I've a problem to realize my query maybe someone of you can help me :)
I have 3 tables :
1) Documents
DocRef CustRef
Doc1 Cust1
Doc2 Cust2
Doc3 Cust1
2) LinkInter
DocRef InterRef
Doc1 Inter1
Doc2 Inter2
Doc3 Inter3
3) Inter
id InterRef deliverychannel email mobilenb date status
1 Inter1 Email email1#email.be 2013-01-14T00:00:00Z ok
2 Inter1 SMS 0444111111 2013-01-12T00:00:00Z ko
3 Inter1 Other email5#email.be 2013-02-21T00:00:00Z ko
4 Inter2 Email email2#email.be 044456465465 2013-01-21T00:00:00Z ko
5 Inter3 Email 2013-01-21T00:00:00Z ko
6 Inter3 SMS 2013-01-22T00:00:00Z ko
7 Inter3 Other email3#mail.be 2013-01-22T00:00:00Z ko
to have a best view go here: sqlfiddle
The result that I want is the following:
CustRef | number of InterRef SMS KO| Last email known| Last mobilenb known
Cust1 | 2 | email5#email.be | 0444111111
I want to have all the Customers where the deliverychannel = 'SMS' and the status = 'ko', the number of Inter (Interactions) with the status 'KO', the last email known and the last mobile number known.
I've tried with 2 functions getLastEmailKnown & getLastmobilenbKnown but with my tables that count more than 10.000.000 of records it takes a lot of times
I can have this result with php page but it's not the solution, I want to have only one query
If I execute 3 queries sepately, it works but i want only one
SELECT d.CustRef, count(DISTINCT i.InterRef) , i.email, i.mobilenb
FROM Documents d
INNER join LinkInter link on link.DocRef = d.DocRef
INNER join Inter i on i.InterRef = link.InterRef
and i.deliverychannel = 'SMS'
and i.status = 'ko'
group by d.CustRef
Order by d.CustRef DESC;
SELECT distinct i.email as lastEmailKnown, d.CustRef
FROM Inter i
INNER join LinkInter link on link.InterRef = i.InterRef
INNER join Documents d on d.DocRef = link.DocRef
where d.CustRef = 'Cust1' AND email is not NULL and email <> '' ORDER by date DESC LIMIT 1;
SELECT distinct i.mobilenb as lastmobileKnown, d.CustRef
FROM Inter i
INNER join LinkInter link on link.InterRef = i.InterRef
INNER join Documents d on d.DocRef = link.DocRef
where d.CustRef = 'Cust1' AND mobilenb is not NULL and mobilenb <> '' ORDER by date DESC LIMIT 1;
Related
I use PostgreSQL 13.3
I'm trying to think how I can make include/exclude in query at the same time
I have include_system_ids [1,5] and exclude_system_ids [3]
There's one big table - records
system_records table
record
system_id
1
1
1
5
1
3
2
1
2
5
If a record contains an exclusive identifier, then it should not be included in the final selection. I had some several tries, but I didn't get a necessary result
Awaiting result: record with id 2
Fact result: 1, 2
My variants
select r.id from records r
left join (select record_id from system_records
where system_id in (1,5)
) include_ids on r.id = include_ids
left join (select record_id from system_records
where system_id not in (3)
) exclude_ids on r.id = exclude_ids.id
Honestly, I don't understand how I can do it((
Is there anyone who can help me
Maybe this query could be a solution (result here)
with x as (select record,string_agg(system_id::varchar,',') as sys_id from records group by record)
select records.*
from records,x
where records.record = x.record
and x.sys_id = '1,5'
We currently have a users table with a one-to-many relationship on a table called steps. Each user can have either four steps or seven steps. The steps table schema is as follows:
id | user_id | order | status
-----------------------------
# | # |1-7/1-4| 0 or 1
I am trying to query all of the users who have a status of 1 on all of their steps. So if they have either 4 or 7 steps, they must all have a status of 1.
I tried a join with a check on step 4 (since a step cannot be complete without the previous one being complete as well) but this has issues if someone with 7 steps completed step 4 but not 7.
select u.first_name, u.last_name, u.email, date(s.updated_at) as completed_date
from users u
join steps s on u.id = s.user_id
where s.order = 4 and s.status = 1;
The bool_and aggregate function should help you to identify the users with all their steps at status = 1 whatever the number of steps.
Then the array_agg aggregate function can help to find the updated_at date associated to the last step for each user by ordering the dates according to order DESC and selecting the first value in the resulting array [1] :
SELECT u.first_name, u.last_name, u.email
, s.completed_date
FROM users u
INNER JOIN
( SELECT user_id
, (array_agg(updated_at ORDER BY order DESC))[1] :: date as completed_date
FROM steps
GROUP BY user_id
HAVING bool_and(status :: boolean) -- filter the users with all their steps status = 1
) AS s
ON u.id = s.user_id
There are many similar questions which I've learned from, but my result set isn't returning the expected results.
My Objective:
Build a query that will return a result set containing all rows in table demo1 with user_id = "admin", and the only row of table demo2 with user_id = "admin". Each row in demo2 has a unique user_id so there's always only one row with "admin" as user_id.
However, I don't want demo2 data to wastefully repeat on every subsequent row of demo1. I only want the first row of the result set to contain demo2 data as non-null values. Null values for demo2 columns should only be returned for rows 2+ in the result set.
