Regex pattern equality - scala

Question

In ScalaTest, I have the following check:
"abc".r shouldBe "abc".r
But it is not equal. I don't understand.
abc was not equal to abc
ScalaTestFailureLocation: com.ing.cybrct.flink.clickstream.ConfigsTest$$anonfun$6 at (ConfigsTest.scala:97)
Expected :abc
Actual :abc

Answer 1

While it's possible to decide whether two regular expressions accept the same language, it seems to be rather complicated and not all that terribly useful for everyday regex usage. Therefore, equality on compiled regex patterns is just referential equality:
val x = "abc".r
val y = "abc".r
x == y
// res0: Boolean = false

Answer 2

The method shouldBe in Scalatest 3.0.5 delegates the equality check to the areEqualComparingArraysStructurally method:
def shouldBe(right: Any): Assertion = {
if (!areEqualComparingArraysStructurally(leftSideValue, right)) {
val (leftee, rightee) = Suite.getObjectsForFailureMessage(leftSideValue, right)
val localPrettifier = prettifier // Grabbing a local copy so we don't attempt to serialize AnyShouldWrapper (since first param to indicateFailure is a by-name)
indicateFailure(FailureMessages.wasNotEqualTo(localPrettifier, leftee, rightee), None, pos)
}
else indicateSuccess(FailureMessages.wasEqualTo(prettifier, leftSideValue, right))
}
which in turn simply delegates the equality check (as you can expect) to the == operator:
private[scalatest] def areEqualComparingArraysStructurally(left: Any, right: Any): Boolean = {
// Prior to 2.0 this only called .deep if both sides were arrays. Loosened it
// when nearing 2.0.M6 to call .deep if either left or right side is an array.
// TODO: this is the same algo as in scalactic.DefaultEquality. Put that one in
// a singleton and use it in both places.
left match {
case leftArray: Array[_] =>
right match {
case rightArray: Array[_] => leftArray.deep == rightArray.deep
case _ => leftArray.deep == right
}
case _ => {
right match {
case rightArray: Array[_] => left == rightArray.deep
case _ => left == right
}
}
}
}
In Scala, at least on the JVM, == simply calls equals, which, if not overridden, checks whether the compared variables point to the same object. case classes are peculiar in that the compiler overrides equals for you to compare the constructor arguments.
You can test it very easily with the following (but as you can imagine, the same applies to simply using == on your own):
package org.example
import org.scalatest.{FlatSpec, Matchers}
final class MyClass(val a: Int)
final case class MyCaseClass(a: Int)
final class TestSpec extends FlatSpec with Matchers {
"equality on case classes" should "succeed" in {
new MyCaseClass(1) shouldBe new MyCaseClass(1)
}
"equality on non-case classes" should "fail" in {
new MyClass(1) shouldNot be(new MyClass(1))
}
"equality between Regex objects" should "fail" in {
"abc".r shouldNot be("abc".r)
}
}
What the r method does is instantiating a new Regex object, which is not a case class and does not override the equality definition, thus yielding the result you see.

Answer 3

Yes, they are not equal. Both "abc".r are different references to two different memory locations. shouldbe is to check equality but not identity.