sed to replace a string which consist of a forwardslash - sed

I'm trying to replace below specific lines in a file
/ACCOUNT/passwd=
/BMC/CONFIRMATION/PASSWORD=
I need help in preparing the sed command
The required output would look something like this
/ACCOUNT/passwd=-2$-$A88CA7BD3DADDDFFC
/TMC/CONFIRMATION/PASSWORD=-2$-$A88CA7BD3DADDDFFC
Any help is appreciated.

There is nothing special about the forward slash, except if you choose to use it as the delimiter in your sed command, so don’t:
sed 's,ACCOUNT/passwd=,ACCOUNT/passwd=-2$-$A88CA7BD3DADDDFFC,g'
And similar for other target strings.
Here I’ve used a comma as the delimiter. You can choose another character as you prefer.

Related

Using Two Regex Strings in SED

I have this text file where I need to first find a string "BEGINNING" and then find a string "HERE" after the first "BEGINNING" but only once. And there can be any amount of strings in between. This must be done with SED commands so no awk. I know I can simply do /BEGINNING/ to find the first one but I don't know how to put the two together in one SED command.
something like this?
$ sed -n '/BEGINNING/,${/HERE/{p;q}}' file
may be supported only by GNU sed, not sure.

Sed replace specific substring

I have a file that's generated as an output to an SQL query. I need to replace the nulls in the file with blanks, so something like
sed -e"s/null//g" would work.
However there's a valid string of the form 'null/' (with a trailing forward slash) and that should not be replaced. Is there a way to replace only 'null' values while leaving 'null/' intact?
The sed one-liner:
sed 's#null\([^/]\|$\)#\1#g' file
should work for your requirement.
It searches pattern: null and followed by a non-slash char (or EOL),
replace with the followed non-slash char.
Thus, null/ won't be touched.
I think this command should be enough:
sed -e "s/null[^/]//g"

sed replacing special string quota

sed is still giving me headaches, so a little help is extremely appreciated.
In a file I have a string like:
SOME_TEXT="variables"
What I want to accomplish is to add a piece of text (variable) to either the end or the begging of the string for that text.
I tried to use variations of:
sed -i '/^SOME_TEXT="/ s/$/ SOME_TEXT="new text'/' filename
but that is failing, so clearly the quota for the string I want to add to is messing up the syntax.
LE:
A variation further is that I have a variable that I want to use as the replace in that syntax, so I have this:
sed -i "s/^SOME_TEXT="/SOME_TEXT=" $variable/" file
This actually produces this output, as it picks up incorrectly the opening/closing quotas:
SOME_TEXT = text_variable" initial text continuation
So how can I properly close the trailing quota so that I can use the variable after it?
I used
sed 's/^SOME_TEXT="/SOME_TEXT="new text/' filename
and it showed:
SOME_TEXT="new textvariables"
Is that what you want?
Escape the '"' characters with a '\' so that they don't terminate your regex string.
sed -i "s/^TEXT=\"/TEXT=\" $variable/"

Using sed to convert singular/plural words into uppercase

Using one sed command I'm trying to convert all occurrences of test and tests found in a .txt file into all caps. I also want to print only the converted lines, so I'm using -n. I've been playing around for it for over an hour. The problem is that I'm able to convert one or the other (either test or tests) but not both.
Any help would be so greatly appreciated. Thank you!
Use this
sed -e 's/tests/TESTS/g; s/test/TEST/g; T; p;' input.txt
The semicolons let you execute multiple commands.
This might work for you (GNU sed):
sed 's/\<tests\?\>/\U&/gp;d' file
This will uppercase words (\<....\>) that begin test with an optional s (s\?).
Sorry for the late response, but here is hopefully an understandable one with basic regex (no extended regex):
sed 's:\<test\(s*\)\>:TEST\1:g' < inputFile.txt > outputFile.txt; cat outputFile.txt | grep -n TEST
Explanation:
: delimiter (instead of usual /)
\<test\> matches test. The character before the first t can be any character except a letter, number or underscore. Same applies for the character after the last t.
\(\) remember what is inside the parenthesis.
s* match zero or more s's.
\1 used to insert first remembered match (i.e. any number of s's matched).
The rest is hopefully clear. Otherwise leave a comment.

Replace 3 lines with another line SED Syntax

This is a simple question, I'm not sure if i'm able to do this with sed/awk
How can I make sed search for these 3 lines and replace with a line with a determined string?
<Blarg>
<Bllarg>
<Blllarg>
replace with
<test>
I tried with sed "s/<Blarg>\n<Bllarg>\n<Blllarg>/<test>/g" But it just don't seem to find these lines. Probably something with my break line character (?) \n. Am I missing something?
Because sed usually handles only one line at a time, your pattern will never match. Try this:
sed '1N;$!N;s/<Blarg>\n<Bllarg>\n<Blllarg>/<test>/;P;D' filename
This might work for you:
sed '/<Blarg>/ {N;N;s/<Blarg>\n<Bllarg>\n<Blllarg>/<test>/}' <filename>
It works as follows:
Search the file till <Blarg> is found
Then append the two following lines to the current pattern space using N;N;
Check if the current pattern space matches <Blarg>\n<Bllarg>\n<Blllarg>
If so, then substitute it with <test>
You can use range addresses with regular expressions an the c command, which does exactly what you are asking for:
sed '/<Blarg>/,/<Blllarg>/c<test>' filename