I want to iterate through this array and separate out the names that have status true.
var array = [["name":"joe", "status":false ],["name":"will", "status":false],["name":"smith" , "status":false]]
This should do the trick.
var array = [["name":"joe", "status":true ],["name":"will", "status":true],["name":"smith" , "status":false]]
let filteredDictionary = array.filter( { $0["status"] as? Bool ?? false } )
var names = [String]()
for dictionary in filteredDictionary {
if let nameFound = dictionary["name"] as? String {
names.append(nameFound)
}
}
I recommend that you use a struct to store the values instead of a dictionary. Something like this.
struct Person {
var name: String
var status: Bool
}
If you have it like this in a Person array, it becomes less complicated as dictionary value optional handling can be avoided.
var personArray = [Person(name: "joe", status: true), Person(name: "will", status: false)
let names = personArray.filter( {$0.status} ).map( {$0.name} )
You can use a simple filter is you want to keep both the status and name, otherwise use compactMap is you just want to keep the name.
let statuses = [["name":"joe", "status":true ],["name":"will", "status":false],["name":"smith" , "status":false]]
let trueStatuses = statuses.filter({$0["status"] as? Bool == true}) // [["name": "joe", "status": true]]
let namesWithTrueStatus = statuses.compactMap{$0["status"] as? Bool == true ? $0["name"] as? String : nil} //["joe"]
Related
I have two table views
#IBOutlet var specialitiesAll: UITableView!
#IBOutlet var specialitiesAdded: UITableView!
and they each populate separate arrays
var allArray = Array<Dictionary<String, Any>>()
var addedArray = Array<Dictionary<String, Any>>()
One is populated with all items, the other is items the user added, both I get from an API
let newAddedArray = self.userProfile["specialities"] as! Array<Dictionary<String, Any>>
for item in newAddedArray
{
self.addedArray.append(["id" : item["id"]!, "text" : item["name"]!])
}
self.specialitiesAdded.reloadData()
getSpecialities(){ result in
for item in result
{
self.allArray.append(["id" : item["id"]!, "text" : item["text"]!])
}
self.specialitiesAll.reloadData()
}
My question is allArray has all the items, how would I either remove or skip the items that are in addedArray or newAddedArray?
You can first convert Array into Set and perform difference set processing. Hash table is very efficient and the order may be messy. Direct processing of Arrays is not efficient, but the order is guaranteed to be the same. According to the scene selection?
var employees: Set = ["Alicia", "Bethany", "Chris", "Diana", "Eric"]
let neighbors: Set = ["Bethany", "Eric", "Forlani", "Greta"]
employees.subtract(neighbors)
print(employees)
try this.
extension Array {
func containsObject(_ object: Any) -> Bool {
let anObject = object as AnyObject
for obj in self {
let anObj = obj as AnyObject
return anObj.isEqual(anObject)
}
return false
}
}
let array1: [[String: Any]] = [["a": 1, "b": "123"], ["c": 456.5]]
let array2: [[String: Any]] = [["a": 1, "b": "123"]]
let result = array1.filter{ !array2.containsObject($0) }
print(result)
//[["c": 456.5]]
I decided to go this route with no extensions
getSpecialities(){ result in
for item in result
{
if (self.addedArray.contains(where: { $0["id"] as! Int == item["id"] as! Int }) == false) {
self.allArray.append(["id" : item["id"]!, "text" : item["text"]!])
}
}
self.specialitiesAll.reloadData()
}
I have a core data framework to handle everything you can do with coredata to make it more cooperateable with codable protocol. Only thing i have left is to update the data. I store and fetch data by mirroring the models i send as a param in their functions. Hence i need the variable names in the models if i wish to only update 1 specific value in the model that i request.
public func updateObject(entityKey: Entities, primKey: String, newInformation: [String: Any]) {
let request = NSFetchRequest<NSFetchRequestResult>(entityName: entityKey.rawValue)
do {
request.predicate = NSPredicate.init(format: "\(entityKey.getPrimaryKey())==%#", primKey)
let fetchedResult = try delegate.context.fetch(request)
print(fetchedResult)
guard let results = fetchedResult as? [NSManagedObject],
results.count > 0 else {
return
}
let key = newInformation.keys.first!
results[0].setValue(newInformation[key],
forKey: key)
try delegate.context.save()
} catch let error {
print(error.localizedDescription)
}
}
As you can see the newInformation param contains the key and new value for the value that should be updated. However, i dont want to pass ("first": "newValue") i want to pass spots.first : "newValue"
So if i have a struct like this:
struct spots {
let first: String
let second: Int
}
How do i only get 1 name from this?
i've tried:
extension Int {
var name: String {
return String.init(describing: self)
let mirror = Mirror.init(reflecting: self)
return mirror.children.first!.label!
