find list of users based on multiple condition using aggregation - mongodb

Question

I want to know how to use aggregation to perform this.
find userId list who perform add to cart and item view event more then 2 times
Collection name event.
{
_id:1,
name:"Add To Cart",
userId:1
}
{
_id:2,
name:"Searched",
userId:2
}
{
_id:3,
name:"Add To Cart",
userId:1
}
{
_id:4,
name:"Item View",
userId:1
}
{
_id:5,
name:"Add To Cart",
userId:2
}
{
_id:6,
name:"Item View",
userId:1
}
my query-
db.getCollection("event").aggregate([ {$match:{$or:[{"name":"Add to
Cart"},{"name":"Item Viewed"}]}},
{$group:{_id: {userId:"$userId",name:"$name"},count:{$sum:1}}},
{$match:{count:{$gte:2}}},
{$group: {_id:"$_id.userId",event:{$push:"$_id.name"}}} ,
{$project:{size:{$size:"$event"}}},
{$match:{size:{$gte:2}}}
]).pretty();
output expected -from above collection
{userId:1}
I want only those userId who perform Add to cart and Item view event(both) more then 2 times.

Answer 1

Here is Full Query ,
db.Test.aggregate(
// Pipeline
[
{
$group: {
"_id": {
"userId": "$userId",
"name": "$name"
},
"count": {
"$sum": 1
}
}
},
{
$match: {
"count": {
"$gte": 2
}
}
},
{
$group: {
"_id": "$_id.userId",
"event": {
"$push": "$_id.name"
}
}
},
{
$project: {
"size": {
"$size": "$event"
}
}
},
{
$match: {
"size": {
"$gte": 2
}
}
},
]
);
You will get your userId in _id field.