I'm having an issue using the ACCESS DateDiff function. I'm attempting to obtain the FULL months between two dates however this function ignores dates in the middle of the month. It apparently performs a simple calculation on the month number itself and does not take into account the day of the month.
For example: If I want to know the full month between October 16th and November 3rd. This should return zero however the DateDiff function is returning 1. What code do I need to implement in order to obtain the full months between and have it work for ALL months. I say ALL months as months can have 28 days (29 in a leap year), 30 days and 31 days which is why I wouldn't simply calculate the days between two dates.
Access Function: DateDiff("m",PAID_DATE,STATIC_DATE) AS Months_Between
The screenshot below shows the data I want as well as the incorrect month between results I am obtaining.
Lastly a screenshot of a simple representation of my output in the ACCESS Design View.
Oracle Example of what I'm trying to accomplish in ACCESS
I can accomplish this in Oracle very easy as oracle's Months_Between function takes into account the months and leap years and the days within each month and outputs the actual months between value. If I knew how to get this in ACCESS I wouldn't have posted this question.
You'll need a custom function like this:
Public Function Months( _
ByVal datDate1 As Date, _
ByVal datDate2 As Date, _
Optional ByVal booLinear As Boolean) _
As Integer
' Returns the difference in full months between datDate1 and datDate2.
'
' Calculates correctly for:
' negative differences
' leap years
' dates of 29. February
' date/time values with embedded time values
' negative date/time values (prior to 1899-12-29)
'
' Optionally returns negative counts rounded down to provide a
' linear sequence of month counts.
' For a given datDate1, if datDate2 is decreased stepwise one month from
' returning a positive count to returning a negative count, one or two
' occurrences of count zero will be returned.
' If booLinear is False, the sequence will be:
' 3, 2, 1, 0, 0, -1, -2
' If booLinear is True, the sequence will be:
' 3, 2, 1, 0, -1, -2, -3
'
' If booLinear is False, reversing datDate1 and datDate2 will return
' results of same absolute Value, only the sign will change.
' This behaviour mimics that of Fix().
' If booLinear is True, reversing datDate1 and datDate2 will return
' results where the negative count is offset by -1.
' This behaviour mimics that of Int().
' DateAdd() is used for check for month end of February as it correctly
' returns Feb. 28. when adding a count of months to dates of Feb. 29.
' when the resulting year is a common year.
'
' 2010-03-30. Cactus Data ApS, CPH.
Dim intDiff As Integer
Dim intSign As Integer
Dim intMonths As Integer
' Find difference in calendar months.
intMonths = DateDiff("m", datDate1, datDate2)
' For positive resp. negative intervals, check if the second date
' falls before, on, or after the crossing date for a 1 month period
' while at the same time correcting for February 29. of leap years.
If DateDiff("d", datDate1, datDate2) > 0 Then
intSign = Sgn(DateDiff("d", DateAdd("m", intMonths, datDate1), datDate2))
intDiff = Abs(intSign < 0)
Else
intSign = Sgn(DateDiff("d", DateAdd("m", -intMonths, datDate2), datDate1))
If intSign <> 0 Then
' Offset negative count of months to continuous sequence if requested.
intDiff = Abs(booLinear)
End If
intDiff = intDiff - Abs(intSign < 0)
End If
' Return count of months as count of full 1 month periods.
Months = intMonths - intDiff
End Function
Related
In Access, I would like to convert a date column in format yywwd to dd-mm-yy. (weekday nr. 1 is monday, and years can only from 2000 and later, so e.g. today (monday 15-06-2020) would be 20251 what I would like to be converted to 15-06-2020.
I'm not much of a coder so honestly asside from messing with Datepart I have not tried a whole lot. Does anyone have suggestion?
It seems that the function 'GetDayFromWeekNumber' mentioned here vba convert week number (and year) to date? could work but how is this used in MSAccess?
Thanks a lot in advance!