}
}
I wan to be able to say something similar to:
spots.first.name
But can't figure out how
Not sure that I understood question, but...what about this?
class Spots: NSObject {
#objc dynamic var first: String = ""
#objc dynamic var second: Int = 0
}
let object = Spots()
let dictionary: [String: Any] = [
#keyPath(Spots.first): "qwerty",
#keyPath(Spots.second): 123,
]
dictionary.forEach { key, value in
object.setValue(value, forKeyPath: key)
}
print(object.first)
print(object.second)
or you can try swift keypath:
struct Spots {
var first: String = ""
var second: Int = 0
}
var spots = Spots()
let second = \Spots.second
let first = \Spots.first
spots[keyPath: first] = "qwerty"
spots[keyPath: second] = 123
print(spots)
however there will be complex (or impossible) problem to solve if you will use dictionary:
let dictionary: [AnyKeyPath: Any] = [
first: "qwerty",
second: 123
]
you will need to cast AnyKeyPath back to WritableKeyPath<Root, Value> and this seems pretty complex (if possible at all).
for path in dictionary.keys {
print(type(of: path).rootType)
print(type(of: path).valueType)
if let writableKeyPath = path as? WritableKeyPath<Root, Value>, let value = value as? Value { //no idea how to cast this for all cases
spots[keyPath: writableKeyPath] = value
}
}
So im using CloudKit and fetching all the data into an array as [StartDay], my StartDay class looks like this:
import UIKit
import CloudKit
class StartDay {
var recordID: CKRecord.ID!
var wakeUp: String!
var sleptWell: String!
var dNN: String!
var created: String! {
get {
return created
}
}
}`
My function loads get an arraylist, which contains information received from the database. In my database it stands like this: "22.01.09:
func checkIfButtonShouldBeEnabled(startDayList: [StartDay]){
let startDayDates = startDayList.map{$0.created}
for i in 0..<startDayDates.count {
print(startDayDates)
}
}`
OUTPUT:
Optional("22.01.2019")
Optional("22.01.2019")
I want to remove "Optional()", so it only says "22.01.2019", how can I do so?
UPDATE: FETCH FUNC
func loadStartDay() -> [StartDay]{
let predicate = NSPredicate(value: true)
let query = CKQuery(recordType: "StartDay", predicate: predicate)
let operation = CKQueryOperation(query: query)
var startDays: [StartDay] = []
operation.desiredKeys = ["wakeUp", "wellSlept", "dNN", "recordID", "createdDato"]
operation.recordFetchedBlock = { (record:CKRecord) in
let newStartDay = StartDay()
newStartDay.wakeUp = record.object(forKey: "wakeUP") as? String
newStartDay.sleptWell = record.object(forKey: "sleptWell") as? String
newStartDay.dNN = record.object(forKey: "dNN") as? String
newStartDay.recordID = record.object(forKey: "recordID") as? CKRecord.ID
newStartDay.created = record.object(forKey: "createdDato") as? String
print(newStartDay.created)
startDays.append(newStartDay)
}
You can use print(startDayDates!) or print(startDayDates ?? "default value").
But I recommend usage of startDayList.compactMap() instead of startDayList.map()to ensure your array doesn't contain nil values.
You can also do like this:
startDayList
.compactMap { $0.created }
.forEach { print($0) }
As you designed the database model you exactly know which record attributes always exist. Declaring class properties as implicit unwrapped optional as an alibi not to write an initializer is very bad practice.
Assuming every attribute in a record does have a value declare the properties as non-optional and write an initializer.
At least created and recordID are supposed to have always a value!
import UIKit
import CloudKit
class StartDay {
var recordID: CKRecord.ID
var wakeUp: String
var sleptWell: String
var dNN: String
var created: String
init(record : CKRecord) {
// recordID can be retrieved directly
self.recordID = record.recordID
self.wakeUp = record.object(forKey: "wakeUP") as! String
self.sleptWell = record.object(forKey: "sleptWell") as! String
self.dNN = record.object(forKey: "dNN") as! String
self.created = record.object(forKey: "createdDato") as! String
}
}
and create instances with
operation.recordFetchedBlock = { record in
startDays.append(StartDay(record: record))
}
Now the Optional has gone.
print(startDayList.map{ $0.created })
Say I have a struct Coin
struct Coin {
var value: Float?
var country: String?
var color: String?
