I'm trying to parse JSON returned from a web service. The response JSON looks like this {"API_Count":"17"}
Here's my code.. Just trying to get the value (17). The key value.
Here's my code.. something 'basic' must be wrong. I get the error
**[NSTaggedPointerString objectForKey:]: unrecognized selector sent to instance**
***Any ideas??***
NSData *jsonData = [responseObject dataUsingEncoding:NSUTF8StringEncoding];
NSError *err = nil;
NSDictionary *json = [NSJSONSerialization JSONObjectWithData:jsonData options:NSJSONReadingAllowFragments error:&err];
for (NSDictionary *item in json )
{
NSObject *val = [item objectForKey:#"API_Count"];
// ERROR !!! [NSTaggedPointerString objectForKey:]: unrecognized selector sent to instance 0xa32b4de1b0d02c49
}
NSDictionary *json = [NSJSONSerialization JSONObjectWithData:jsonData options:NSJSONReadingAllowFragments error:&err];
NSInteger val = [[json objectForKey:#"API_Count"] intergerValue];
Related
How do I extract just the "token" value from the following code? I'm looking to save this value into a string.
Is meta an array? If so how would I extract the data from the "token" value?
thanks for any help
NSString *responseData = [[NSString alloc]initWithData:urlData encoding:NSUTF8StringEncoding];
Response ==> {"meta":[],"data":{"token":"IVZ2ciRkbVtDLUl3YmhwOTkyXzpRR1M3LUUsRiElfWF6T3I6dCxsRWg6di1XcyR6OTUzZHhVazdLTEJ7blU5O258d2xRTXg0VUxwQXBlNHRSOXd2VXZ1aG1RfFhQQjJsSkkoc2IuOTFyYkYodyhAe2RldXR1aDF3RClXWyhoMiU="}}
2013-07-19 15:10:23.139 appName [11190:907] {
data = {
token = "IVZ2ciRkbVtDLUl3YmhwOTkyXzpRR1M3LUUsRiElfWF6T3I6dCxsRWg6di1XcyR6OTUzZHhVazdLTEJ7blU5O258d2xRTXg0VUxwQXBlNHRSOXd2VXZ1aG1RfFhQQjJsSkkoc2IuOTFyYkYodyhAe2RldXR1aDF3RClXWyhoMiU=";
};
meta = (
);
}
I believe the data is in JSON format. In that case, this should work.
NSError *error = nil;
NSDictionary *responseDict = [NSJSONSerialization JSONObjectWithData:urlData options:0 error:&error];
NSString *token = [[responseDict objectForKey:#"data"] objectForKey:#"token"];
I'd just do this:
NSData *responseData = [NSData dataWithContentsOfURL:yourURL];
NSString *token = [NSJSONSerialization JSONObjectWithData:responseData
options:kNilOptions error:NULL][#"data"][#"token"];
It will be nil if there's any error.
In your Case, meta is an Array and data is a Dictionary. If your Response is properly formatted in JSON then you can use the below sample code to get the TokenString and metaArray.
Sample Code :
NSData *data = [NSData dataWithContentsOfURL:yourURL];
NSError* error = nil;
NSDictionary* responseDict = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
NSString *token = [[responseDict objectForKey:#"data"] objectForKey:#"token"];
NSArray *meta = [responseDict objectForKey:#"meta"];
NSLog(#"\ntoken :: %#\nmeta :: %#",token,meta);
PS : To know more about JSON response , take a look at this Answer.
