Laravel-mongo DB - mongodb

Question

I'm using https://github.com/jenssegers/laravel-mongodb
$query = $this->proposal->where('status', 'approved')
->with(['evaluations', 'user', 'contributions'])
->with(['reviews' => function ($q) {
$q->where('status','approved')->orderBy('created_at', 'desc');
}]);
if( .... ) {
dd($query->toSql()); // "select * from "proposals" where "status" = ?"
$proposalsFoundByTile = $query->where('title','like',"%$request->search%")->get();
dd($query->toSql()); // "select from "proposals" where "status" = ? and "title" like ?"
...
}
Why $query value changed? How can I "clear" this changes to initial value?

Answer 1

After this line,
$proposalsFoundByTile = $query->where('title','like',"%$request->search%")->get();
put this,
$key = array_search("title", array_column($query->getQuery()->wheres,
'column'));
unset($query->getQuery()->wheres[$key]);
Then this will return,
dd($query->toSql()); // "select from "proposals" where "status" = ?"

Answer 2

As adviced in comments solved this problem with clone() function.
$query = $this->proposal->where('status', 'approved')
->with(['evaluations', 'user', 'contributions'])
->with(['reviews' => function ($q) {
$q->where('status','approved')->orderBy('created_at', 'desc');
}]);
if( .... ) {
$subQuery = clone($query);
$proposalsFoundByTile = $subQuery->where('title','like',"%$request->search%")->get();
...
$subQuery = clone($query);
$some_var = $subQuery->... ;
}