}
I have two instances of a Coin; we'll call them coinA and coinB.
let coinA = Coin()
coinA.value = nil
coinA.country = "USA"
coinA.color = "silver"
let coinB = Coin()
coinB.value = 50.0
Now, I want to merge the values of coinB into coinA. So the result would be coinA whose values would result in:
country = "USA"
color = "silver"
value = 50.0
I am able to accomplish this with Dictionary objects using the merge() function. However, I am unsure how to accomplish this using custom Swift objects. Is there a way?
Update
Here's how I've gotten it to work with dictionaries:
var originalDict = ["A": 1, "B": 2]
var newDict = ["B": 69, "C": 3]
originalDict.merge(newDict) { (_, new) in new }
//originalDict = ["A": 1, "B": 69, "C": 3]
And I will further clarify, in this function if the newDict does not have keys that the originalDict, the originalDict maintains them.
Ultimately, the most efficient way in the fewest lines of code is probably exactly what you'd expect:
extension Coin {
func merge(with: Coin) -> Coin {
var new = Coin()
new.value = value ?? with.value
new.country = country ?? with.country
new.color = color ?? with.color
return new
}
}
let coinC = coinA.merge(with: coinB)
Note that in the above scenario, the resulting value will always be coinA's, and will only be coinB's if coinA's value for a given key is nil. Whenever you change, add, or delete a property on Coin, you'll have to update this method, too. However, if you care more about future-proofing against property changes and don't care as much about writing more code and juggling data around into different types, you could have some fun with Codable:
struct Coin: Codable {
var value: Float?
var country: String?
var color: String?
func merge(with: Coin, uniquingKeysWith conflictResolver: (Any, Any) throws -> Any) throws -> Coin {
let encoder = JSONEncoder()
let selfData = try encoder.encode(self)
let withData = try encoder.encode(with)
var selfDict = try JSONSerialization.jsonObject(with: selfData) as! [String: Any]
let withDict = try JSONSerialization.jsonObject(with: withData) as! [String: Any]
try selfDict.merge(withDict, uniquingKeysWith: conflictResolver)
let final = try JSONSerialization.data(withJSONObject: selfDict)
return try JSONDecoder().decode(Coin.self, from: final)
}
}
With that solution, you can call merge on your struct like you would any dictionary, though note that it returns a new instance of Coin instead of mutating the current one:
let coinC = try coinA.merge(with: coinB) { (_, b) in b }
I thought it would be interesting to show a solution based on Swift key paths. This allows us to loop somewhat agnostically through the properties — that is, we do not have to hard-code their names in a series of successive statements:
struct Coin {
var value: Float?
var country: String?
var color: String?
}
let c1 = Coin(value:20, country:nil, color:"red")
let c2 = Coin(value:nil, country:"Uganda", color:nil)
var c3 = Coin(value:nil, country:nil, color:nil)
// ok, here we go
let arr = [\Coin.value, \Coin.country, \Coin.color]
for k in arr {
if let kk = k as? WritableKeyPath<Coin, Optional<Float>> {
c3[keyPath:kk] = c1[keyPath:kk] ?? c2[keyPath:kk]
} else if let kk = k as? WritableKeyPath<Coin, Optional<String>> {
c3[keyPath:kk] = c1[keyPath:kk] ?? c2[keyPath:kk]
}
}
print(c3) // Coin(value: Optional(20.0), country: Optional("Uganda"), color: Optional("red"))
There are unfortunate features of key paths that require us to cast down from the array element explicitly to any possible real key path type, but it still has a certain elegance.
If you're willing to make the merge function specific to Coin, you can just use the coalesce operator like so:
struct Coin {
var value: Float?
var country: String?
var color: String?
func merge(_ other: Coin) -> Coin {
return Coin(value: other.value ?? self.value, country: other.country ?? self.country, color: other.color ?? self.color)
}
}
let coinC = coinA.merge(coinB)
This will return a new Coin using the values from coinB, and filling in any nils with those from coinA.