I have a function that works in Excel to convert YYWWD to a date, this should be very similar if not identical to the code needed in Access. It is quite verbose so you could probably make it simpler, but at least the calculation steps are clearly set out.
The function assumes the ISO definition of week number - i.e. the first week of the year is the week in which the 4th of Jan falls. The first day of a week is Monday, the last day of a week is Sunday.
Function dateFromYYWWD(yywwd)
Dim sYYWWD As String
Dim sYYYY As String
Dim ww As Integer
Dim d As Integer
Dim fourthOfJan As Date
Dim fourthOfJanWeekday As Integer
Dim week1StartDate As Date
Dim targetWeekStartDate As Date
Dim targetDate As Date
' Convert to string if not already
sYYWWD = "" & yywwd
' Get the year in full
sYYYY = "20" + Left(sYYWWD, 2)
' Get the week number and day in the week
ww = CInt(Mid(sYYWWD, 3, 2))
d = CInt(Right(sYYWWD, 1))
' Calculate the date of 4th Jan in the same year
fourthOfJan = CDate(sYYYY & "-01-04")
' Get the day of week of the 4th Jan
' NOTE - CALCULATES MONDAY AS DAY 1 OF THE WEEK, SUNDAY AS DAY 7
fourthOfJanWeekday = Weekday(fourthOfJan, vbMonday)
' Date of the first day of week #1 in the target year
week1StartDate = fourthOfJan - fourthOfJanWeekday + 1
' First day of the target week
targetWeekStartDate = week1StartDate + (ww - 1) * 7
' Target date
targetDate = targetWeekStartDate + d - 1
dateFromYYWWD = targetDate
End Function
It's as simple as this:
Public Function ConvertFromYYWWD(s) As Date
Dim t&
t = DateSerial(2000 + Mid(s, 1, 2), 1, 1) + 7 * (Mid(s, 3, 2) - 1)
ConvertFromYYWWD = t - Weekday(t, vbMonday) + Mid(s, 5, 1)
End Function
Just place the above function in a code module in the database project.
You mentioned in the comments under your question that the week number is always two digits. I am assuming the the year number is likewise always two digits.
The first task is to split the value:
YWDDate = 20251
Year = YWDDate \ 1000 + 2000
2020
Week = (YWDDate Mod 1000) \ 10
25
Weekday = YWDDate Mod 10
1
Then, as this probably is ISO 8601 week numbering, the year is not the calendar year but the ISO 8601 year, which native VBA knows nothing about, thus a custom function is needed:
' First day of the week.
WeekStart = DateYearWeek(25, 2020, vbMonday)
' Requested day of week (which here is the same)
WeekDate = DateAdd("d", 1 - 1, WeekStart)
The function is not that convoluted:
' Returns the date of Monday for the ISO 8601 week of IsoYear and Week.
' Optionally, returns the date of any other weekday of that week.
'
' 2017-05-03. Gustav Brock, Cactus Data ApS, CPH.
'
Public Function DateYearWeek( _
ByVal IsoWeek As Integer, _
Optional ByVal IsoYear As Integer, _
Optional ByVal DayOfWeek As VbDayOfWeek = VbDayOfWeek.vbMonday) _
As Date
Dim WeekDate As Date
Dim ResultDate As Date
If IsoYear = 0 Then
IsoYear = Year(Date)
End If
' Validate parameters.
If Not IsWeekday(DayOfWeek) Then
' Don't accept invalid values for DayOfWeek.
Err.Raise DtError.dtInvalidProcedureCallOrArgument
Exit Function
End If
If Not IsWeek(IsoWeek, IsoYear) Then
' A valid week number must be passed.
Err.Raise DtError.dtInvalidProcedureCallOrArgument
Exit Function
End If
WeekDate = DateAdd(IntervalSetting(dtWeek), IsoWeek - 1, DateFirstWeekYear(IsoYear))
ResultDate = DateThisWeekPrimo(WeekDate, DayOfWeek)
DateYearWeek = ResultDate
End Function
but - as you can see - it calls some helper functions, which again call other functions, which will be too much to post here.
