what is wrong with this
select
ID
,SYSCODE
,LID
,ROW_NUMBER() OVER(PARTITION BY ID ORDER BY SYSCODE, LID) AS row_num
from prod_sys.P_ENTERPRISE
it works in management studio but not in mysql workbench
ROW_NUMBER() is not there in MYSQL, rewrite the query like below.
select
ID
,SYSCODE
,LID
,#row_num := #row_num + 1 as Row_number
from prod_sys.P_ENTERPRISE join (SELECT #row_num := 0) a;
Related
I have two table with same name in two different schemas (old and new dump). I would like to know the difference between the two integration.
I have two queries, that gives old and new count:
select count(*) as count_old from(
SELECT
distinct id
FROM
schema1.compound)q1
select count(*) as count_new from(
SELECT
distinct id
FROM
schema2.compound)q2
I would like have the following output.
table_name count_new count_new diff
compound 4740 4735 5
Any help is appreciated. Thanks in advance
with counts as (
select
(select count(distinct id) from schema1.compound) as count_old,
(select count(distinct id) from schema2.compound) as count_new
)
select
'compound' as table_name,
count_old,
count_new,
count_old - count_new as diff
from counts;
I think you could do something like this:
SELECT 'compound' AS table_name, count_old, count_new, (count_old - count_new) AS diff FROM (
SELECT(
(SELECT count(*) FROM (SELECT DISTINCT id FROM schema1.compound)) AS count_old,
(SELECT count(*) FROM (SELECT DISTINCT id FROM schema2.compound)) AS count_new
)
It was probably answered already, but it is a subquery/nested query.
You can directly compute the COUNT on distinct values if you use the DISTINCT keyword inside your aggregation function. Then you can join the queries extracting your two needed values, and use them inside your query to get the output table.
WITH cte AS (
SELECT new.cnt AS count_new,
old.cnt AS count_old
FROM (SELECT COUNT(DISTINCT id) AS cnt FROM schema1.compound) AS old
INNER JOIN (SELECT COUNT(DISTINCT id) AS cnt FROM schema2.compound) AS new
ON 1 = 1
)
SELECT 'compound' AS table_name,
count_new,
count_old,
count_new = count_old AS diff
FROM cte
I have a test table
ID V_ID
1 1
1 2
I want max(V_ID) and resulr should be V_ID 2
select Id,max(V_ID) from test
group by Id,value
I am trying simple query but it's still pulling two records. Is there any other simple query 1) we can try rank 2)?
You should be grouping only by the ID column:
SELECT ID, MAX(V_ID)
FROM test
GROUP BY IdD;
A more general pattern for this type of problem uses ROW_NUMBER to find the entire record for each Id having the max value of V_ID:
SELECT ID, V_ID
FROM
(
SELECT *, ROW_NUMBER() OVER (PARTITION BY ID ORDER BY V_ID DESC) rn
FROM test
) t
WHERE rn = 1;
I have 9000 row in News table and use this code for selecting 20 from it:
Select *
From (
Select *, ROW_NUMBER() OVER (ORDER BY DateSend DESC) AS Num
From News
Where SubjectID in(Select MenuSubject.SubjectID
From MenuSubject inner join Menu on MenuSubject.MenuID = Menu.MenuID)
) as myTable
where myTable.Num BETWEEN 100 and 120
But time is 28 second spent reading! Also, I test this query with out join table and get result at 1 second.
So, I want use Table type for select join table and use this in query. I made new Table type using the following code:
DECLARE #MyTable2 IntListTable
Insert Into #MyTable2
Select MenuSubject.SubjectID
From MenuSubject inner join Menu on MenuSubject.MenuID = Menu.MenuID
Select *
From (
Select *, ROW_NUMBER() OVER (ORDER BY DateSend DESC) AS Num
From News
Where SubjectID in #MyTable2
) as myTable
where myTable.Num BETWEEN 100 and 120
But get Error in
SubjectID in #MyTable2
Error:
Incorrect syntax near '#MyTable2'.
Edit:
I test my code with:
Select myTable.Title
or use this code instead join table:
Where SubjectID in(13,14,20,21,25,24,26,24,28,29,30,54,55,60,47,98,99,65,14,20,33,666,987,254)
get result at 1 second.
but use this code in query:
Select myTable.MoreText
time is 28 second spent reading!. why!?
Try this,
Select x.Num
From (
Select *, ROW_NUMBER() OVER (ORDER BY DateSend DESC) AS Num
From News
Where SubjectID in(Select MenuSubject.SubjectID
From MenuSubject inner join Menu on MenuSubject.MenuID = Menu.MenuID)
) x
where x.Num <21
WITH myTempTable as (Select MenuSubject.SubjectID
From MenuSubject inner join Menu on MenuSubject.MenuID = Menu.MenuID)
Select *
From (
Select *, ROW_NUMBER() OVER (ORDER BY DateSend DESC) AS Num
From News
Where SubjectID in (SELECT SubjectID FROM myTempTable)
) as myTable
where myTable.Num BETWEEN 100 and 120
You can try above query.
