Given two linestrings that occupy the same space, is it possible to define a style such that the lines are offset from each other and are rendered side-by-side?
A colleague says he can half remember that this functionality is available in the style spec, but I have not been able to find reference to it. Is it possible?
The property you are looking for is "Line-Offset".
From documentation (paint-line-line-offset as of 2018-09-17) :
line-offset (Paint property) Optional number. Units in pixels. Defaults to 0. Transitionable.
The line's offset.
For linear features, a positive value offsets the line to the right, relative
to the direction of the line, and a negative value to the left.
For polygon features, a positive value results in an inset, and a negative value results in an outset.
Related
I was visualizing my vorticity vector field and notice that I am not able to see the pattern without zooming in as there are too many glyphs and are too packed.
Currently, I am using a calculator to combine X,Y,Z vorticity field into a single vector field using the calculator. Take a slice of it and do a glyph filter visualizing all points on the plane.
I notice that one possible way is to visualize a curved glyphs and scale up a little bit to make it more noticeable, but not sure how to do that. Does anyone know whats the steps to do that? Or any other suggestions?
TIA
Have you tried reducing the Maximum Number of Sample Points property in the Properties Panel when the Glyph filter is selected in the Pipeline Browser? You may also want to change the Scale Factor property to change the length of the glyphs.
I would like to have a text box rescale with the level of magnification, such that one unit of text is always assigned one unit of horizontal axis-length. The text width should not change but rather the spacing between characters.
For instance, if the x-axis displayed [0:50], fifty characters should be displayed, one at each integer position. If the magnification was increased such that the display comprised only [0:10], only ten characters would be displayed, again placing one character at each integer position along the horizontal axis.
Finally, the text would ideally not display when the magnification level was below some threshold determined by the number of characters that can be legibly printed along a horizontal line spanning the extent of the axes.
I have tried using the text object, but it doesn't seem to have the relevant properties to allow such dynamic behavior. I have instead considered breaking the N-length string into N unit-length strings and placing each at a defined x-position, but I'm having trouble figuring out how to display only those relevant at the prevailing zoom level (there is some spill-over of characters beyond the bounds of the axis). In contrast, with this approach, all the characters appear as a jumble at zoom levels so low that the number of characters printed cannot be reasonably accommodated.
Thus, I inquire whether another solution besides printing a series of unit-length strings might be advised and, if not, how the twin problems of text spill-over and text overlap can be resolved at high and low zoom, respectively (the first might be done by somehow preventing printing of information outside the axes; the second seems to require some dynamic magnification-aware means of suppressing text output at or above a certain x-axis extent).
The way I understand how emacs displays stuff is that essentially everything is text. If you have something in the fringe or linum mode active, essentially your document is pushed a little inwards and something is written in the first few columns.
I'm writing a function for putting some stuff into the head-line and this works nicely, however, I would like the start of the text to be aligned with the start of the document.
Thus I am looking for a way to get the number of columns that sit between the frame border and the start of the actual document.
Let me illustrate using a poorly produced graphic:
I want to get the number of columns (or the number of pixels) that make up the distance marker by the ruler just below the line number 10000.
The function which returns this value shall be executed in the functions which create the head-line.
There is a function called window-inside-edges that you can use to determine the offset of the text area ("window body") from the total width and height of the window in columns and lines, respectively.
It returns a list four values; the order is left - top - right - bottom, so to get the value you are interested in for the current window, just do
(car (window-inside-edges))
More information on window coordinates can be found here; this page has information about window sizes, including a nice ASCII representation of window elements.
I am drawing text in a PDF page using iTextSharp, and I have two requirements:
1) the text needs to be searchable by Adobe Reader and such
2) I need character-level control over where the text is drawn.
I can draw the text word-by-word using PdfContentByte.ShowText(), but I don't have control over where each character is drawn.
I can draw the text character-by-character using PdfContentByte.ShowText() but then it isn't searchable.
I'm now trying to create a PdfTextArray, which would seem to satisfy both of my requirements, but I'm having trouble calculating the correct offsets.
So my first question is: do you agree that PdfTextArray is what I need to do, in order to satisfy both of my original requirements?
If so, I have the PdfTextArray working correctly (in that it's outputting text) but I can't figure out how to accurately calculate the positioning offset that needs to get put between each pair of characters (right now I'm just using the fixed value -200 just to prove that the function works).
I believe the positioning offset is the distance from the right edge of the previous character to the left edge of the new character, expressed in "thousandths of a unit of text space". That leaves me two problems:
1) How wide is the previous character (in points), as drawn in the specified font & height? (I know where its left edge is, since I drew it there)
2) How do I convert from points to "units of text space"?
I'm not doing any fancy scaling or rotating, so my transformation matrices should all be identity matrices, which should simplify the calculations ...
Thanks,
Chris
I am creating a Microsoft Word document using the OpenXml library. Most of what I need is already working correctly. However, I can't for the life of me find the following bit of information.
I'm displaying an image in an anchor, which causes text to wrap around the image. I used WrapSquare but this seems to affect the last line of the previous paragraph as shown in the image below. The image is anchored to the second paragraph but causes the last line of the first paragraph to also indent around the image.
Word Screenshot http://www.softcircuits.com/Client/Word.jpg
Experimenting within Word, I can make the text wrap how I want by changing the wrapping to WrapTight. However, this requires a WrapPolygon with several coordinates. And I can't find any way to determine the polygon coordinates so that they match the size of the image, which is in pixels.
The documentation doesn't even seem to indicate what units are used for these coordinates, let alone how to calculate them from pixels. I can only assume the calculation would involve a DPI value, but I have no idea how to determine what DPI will be used when the user eventually loads the document into Word.
I would also be satisfied if someone can explain why the issues described above is happening in the first place. I can shift the image down and the previous paragraph is no longer affected. But why is this necessary? (The Distance from text setting for both Left and Top is 0".)
The WrapPolygon element has two possible child elements of LineTo and StartPoint that each take a x and y coordinate. According to 2.1.1331 Part 1 Section 20.4.2.9, lineTo (Wrapping Polygon Line End Position) and 2.1.1334 Part 1 Section 20.4.2.14, start (Wrapping Polygon Start) found in the [MS-OI29500: Microsoft Office Implementation Information for ISO/IEC-29500 Standard Compliance]:
The standard states that the x and y attributes are represented in
EMUs. Office interprets the x and y attributes in a fixed coordinate
space of 21600x21600.
As far as converting pixels to EMUs (English Metric Units), take a look at this blog post for an example.
I finally resolved this. Despite what the standard says, the WrapPolygon coordinates are not EMUs (English Metric Units). The coordinates are relative to the fixed coordinate space (21600 x 21600, as mentioned in the quote provided by amurra).
More specifically, this means 0,0 is at the top, left corner of the image, and 21600,21600 is at the bottom, right corner of the image. This is the case no matter what the size of the image is. Coordinates greater than 21600 extend outside the image.
According to this article, "The 21600 value is a legacy artifact from the drawing layer of early versions of the Microsoft Office."