If your goal is to change coin A what you need is a mutating method. Note that structures are not like classes. If you would like to change its properties you need to declare your coin as variable. Note that none of your examples would compile if you declare your coins as constants:
struct Coin {
var value: Float?
var country: String?
var color: String?
mutating func merge(_ coin: Coin) {
value = value ?? coin.value
country = country ?? coin.country
color = color ?? coin.color
}
init(value: Float? = nil, country: String? = nil, color: String? = nil) {
self.value = value
self.country = country
self.color = color
}
}
Playground testing:
var coinA = Coin(country: "USA", color: "silver")
coinA.merge(Coin(value: 50))
print(coinA.country ?? "nil") // "USA"
print(coinA.color ?? "nil") // "silver"
print(coinA.value ?? "nil") // 50.0
This is not a high-level approach like the merge one you shared the link to but as long as you have a struct to implement the merge feature into, it will do the job.
func merge(other: Coin, keepTracksOfCurrentOnConflict: Bool) -> Coin {
var decidedValue = value
if decidedValue == nil && other.value != nil {
decidedValue = other.value
} else if other.value != nil {
//in this case, it's conflict.
if keepTracksOfCurrentOnConflict {
decidedValue = value
} else {
decidedValue = other.value
}
}
var resultCoin = Coin(value: decidedValue, country: nil, color: nil)
return resultCoin
}
}
You can do the same for other properties.
If you want to wrap it around protocol. The idea behind is the same:
you convert object's to dict
merge two dict's
convert merged dict back to your object
import Foundation
protocol Merge: Codable {
}
extension Dictionary where Key == String, Value == Any {
func mergeAndReplaceWith(object: [Key: Value]) -> [Key: Value] {
var origin = self
origin.merge(object) { (_, new) in
new
}
return origin
}
}
extension Merge {
func toJson() -> [String: Any] {
let jsonData = try! JSONEncoder().encode(self)
let json = try! JSONSerialization.jsonObject(with: jsonData, options: []) as! [String: Any]
return json
}
func merge(object: Merge) -> Merge {
let origin = self.toJson()
let objJson = object.toJson()
let decoder = JSONDecoder()
let merge = origin.mergeAndReplaceWith(object: objJson)
var jsonData = try! JSONSerialization.data(withJSONObject: merge, options: .prettyPrinted)
var mergedObject = try! decoder.decode(Self.self, from: jsonData)
return mergedObject
}
}
struct List: Merge {
let a: String
}
struct Detail: Merge {
struct C: Codable {
let c: String
}
let a: String
let c: C?
}
let list = List(a: "a_list")
let detail_without_c = Detail(a: "a_detail_without_c", c: nil)
let detail = Detail(a: "a_detail", c: Detail.C(c: "val_c_0"))
print(detail.merge(object: list))
print(detail_without_c.merge(object: detail))
Detail(a: "a_list", c: Optional(__lldb_expr_5.Detail.C(c: "val_c_0")))
Detail(a: "a_detail", c: Optional(__lldb_expr_5.Detail.C(c: "val_c_0")))
With this solution you can actually merge two representations of your endpoint, in my case it is List and Detail.
I'm new to Swift programming. For my particular project, I'm trying to filter a dictionary with some user input, and the dictionary's value consists of an array.
Here is some sample code, and what I'm trying to accomplish:
var dictionary = ["a": ["aberration", "abc"], "b" : ["babel", "bereft"]]
var filteredDictionary = [String: [String]]()
var searchText = "aberration"
//getting the first letter of string
var firstLetter = searchText[searchText.startIndex]
With this particular searchText, I'm trying to get:
filteredDictionary = ["a": ["aberration"]]
Edit: I want the dictionary to return with the first letter as its key, and the values with what searchText matches up with. Sorry if it I wasn't clear.
Here is some code I have tried, but obviously, I can't get it to work:
filteredDictionary = dictionary.filter{$0.key == firstLetter && for element in $0.value { element.hasPrefix(searchText) }}
Any help would be appreciated. Thanks.
Here's a solution that maps the values based on the search and then filters out the empty results.
var dictionary = ["a": ["aberration", "abc"], "b" : ["babel", "bereft"]]
var searchText = "aberration"
let filteredDictionary = dictionary.mapValues { $0.filter { $0.hasPrefix(searchText) } }.filter { !$0.value.isEmpty }
print(filteredDictionary)
Output:
["a": ["aberration"]]
Try this:
var dictionary = ["a": ["aberration", "abc"], "b" : ["babel", "bereft"]]
var searchText = "aberration"
var filteredDictionary = dictionary.filter { (key, value) -> Bool in
return (value as! [String]).contains(searchText)
}.mapValues { (values) -> [String] in
return [searchText]
}
print(filteredDictionary)
You can use a combination of filter and map to achieve the desired result.
Output:
["a": ["aberration"]]
let firstLetter = String(searchText[searchText.startIndex])
let filteredDictionary = dictionary
.reduce(into: [String: [String]]()) { (result, object) in
if object.key == firstLetter {
let array = object.value.filter({ $0.hasPrefix(searchText) })
if array.count > 0 {
result[object.key] = array
}
}
}
Output:
["a": ["aberration"]]