How to convert hex string to byte array in CAPL? - type-conversion

Question

Considering having, for example, this type of hex string:
char hex_str[100] = "0x01 0x03 0x04 0x0A";
How to get out of this string the byte array representation in CAPL, like:
byte hex_str_as_byte_arr[4] = {0x01, 0x03, 0x04, 0x0A};
EDIT: Only Vector CANoe supported data types/functions are allowed!

Answer 1

Use strtok to split the character array into separate hex strings, then use long strtol( const char *restrict str, char **restrict str_end, int base ) to convert each hex string to an integral value.

Answer 2

Thanks to all...
Actually I've found a solution myself:
char hex_str[100] = "0x01 0x03 0x04 0x0A";
long data[4];
dword pos = 0;
pos = strtol(hex_str, pos, data[0]);
pos = strtol(hex_str, pos, data[1]);
pos = strtol(hex_str, pos, data[2]);
pos = strtol(hex_str, pos, data[3]);
write("0x%02x,0x%02x,0x%02x, 0x%02x", data[0], data[1], data[2], data[3]);
Now it's a simple cast: (byte) data[0]

Answer 3

We can use sscanf() to convert the numbers to unsigned char. In a loop, we'll need to also use a %n conversion to determine the reading position for the next iteration.
Here's a simple example (in real life, you'll need some range checking to make sure you don't overrun the output buffer):
#include <stdio.h>
int main(void)
{
const char hex_str[100] = "0x01, 0x03, 0x04, 0x0A";
unsigned char bytes[4];
{
int position;
unsigned char *b = bytes;
for (const char *input = hex_str; sscanf(input, "%hhi, %n", b, &position) == 1; ++b) {
input += position;
}
}
/* prove we did it */
for (size_t i = 0; i < sizeof bytes; ++i) {
printf("%hhu ", bytes[i]);
}
puts("");
}