I can upload it somewhere, if you feel this will provide a solution for you.
I have searched, but all results didn't help me to understand.
I need to select names of people who are 18-23 years old.
So my try was:
WHERE ((People.Birth) Between (Now()-Year(18)) And (Now()-Year(23)))
What I'm doing wrong? Solution as #some_date# is a bad idea!
For a true solution, you need to use DateAdd and a function like this:
Public Function AgeSimple( _
ByVal datDateOfBirth As Date) _
As Integer
' Returns the difference in full years from datDateOfBirth to current date.
'
' Calculates correctly for:
' leap years
' dates of 29. February
' date/time values with embedded time values
'
' DateAdd() is used for check for month end of February as it correctly
' returns Feb. 28. when adding a count of years to dates of Feb. 29.
' when the resulting year is a common year.
' After an idea of Markus G. Fischer.
'
' 2007-06-26. Cactus Data ApS, CPH.
Dim datToday As Date
Dim intAge As Integer
Dim intYears As Integer
datToday = Date
' Find difference in calendar years.
intYears = DateDiff("yyyy", datDateOfBirth, datToday)
If intYears > 0 Then
' Decrease by 1 if current date is earlier than birthday of current year
' using DateDiff to ignore a time portion of datDateOfBirth.
intAge = intYears - Abs(DateDiff("d", datToday, DateAdd("yyyy", intYears, datDateOfBirth)) > 0)
End If
AgeSimple = intAge
End Function
Then your query will have this where clause:
WHERE AgeSimple(People.Birth) Between 18 And 23
Finally solved it by simple
WHERE ((People.Birth) Between (Now()- 365*18) And (Now()-365*23))
If you have better solution- welcome
Hi I am creating a table in MS Access to store the details of children in a school.
I have a field called YearGroup which needs to calculate the school year they are in based on their date of birth and whether they have been moved up or down a year.
I.e. if the expression deems they are six years old they should be placed in year 2. If they were moved down or up a year they should be in year 1 or 3 (this is based on another field in the table called YearModifier).
The code I have at the moment is this:
Year(Now()) - IIf(Month([DOB]) > 8, Year([DOB]) + 6 + [YearModifier], Year([DOB]) + 5 + [YearModifier])
My problem is that Year(Now()) is returning as invalid expression. Lots of websites have recognised using the Now() function and also I've tried Date() but nothing seems to be accepted by Access (The version is 2010).
What is going on? How can I get today's date in a calculated field expression?
Thanks
Try creating a query with all of the fields from your table, and then add an extra field YearGroup: Year(Now()) - IIf(Month([DOB]) > 8, Year([DOB]) + 6 + [YearModifier], Year([DOB]) + 5 + [YearModifier])
It appears that Date functions can't be used in calculated columns in tables.
You could use this to get the year, which might work in field expressions:
format(date(),"yyyy")
About your function (which I have re-written very slightly)
Year( Now() )
- Year([DOB])
- IIf( Month([DOB]) > 8
, 6
, 5 )
+ [YearModifier]
however!
I don't think you want to use now(). Which year they are in depend on their age at the 1st Sept at the start of the current academic year not now! Ok now will work until 31/dec/2015, so I must assume you will not be using the function after this date!
If you are you must use 2015 not Now().
Ok?
You can calculate the age of the children with a simple function:
Public Function AgeSimple( _
ByVal datDateOfBirth As Date) _
As Integer
' Returns the difference in full years from datDateOfBirth to current date.
'
' Calculates correctly for:
' leap years
' dates of 29. February
' date/time values with embedded time values
'
' DateAdd() is used for check for month end of February as it correctly
' returns Feb. 28. when adding a count of years to dates of Feb. 29.
' when the resulting year is a common year.
' After an idea of Markus G. Fischer.
'
' 2007-06-26. Cactus Data ApS, CPH.