There is absolutely no need for a User-Defined Table Type in this query. It adds work but no actual benefit.
The problem is most likely the fact that you are using an IN list as those translate out to be an OR condition for each of the values. But an IN list isn't needed either.
This query can actually be simplified by rethinking it in terms of an INNER JOIN, which should be better as it will allow the Query Optimizer to do its job.
SELECT *
FROM (
SELECT nw.*, ROW_NUMBER() OVER (ORDER BY DateSend DESC) AS [Num]
FROM News nw
INNER JOIN (
MenuSubject
INNER JOIN Menu
ON MenuSubject.MenuID = Menu.MenuID
) ON MenuSubject.SubjectID = nw.SubjectID
) AS myTable
WHERE myTable.Num BETWEEN 100 AND 120;
One final simplification that can be made, though I doubt it is needed here since 9000 rows is almost no data at all, is to first dump the results to a local temporary table and then use that in the INNER JOIN:
CREATE TABLE #Subjects
(
SubjectID INT NOT NULL -- PRIMARY KEY -- test with and without PK to see if it helps
);
INSERT INTO #Subjects (SubjectID)
SELECT MenuSubject.SubjectID
FROM MenuSubject
INNER JOIN Menu
ON Menu.MenuID = MenuSubject.MenuID;
SELECT *
FROM (
SELECT nw.*, ROW_NUMBER() OVER (ORDER BY DateSend DESC) AS [Num]
FROM News nw
INNER JOIN #Subjects sub
ON sub.SubjectID = nw.SubjectID
) AS myTable
WHERE myTable.Num BETWEEN 100 AND 120;
I have a field called "Users", and I want to run SUM() on that field that returns the sum of all DISTINCT records. I thought that this would work:
SELECT SUM(DISTINCT table_name.users)
FROM table_name
But it's not selecting DISTINCT records, it's just running as if I had run SUM(table_name.users).
What would I have to do to add only the distinct records from this field?
Use count()
SELECT count(DISTINCT table_name.users)
FROM table_name
SQLFiddle demo
This code seems to indicate sum(distinct ) and sum() return different values.
with t as (
select 1 as a
union all
select '1'
union all
select '2'
union all
select '4'
)
select sum(distinct a) as DistinctSum, sum(a) as allSum, count(distinct a) as distinctCount, count(a) as allCount from t
Do you actually have non-distinct values?
select count(1), users
from table_name
group by users
having count(1) > 1
If not, the sums will be identical.
You can see for yourself that distinct works with the following example. Here I create a subquery with duplicate values, then I do a sum distinct on those values.
select DistinctSum=sum(distinct x), RegularSum=Sum(x)
from
(
select x=1
union All
select 1
union All
select 2
union All
select 2
) x
You can see that the distinct sum column returns 3 and the regular sum returns 6 in this example.
You can use a sub-query:
select sum(users)
from (select distinct users from table_name);
SUM(DISTINCTROW table_name.something)
It worked for me (innodb).
Description - "DISTINCTROW omits data based on entire duplicate records, not just duplicate fields." http://office.microsoft.com/en-001/access-help/all-distinct-distinctrow-top-predicates-HA001231351.aspx
;WITH cte
as
(
SELECT table_name.users , rn = ROW_NUMBER() OVER (PARTITION BY users ORDER BY users)
FROM table_name
)
SELECT SUM(users)
FROM cte
WHERE rn = 1
SQL Fiddle
Try here yourself
TEST
DECLARE #table_name Table (Users INT );
INSERT INTO #table_name Values (1),(1),(1),(3),(3),(5),(5);
;WITH cte
as
(
SELECT users , rn = ROW_NUMBER() OVER (PARTITION BY users ORDER BY users)
FROM #table_name
)
SELECT SUM(users) DisSum
FROM cte
WHERE rn = 1
Result
DisSum
9
If circumstances make it difficult to weave a "distinct" into the sum clause, it will usually be possible to add an extra "where" clause to the entire query - something like:
select sum(t.ColToSum)
from SomeTable t
where (select count(*) from SomeTable t1 where t1.ColToSum = t.ColToSum and t1.ID < t.ID) = 0
May be a duplicate to
Trying to sum distinct values SQL
As per Declan_K's answer:
Get the distinct list first...
SELECT SUM(SQ.COST)
FROM
(SELECT DISTINCT [Tracking #] as TRACK,[Ship Cost] as COST FROM YourTable) SQ
I need to select one row from each group based on COUNT(1) field.
In other databases I'd use ROW_NUMBER() function, which in redshift is unsupported yet.
The answer is to use a SUM(1) OVER(PARTITION BY group_field ORDER BY order field ROWS UNBOUNDED PRECEDING) construct like that:
SELECT id,
name,
cnt
FROM
(SELECT id,
name,
count(*) cnt,
sum(1) over (partition BY id ORDER BY cnt DESC ROWS UNBOUNDED PRECEDING) AS row_number
FROM table
GROUP BY id,
name)
WHERE row_number = 1
ORDER BY name