Ok, this is my first approach to JSONs in Objective-C (and i'm quite new to the last one too). i'm to get infos stored my json to use them in Objective-C, but when trying to load it i get null in response from NSLog(#"%#",allData); on. Can anybody please tell me what i am doing wrong? thanks in advance for your time and your patience.
oh and if needed here's the json:
http://jsonviewer.stack.hu/#http://conqui.it/ricette.json
NSString *filePath = [[NSBundle mainBundle] pathForResource:#"recipes" ofType:#"json"];
NSError *error = nil;
NSMutableData *JSONData = [NSData dataWithContentsOfFile:filePath options:NSDataReadingMappedIfSafe error:&error];
NSLog(#"%#",JSONData);
NSArray *allData = [NSJSONSerialization JSONObjectWithData:JSONData options:0 error:nil];
NSLog(#"%#",allData);
for (NSDictionary *diction in allData) {
NSString *recipe = [diction objectForKey:#"recipe"];
[array addObject:recipe];
}
NSLog(#"%#",array);
The JSONObjectWithData method has an error parameter, of which you can avail yourself in order to diagnose the problem. For example:
NSError *error = nil;
NSArray *allData = [NSJSONSerialization JSONObjectWithData:JSONData
options:0
error:&error];
if (error)
NSLog(#"%s: JSONObjectWithData error: %#", __FUNCTION__, error);
In your comments, you suggest that you received an error about "Unescaped control character around character 414." That would suggest an error in the JSON, itself, which you might want to validate by copying into http://jsonlint.com/ and see if it reports any issues.
In response to the broader question about whether there are any Objective-C issues, there are no coding errors, per se. I can't comment on the for loop which clearly assumes that allData is an array of dictionaries to which I cannot attest without seeing the JSON. But I'll take your word for it. But, yes, the Objective-C code looks fine (albeit, a little light on checking of the return values types and error objects).
For example, if you wanted some diagnostic assert statements that you could use during development, you might do something like:
NSArray *allData = [NSJSONSerialization JSONObjectWithData:JSONData options:0 error:nil];
NSAssert(error, #"%s: JSONObjectWithData error: %#", __FUNCTION__, error);
NSLog(#"%s: array=%#", __FUNCTION__, array);
NSAssert([allData isKindOfClass:[NSArray class]], #"allData is not an array");
for (NSDictionary *diction in allData) {
NSAssert([diction isKindOfClass:[NSDictionary class]], #"%s: diction is not a dictionary (%#), __FUNCTION__, diction);
NSString *recipe = [diction objectForKey:#"recipe"];
NSAssert(recipe, #"%s: Did not find recipe key in diction (%#)", __FUNCTION__, diction);
[array addObject:recipe];
}
If any of these errors were possible runtime errors in production, you'd replace assert statements with if statements that do the necessary error handling. But hopefully it illustrates the concept.
Problem in your response is that , string values are unable to concatenate.So, I have to manually remove those tabs and new lines.
At five places you are getting error i.e:
pelate.
pasta.
pomodoro.
saporiti).
\t
- (void)viewDidLoad
{
NSString *urlStr=[NSString stringWithFormat:#"http://www.conqui.it/ricette.json"];
urlStr=[urlStr stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *fileNameURL=[NSURL URLWithString:urlStr];
NSLog(#"url is %#",urlStr);
NSMutableURLRequest *filenameReq=[[NSMutableURLRequest alloc] initWithURL:fileNameURL];
NSData *responseData=[NSURLConnection sendSynchronousRequest:filenameReq returningResponse:nil error:nil];
NSString *responseString=[[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
responseString=[[responseString componentsSeparatedByString:#"\n"] componentsJoinedByString:#""];
responseString=[responseString stringByReplacingOccurrencesOfString:#"\t" withString:#""];
responseData=[responseString dataUsingEncoding:NSUTF8StringEncoding];
NSLog(#"response String is %#",responseString);
[NSCharacterSet characterSetWithCharactersInString:responseString];
NSError *e = nil;
NSArray *jsonArray = [NSJSONSerialization JSONObjectWithData:responseData options: 0 error: &e];
NSLog(#"JSON Array is %# & error is %#",jsonArray,e);
[super viewDidLoad];
// Do any additional setup after loading the view, typically from a nib.
