Range position of letter in string duplicating [duplicate] - swift

Question

This question already has answers here:
Index of a substring in a string with Swift
(11 answers)
Closed 4 years ago.
I have a string like "abc1abc1".
What I want to do is bold each number of the string. I have drawn the code below. It works by separating each character of the string and putting them into an array. Then, in a loop, if each character contains an Int(), the character is bolded.
However, the issue comes when the there are two of the same Int. In the string above, there are 2 characters of 1, therefore the code will only bold the first character.
// Bold the numbers
let fullString = "abc1abc1"
let characters = Array(fullString)
let mutableString = NSMutableAttributedString(string: fullString)
for item in characters {
let string = String(item)
let decimalCharacters = CharacterSet.decimalDigits
let decimalRange = string.rangeOfCharacter(from: decimalCharacters)
if decimalRange != nil {
let str = NSString(string: fullString)
let range = str.range(of: string)
mutableString.addAttribute(NSAttributedStringKey.foregroundColor, value: UIFont.systemFont(ofSize: 18, weight: .heavy), range: range)
}
}
instructionsLabel.attributedText = mutableString
// characters = ["a", "b", "c", "1", "a", "b", "c", "1"]
// range of ints returns {3, 1} and {3, 1}
// range of ints SHOULD return {3, 1} and {7, 1}

Answer 1

Try this:
let fullString = "abc1abc1"
let range = NSRange(location: 0, length: (fullString as NSString).length)
let mutableString = NSMutableAttributedString(string: fullString)
let regex = try! NSRegularExpression(pattern: "[0-9]")
let matches = regex.matches(in: fullString, range: range)
for match in matches {
mutableString.addAttributes([.font: UIFont.systemFont(ofSize: 18, weight: .heavy)], range: match.range)
}
instructionsLabel.attributedText = mutableString