Dim datToday As Date
Dim intAge As Integer
Dim intYears As Integer
datToday = Date
' Find difference in calendar years.
intYears = DateDiff("yyyy", datDateOfBirth, datToday)
If intYears > 0 Then
' Decrease by 1 if current date is earlier than birthday of current year
' using DateDiff to ignore a time portion of datDateOfBirth.
intAge = intYears - Abs(DateDiff("d", datToday, DateAdd("yyyy", intYears, datDateOfBirth)) > 0)
End If
AgeSimple = intAge
End Function
Then your expression would be something like this (ignoring the modifier):
ClassYear: IIf(AgeSimple([DOB]) > 6, 2, 1)
In my quarterly report Im trying to validate the two parameters StartDate and EndDate.
I first check if the difference between the dates is 2 months:
Switch(DateDiff(
DateInterval.Month, Parameters!StartDate.Value, Parameters!EndDate.Value) <> 2,
"Error message")
Then I try to add whether the StartDate is the first day of month AND EndDate is last day of month:
And (Day(Parameters!StartDate.Value) <> 1
And Day(DATEADD(DateInterval.Day,1,Parameters!EndDate.Value)))
So the whole expression looks like this:
Switch(DateDiff(DateInterval.Month, Parameters!StartDate.Value, Parameters!EndDate.Value) <> 2
And
Parameters!IsQuarterly.Value = true
And
Day(Parameters!StartDate.Value) <> 1
And
Day(DATEADD(DateInterval.Day,1,Parameters!EndDate.Value))<>1),
"Error: Quarterly report must include 3 months")
But It works wrong when the difference between dates is still 2 months, but StartDate and EndDate are not first and last day of the whole period.
I'd appreciate any help :)
I would say just change the implementation Add another two Parameter With Quarter and Year
Quarter like Q1,Q2,Q3 & Q4 with Value 1,2,3 & 4 respectively and year 2012,2013,2014 & so on
Now based on the parameter selected Qtr & Year set Default value of start & End Date
=DateSerial(Parameters!Year.Value), (3*Parameters!Qtr.Value)-2, 1) --First day of Quarter
=DateAdd("d",-1,DateAdd("q",1,Parameters!Year.Value, (3*Parameters!Qtr.Value)-2, 1))) --Last day of quarter
Doing this no need to do any validation bcz its always get the correct Date Difference.
Other Reference
First day of current quarter
=DateSerial(Year(Now()), (3*DatePart("q",Now()))-2, 1)
Last day of current quarter
=DateAdd("d",-1,DateAdd("q",1,DateSerial(Year(Now()), (3*DatePart("q",Now()))-2, 1)))
I am trying to fix a function which returns the number of weeks in a given year.
Here's how it looks:
Function GetWeekNo(date)
weekOfYear = DatePart("ww", DateValue(date), vbMonday, vbFirstFourDays)
If weekOfYear > 52 Then
If DatePart("ww", DateValue(date) + 7, vbMonday, vbFirstFourDays) = 2 Then
weekOfYear = 1
End If
End If
GetWeekNo = weekOfYear
End Function
When this function is given the date 12-31-2010 it returns 52. There are 53 weeks in 2010.
Note: I have no experience with classic ASP, what-so-ever.
Seems like it depends on which week is considered as the "first week of the year".
DatePart( "ww", "12/31/2010", vbMonday )
' returns 53
' FirstWeekOfYear parameter defaults to vbFirstJan1
' the week that contains January/01/2010
' here, its the week starting on December/28/2009
DatePart( "ww", "12/31/2010", vbMonday, vbFirstFourDays )
' returns 52
' FirstWeekOfYear parameter set to vbFirstFourDays
' the first week that has at least four days of the new year
' here, its the week starting on January/04/2010
DatePart( "ww", "12/31/2010", vbMonday, vbFirstFullWeek )
' returns 52
' FirstWeekOfYear parameter set to vbFirstFullWeek
' the first week that has full seven days of the new year
' here, again, its the week starting on January/04/2010
Decide what is your definition of the first week of the year, then use the DatePart function accordingly.