,
"phoneNum" : "7778883333"
}}
I want to return and store the value for profile.flagged specifically for the document with _id : XfCZSje7GjynvMZu7. So far I have tried:
db.users.find({_id:'myfi3E4YTf9z6tdgS'},{admin:1})
and
db.users.find({_id: 'myfi3E4YTf9z6tdgS'}, {profile:admin});
I want the query to return true or false depending on the assigned value.
Can someone help? Thanks!
MongoDB queries always return document objects, not single values. So one way to do this is with shell code like:
var flagged =
db.users.findOne({_id: 'myfi3E4YTf9z6tdgS'}, {'profile.flagged': 1}).profile.flagged;
Note the use of findOne instead of find so that you're working with just a single doc instead of the cursor that you get with find.
The correct answer here is the method .distinct() (link here)
Use it like this:
db.users.find({_id:'myfi3E4YTf9z6tdgS'},{admin:1}).distinct('admin')
The result will be: 1 or 0
I was trying to change the strength based on the hero name in a document like this:
"_id" : ObjectId("52b0d27b5dee463864000001"),
"author" : "niko",
"permalink" : "super_heroes"
"hero" : [
{
"name" : "Batman",
"strength" : 1,
"magic" : [ ],
"times" : [ ]
},
I couldn't change it when initially trying:
var operator = { '$set' : { 'hero.strength' : strength } };
var query = { 'permalink': permalink , 'hero.name':name };
posts.update(query, operator, options, function(err, numModified) {...})
I got MongoError: can't append to array using string field name: strength.
But after seeing this post I added a dollar sign and it worked:
var operator = { '$set' : { 'hero.$.strength' : strength } };
What did that dollar sign in a JSON key do? I tried googling it, but I just came up with a million explanations of what jQuery is. Thank you.
This is not a JSON operator (there is no such things as JSON operator. You might think that JSON is a string).
In this context $ is a mongodb positional operator to perform update in a specific position.
I use from Mongodb and my database schema like this:
firstName: 'vahid',
lastName: 'kh',
age: 12
I want find all records that firstname + lastname likes 'vahid kh'. In SQL, this would be:
Select * from table where firstName + lastName like '%vahid kh%'
Seems this is available only in 2.4, which was released today.
> db.temp.save({ "firstName" : "Bob", "lastName" : "Smith", Age : 12 });
> db.temp.find();
{ "_id" : ObjectId("5148a2a00477cddcdece1b34"), "firstName" : "Bob", "lastName" : "Smith", "Age" : 12 }
> db.temp.aggregate({ $project : { "name" : { $concat : [ "$firstName", " ", "$lastName" ] } } });
{
"result" : [
{
"_id" : ObjectId("5148a2a00477cddcdece1b34"),
"name" : "Bob Smith"
}
],
"ok" : 1
}
You can use $regex, this way you can use partial matches.
Something like that:
db.collection.find( { field: /acme.*corp/i } )
Here is somewhat similar question with answer in php: MongoRegex and search multiple rows in collection
Docs about mongoregex are here: http://docs.mongodb.org/manual/reference/operator/regex/
Edit:
I just read your comment with query in sql. Simple solution could be to make field fullname and search it with $regex, it is kind of db denormalization, where you store somewhat redundant data.
Or even easier, this should do the job too:
db.collection.find( { firstName: /*vahid/i, lastName: /kh*/i } )
To search against a combination of two or more fields, you need to use the aggregation framework. It lets you sort by the combinations of fields, and you don't need to store (denormalize) any extra fields:
db.collection.aggregate([
{
$match: {
// Optional criteria to select only some documents to process, such as...
deleted: null
}
},
{
$addFields: {
// Need to prefix fields with '$'
fullName: { $concat: [ "$firstName", "$lastName" ] },
}
},
{
$search: { fullName: /.*vakid kh.*/ },
}
]);
Explanation:
the $addFields aggregation pipeline stage creates dynamic, on-the-fly fields
$concat creates the fullName field by concatenating the first and last name
$search does a regular expression search, which is the MongoDB equivalent to the SQL LIKE operator.
I have code in expressjs code aggregate is bit slow then find so I have use conditional based and use regular express to find true results, I am sharing with you nodejs code I hope it useful for you or my other code lover friends.
router.get('/publisher/:q',function(req,res){
var q = ucfirst( req.params['q'] );
var qSplit = q.split(" ");
var db = mongojs(CONNECTION_STRING, ['tags_helper','users']);
var query = { "status" : 1, isAdmin : { $exists : false } };
console.log(qSplit);
if( qSplit.length > 1 )
{
query["firstName"] = new RegExp(qSplit[0],"i");
query["lastName"] = new RegExp(qSplit[1],"i");
}
else
{
qSplit[0] = new RegExp(qSplit[0],"i");
qSplit[1] = new RegExp(qSplit[0],"i");
//query.push( { $or : [ {"firstName": new RegExp(q,"i")},{"lastName": new RegExp(q,"i")} ] } );
query["$or"] = [ {"firstName": new RegExp(q,"i")},{"lastName": new RegExp(q,"i")} ];
}
db.users.find( query,{_id : 1,firstName:1,lastName:1,image:1,profileName:1}).limit(10,function (err, users) {
//TODO your further code ..
});
});
Have a happy coding day.