Two Table Views in One VC - swift

Question

I want to display two (or more) table views from a single view controller. I mean display simultaneously, e.g., beside each other or one above the other. The only way I can think of doing it is with child view controllers. Is there a better or easier way?
Thanks for your comments.

Answer 1

Yes of course you can use like this:
override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell
{
if tableView == firstTableView
{
let cell = tableView.dequeueReusableCell(withIdentifier: "LabelCell1", for: indexPath)
cell.textLabel?.text = "Section \(indexPath.section) Row \(indexPath.row)"
return cell
}
else if (tableView == secondTableView)
{
let cell = tableView.dequeueReusableCell(withIdentifier: "LabelCell2", for: indexPath)
cell.textLabel?.text = "Section \(indexPath.section) Row \(indexPath.row)"
return cell
}
else
{
return UITableViewCell()
}
}
Similar to other tableview delegate methods, you should add a condition for each table

Answer 2

If your use case is to have two individually scrolling table views then you can simply add two table views in the xib, assign datasource and delegates and call it a day.
If your use case is to display two types of information on a page I'd recommend using just one table view and handling what to display manually.
Let me know if you need any more help.

Answer 3

Use Switch Condition
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = UITableViewCell()
switch tableView {
case firsttableView:
let cell = tableView.dequeueReusableCell(withIdentifier: "TableViewCell", for: indexPath) as! TableViewCell
cell.label1.text = "Zaid"
cell.label2.text = "Ahamd"
return cell
case secondTableView:
let cell = tableView.dequeueReusableCell(withIdentifier: "SecondTableViewCell", for: indexPath) as! SecondTableViewCell
cell.labelText.text = "ZaidAfzalMughal"
return cell
default:
print("Something wrong")
}
return cell
}