Redirect in Scala play framework - scala

Question

I have a problem with Redirect in Scala play framework.
How can I redirect to view BooksController.index() ? In documentation they suggest to use Redirect but I don't know how.
def edit(Id: Int) = Action {
val book: Book = Book.findById(Id)
Ok(views.html.edit())
}
def update = Action {
implicit request =>
val (id, title, price, author) = bookForm.bindFromRequest.get
val book: Book = Book.findById(id)
book.id = id
book.title = title
book.price = price
book.author = author
Redirect(routes.BooksController.index())
}
Now can recognize --> import play.api.mvc.Results._
But i have an error --> "object java.lang.ProcessBuilder.Redirect is not a value"

Answer 1

If you would really like to continue using reverse routing in your code instead of having string uri values all over the place, see this:
Redirect with Bad Request Status.
The Redirect function accepts only a String or Call.
Try the following steps:
0) Add in the BookController
import play.api.mvc._
1) Add the following string in your route config file(hard disk location: controllers/BooksController)
GET /redirectedPage controllers.BooksController.index
2) Define a variable in the BookController
val Home = Redirect(routes.BookController.index())
3) Describe in the BookController
def update = Action {
implicit request => Home
}
Also do "sbt clean; sbt compile" to recompile auto-calls in ReverseRoutes.scala.
Well done.

Answer 2

The last line in the update action is the Redirect call which redirects to BooksController index route
import play.api.mvc.Results._
Redirect(routes.BooksController.index())