how to implement takeUntil with Scala lazy collections - scala

Question

I have an expensive function which I want to run as few times as possible with the following requirement:
I have several input values to try
If the function returns a value below a given threshold, I don't want to try other inputs
if no result is below the threshold, I want to take the result with the minimal output
I could not find a nice solution using Iterator's takeWhile/dropWhile, because I want to have the first matching element included. just ended up with the following solution:
val pseudoResult = Map("a" -> 0.6,"b" -> 0.2, "c" -> 1.0)
def expensiveFunc(s:String) : Double = {
pseudoResult(s)
}
val inputsToTry = Seq("a","b","c")
val inputIt = inputsToTry.iterator
val results = mutable.ArrayBuffer.empty[(String, Double)]
val earlyAbort = 0.5 // threshold
breakable {
while (inputIt.hasNext) {
val name = inputIt.next()
val res = expensiveFunc(name)
results += Tuple2(name,res)
if (res<earlyAbort) break()
}
}
println(results) // ArrayBuffer((a,0.6), (b,0.2))
val (name, bestResult) = results.minBy(_._2) // (b, 0.2)
If i set val earlyAbort = 0.1, the result should still be (b, 0.2) without evaluating all the cases again.

Answer 1

You can make use of Stream to achieve what you are looking for, remember Stream is some kind of lazy collection, that evaluate operations on demand.
Here is the scala Stream documentation.
You only need to do this:
val pseudoResult = Map("a" -> 0.6,"b" -> 0.2, "c" -> 1.0)
val earlyAbort = 0.5
def expensiveFunc(s: String): Double = {
println(s"Evaluating for $s")
pseudoResult(s)
}
val inputsToTry = Seq("a","b","c")
val results = inputsToTry.toStream.map(input => input -> expensiveFunc(input))
val finalResult = results.find { case (k, res) => res < earlyAbort }.getOrElse(results.minBy(_._2))
If find does not get any value, you can use the same stream to find the min, and the function is not evaluated again, this is because of memoization:
The Stream class also employs memoization such that previously computed values are converted from Stream elements to concrete values of type A
Consider that this code will fail if the original collection was empty, if you want to support empty collections you should replace minBy with sortBy(_._2).headOption and getOrElse by orElse:
val finalResultOpt = results.find { case (k, res) => res < earlyAbort }.orElse(results.sortBy(_._2).headOption)
And the output for this is:
Evaluating for a
Evaluating for b
finalResult: (String, Double) = (b,0.2)
finalResultOpt: Option[(String, Double)] = Some((b,0.2))

Answer 2

The clearest, simplest, thing to do is fold over the input, passing forward only the current best result.
val inputIt :Iterator[String] = inputsToTry.iterator
val earlyAbort = 0.5 // threshold
inputIt.foldLeft(("",Double.MaxValue)){ case (low,name) =>
if (low._2 < earlyAbort) low
else Seq(low, (name, expensiveFunc(name))).minBy(_._2)
}
//res0: (String, Double) = (b,0.2)
It calls on expensiveFunc() only as many times as is needed, but it does walk through the entire input iterator. If that's still too onerous (lots of input) then I'd go with a tail-recursive method.
val inputIt :Iterator[String] = inputsToTry.iterator
val earlyAbort = 0.5 // threshold
def bestMin(low :(String,Double) = ("",Double.MaxValue)) :(String,Double) = {
if (inputIt.hasNext) {
val name = inputIt.next()
val res = expensiveFunc(name)
if (res < earlyAbort) (name, res)
else if (res < low._2) bestMin((name,res))
else bestMin(low)
} else low
}
bestMin() //res0: (String, Double) = (b,0.2)

Answer 3

Use view in your input list:
try the following:
val pseudoResult = Map("a" -> 0.6, "b" -> 0.2, "c" -> 1.0)
def expensiveFunc(s: String): Double = {
println(s"executed for ${s}")
pseudoResult(s)
}
val inputsToTry = Seq("a", "b", "c")
val earlyAbort = 0.5 // threshold
def doIt(): List[(String, Double)] = {
inputsToTry.foldLeft(List[(String, Double)]()) {
case (n, name) =>
val res = expensiveFunc(name)
if(res < earlyAbort) {
return n++List((name, res))
}
n++List((name, res))
}
}
val (name, bestResult) = doIt().minBy(_._2)
println(name)
println(bestResult)
The output:
executed for a
executed for b
b
0.2
As you can see, only a and b are evaluated, and not c.

Answer 4

This is one of the use-cases for tail-recursion:
import scala.annotation.tailrec
val pseudoResult = Map("a" -> 0.6,"b" -> 0.2, "c" -> 1.0)
def expensiveFunc(s:String) : Double = {
pseudoResult(s)
}
val inputsToTry = Seq("a","b","c")
val earlyAbort = 0.5 // threshold
#tailrec
def f(s: Seq[String], result: Map[String, Double] = Map()): Map[String, Double] = s match {
case Nil => result
case h::t =>
val expensiveCalculation = expensiveFunc(h)
val intermediateResult = result + (h -> expensiveCalculation)
if(expensiveCalculation < earlyAbort) {
intermediateResult
} else {
f(t, intermediateResult)
}
}
val result = f(inputsToTry)
println(result) // Map(a -> 0.6, b -> 0.2)
val (name, bestResult) = f(inputsToTry).minBy(_._2) // ("b", 0.2)

Answer 5

If you implement takeUntil and use it, you'd still have to go through the list once more to get the lowest one if you don't find what you are looking for. Probably a better approach would be to have a function that combines find with reduceOption, returning early if something is found or else returning the result of reducing the collection to a single item (in your case, finding the smallest one).
The result is comparable with what you could achieve using a Stream, as highlighted in a previous reply, but avoids leveraging memoization, which can be cumbersome for very large collections.
A possible implementation could be the following:
import scala.annotation.tailrec
def findOrElse[A](it: Iterator[A])(predicate: A => Boolean,
orElse: (A, A) => A): Option[A] = {
#tailrec
def loop(elseValue: Option[A]): Option[A] = {
if (!it.hasNext) elseValue
else {
val next = it.next()
if (predicate(next)) Some(next)
else loop(Option(elseValue.fold(next)(orElse(_, next))))
}
}
loop(None)
}
Let's add our inputs to test this:
def f1(in: String): Double = {
println("calling f1")
Map("a" -> 0.6, "b" -> 0.2, "c" -> 1.0, "d" -> 0.8)(in)
}
def f2(in: String): Double = {
println("calling f2")
Map("a" -> 0.7, "b" -> 0.6, "c" -> 1.0, "d" -> 0.8)(in)
}
val inputs = Seq("a", "b", "c", "d")
As well as our helpers:
def apply[IN, OUT](in: IN, f: IN => OUT): (IN, OUT) =
in -> f(in)
def threshold[A](a: (A, Double)): Boolean =
a._2 < 0.5
def compare[A](a: (A, Double), b: (A, Double)): (A, Double) =
if (a._2 < b._2) a else b
We can now run this and see how it goes:
val r1 = findOrElse(inputs.iterator.map(apply(_, f1)))(threshold, compare)
val r2 = findOrElse(inputs.iterator.map(apply(_, f2)))(threshold, compare)
val r3 = findOrElse(Map.empty[String, Double].iterator)(threshold, compare)
r1 is Some(b, 0.2), r2 is Some(b, 0.6) and r3 is (reasonably) None. In the first case, since we use a lazy iterator and terminate early, we only invoke f1 twice.
You can have a look at the results and can play with this code here on Scastie.