How to use Status in own code in Play - scala

Question

Playversion is 2.6.12.
I want to use Results.Status in my own code like
// in my code somewhere
def doSomething(status:Results.Status) { ....}
// in controller
doSomething(Ok) <---- results in error
But I the Ok inside a controller seems not to be of type Results.Status
[error] found : MyController.this.Status
[error] required: play.api.mvc.Results.Status
Any ideas how to use Status in my own code outside controllers?
The helper code is
import org.scalactic.{Bad, Good, Or}
import play.api.libs.json.Json
import play.api.mvc.Result
import play.api.mvc.Results.Status
object Helper {
def toResult[T](r:Or[T, Result], s:Status):Result = {
r match {
case Good(entity) => s(Json.toJson(entity))
case Bad(badRequest) => badRequest
}
}
}
The controller code definition is extending
class AuthBaseController #Inject()(acc: AuthControllerComponents) extends BaseController with AuthRequestMarkerContext {
where BaseController leads to
trait ControllerHelpers extends Results with HttpProtocol with Status with HeaderNames with ContentTypes with RequestExtractors with Rendering with RequestImplicits
extending Status.

Answer 1

You can always explicitly pass the requested type:
doSomething(play.api.mvc.Results.Ok)
I suppose if you just import play.api.mvc.Results._ in your controller, you will have an import conflict (you can still try it), but just importing play.api.mvc.Results, and then using it like this
doSomething(Results.Ok)
should work.

Answer 2

[error] found : MyController.this.Status
[error] required: play.api.mvc.Results.Status
Status is a specific type that depends on the controller. To have a function that's a certain type, that doesn't care about the parent type you can use the # symbol like this:
def doSomething(status:Results#Status) { ....}