}
I am using ASIHTTPRequest to get JSON response from server. And I want to convert this response to NSArray. My code:
NSURL *url = [NSURL URLWithString:#"http://chirkov.net.ua/iosnettest/request.php?act=showdata&query=2;0;3;0;ASC"];
ASIHTTPRequest *request = [ASIHTTPRequest requestWithURL:url];
[request startSynchronous];
NSError *error = [request error];
if (!error) {
NSData *responseData = [[NSMutableData alloc] initWithData:[request responseData]];
NSArray *array = [NSKeyedUnarchiver unarchiveObjectWithData:responseData];
NSLog(#"array = %#",array);
}
But got exception Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '*** -[NSKeyedUnarchiver initForReadingWithData:]: incomprehensible archive (0xffffffef, 0xffffffbb, 0xffffffbf, 0x5b, 0x7b, 0x22, 0x69, 0x64.
How can I solve my problem?
You getting JSON data so you have to convert that data using NSJSONSerialization. Have a look at class reference.
http://developer.apple.com/library/ios/#documentation/Foundation/Reference/NSJSONSerialization_Class/Reference/Reference.html
Also check this Working with JSON
You can use NSJSONSerialization like this:
NSError *jsonError = nil;
NSArray *jsonObject = (NSArray *)[NSJSONSerialization JSONObjectWithData:jsonData options:kNilOptions error:&jsonError];
I am trying to parse Json response from This URL. I have used SBJsonParser, MTJSON and another parser but i am getting NULL in all three case.
apiUrlStr = #"http://maps.google.com/maps?output=dragdir&saddr=Delhi&daddr=Mumbai+to:hyderabad";
NSURL* apiUrl = [NSURL URLWithString:apiUrlStr];
NSString *apiResponse = [NSString stringWithContentsOfURL:apiUrl encoding:NSUTF8StringEncoding error:nil];
SBJsonParser *json = [[[SBJsonParser alloc] init] autorelease];
NSDictionary *dictionary = [json objectWithString:apiResponse];
NSLog(#"dictionary=%#", [json objectWithString:apiResponse]);
2011-12-09 16:59:01.226 MapWithRoutes[2523:207] dictionary=(null)
Plz suggest me something
Oke if checked the url you gave with JSONlint.com and the JSON is not valid. thus can not be parsed by any library.
If you used JSONkit you can supply a NSError object with the parse call to see what went wrong:
NSError *error = nil;
NSDictionary *dictionary = [apiResponse objectFromJSONStringWithParseOptions:JKParseOptionNone error:&error];
if (!dictionary) {
NSLog(#"Error: %#", error);
}
Never touched json before. I'm trying to access some variables within the Wunderground weather API for Melbourne. For example, let's say I want to access the "wind_dir":"East" variable. This is my code thus far:
NSString *urlString =
[NSString stringWithFormat:
#"http://api.wunderground.com/api/key/geolookup/conditions/forecast/q/-33.957550,151.230850.json"];
NSLog(#"URL = %#", urlString);
SBJsonParser *parser = [[SBJsonParser alloc] init];
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:urlString]];
NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
NSString *json_string = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding];
NSArray *weatherInfo = [parser objectWithString:json_string error:nil];
for (NSDictionary *weatherString in weatherInfo)
{
NSLog(#"some weather info = %#", [[[weatherString objectForKey:#"response"] objectForKey:#"current_observation"] objectForKey:#"wind_dir"]);
}
My code reaches the for loop and crashes with this error: -[NSCFString objectForKey:]: unrecognized selector sent to instance.
I'm not 100% sure what's causing the crash, and whether my path to the "wind_dir" variable is correct, though they could well be the same problem.
Thanks in advance for any help.
either the "response" property or the "current_observation" propery is string and not dictionary.
the error you are getting is that you are trying to call "objectForKey" on a string.
after looking at the result of the API, it seems that you are not getting an array.
You should do something like this:
NSDictionary *weatherInfo = [parser objectWithString:json_string error:nil];
NSLog(#"some weather info = %#", [[weatherInfo objectForKey:#"current_observation"] objectForKey:#"wind_dir"]);
instead of your for statement.