Current Status:
Right now my query is returning the appropriate columns (all demo1 and all demo2) but
all the data returned from demo2 is null.
Demo1:
id user_id product quantity warehouse
1 admin phone 3 A
2 admin desk 1 D
3 k45 chair 5 B
Demo2:
id user_id employee job country
1 admin james tech usa
2 c39 cindy tech spain
Query:
SELECT *
from demo1
left join (SELECT * FROM demo2 WHERE demo2.user_id = 'X' LIMIT 1) X
on (demo1.user_id = x.user_id)
WHERE demo1.user_id = 'admin'
Rationale:
The subquery's LIMIT 1 was my attempt to retrieve demo2 values for row 1 only, thinking the rest would be null. Instead, all values are null.
Current Result:
id user_id product quantity warehouse id employee job country
1 admin phone 3 A null null null null
2 admin desk 1 D null null null null
Desired Result:
id user_id product quantity warehouse id employee job country
1 admin phone 3 A 1 james tech usa
2 admin desk 1 D null null null null
I've tried substituting left join for left inner join, right join, full join, but nothing returns the desired result.
Your join is going to bring through ANY records that satisfies the join condition for your two tables. There is no changing that.
But you could suppress subsequent records in your result set from displaying the matching demo2 record that satisfied the join condition AFTER it's joined:
SELECT demo1.id ,
demo1.user_id,
demo1.product,
demo1.quantity,
demo1.warehouse
CASE WHEN ROW_NUMBER() OVER (PARTITION BY demo1.user_id ORDER BY demo1.id) = 1 THEN demo2.id END as demo2_id,
CASE WHEN ROW_NUMBER() OVER (PARTITION BY demo1.user_id ORDER BY demo1.id) = 1 THEN demo2.employee END AS demo2_employee,
CASE WHEN ROW_NUMBER() OVER (PARTITION BY demo1.user_id ORDER BY demo1.id) = 1 THEN demo2.job END as demo2_job,
CASE WHEN ROW_NUMBER() OVER (PARTITION BY demo1.user_id ORDER BY demo1.id) = 1 THEN demo2.country END as demo2_country
from demo1
left join demo2
on demo1.user_id = demo2.user_id
AND demo2.user_id = 'X'
WHERE demo1.user_id = 'admin'
That's just a quick rewrite of your original sql with the addition CASE expressions included.
That being said, this sql will produce no results for demo2 since the demo2.user_id can't satisfy both conditions in this query:
The join condition demo1.user_id = demo2.user_id with the where predicate of demo1.user_id = 'admin'
Also hold the value X.
It's either admin and satisfies your first join condition, but fails your second. Or it's X and satisfies your second condition, but nor your first.
Here is another nice approach:
sqlfiddle
I need to write a query on below table to fetch the records only when the same email and name is shared by more than 1 member. In below example, I need resultset as
100 a#a.com nameA
300 a#a.com nameA
Table
Member email name
100 a#a.com nameA
100 a#a.com nameA
300 a#a.com nameA
200 b#b.com nameB
I doubt you have typo and you mean 100 instead of 200 in your expected result. If so, then there is one way:
with your_table(Member, email , name ) as (
select 100,'a#a.com','nameA' union all
select 100,'a#a.com','nameA' union all
select 300,'a#a.com','nameA' union all
select 200,'b#b.com','nameB'
)
-- below is actual query:
select distinct your_table.*
from your_table
inner join (
select email , name from your_table
group by email , name
having count(distinct Member) > 1
) t
on your_table.email = t.email and your_table.name = t.name
I need a specific SQL query to select last 10 conversations for user inbox.
Inbox shows only conversations(threads) with every user - it selects the last message from the conversation and shows it in inbox.
Edited.
Expecting result: to extract latest message from each of 10 latest conversations. Facebook shows latest conversations in the same way
And one more question. How to make a pagination to show next 10 latest messages from previous latest conversations in the next page?
Private messages in the database looks like:
| id | user_id | recipient_id | text
| 1 | 2 | 3 | Hi John!
| 2 | 3 | 2 | Hi Tom!
| 3 | 2 | 3 | How are you?
| 4 | 3 | 2 | Thanks, good! You?
As per my understanding, you need to get the latest message of the conversation on per-user basis (of the last 10 latest conversations)
Update: I have modified the query to get the latest_conversation_message_id for every user conversation
The below query gets the details for user_id = 2, you can modify, users.id = 2 to get it for any other user
SQLFiddle, hope this solves your purpose
SELECT
user_id,
users.name,
users2.name as sent_from_or_sent_to,
subquery.text as latest_message_of_conversation
FROM
users
JOIN
(
SELECT
text,
row_number() OVER ( PARTITION BY user_id + recipient_id ORDER BY id DESC) AS row_num,
user_id,
recipient_id,
id
FROM
private_messages
GROUP BY
id,
recipient_id,
user_id,
text
) AS subquery ON ( ( subquery.user_id = users.id OR subquery.recipient_id = users.id) AND row_num = 1 )
JOIN users as users2 ON ( users2.id = CASE WHEN users.id = subquery.user_id THEN subquery.recipient_id ELSE subquery.user_id END )
WHERE
users.id = 2
ORDER BY
subquery.id DESC
LIMIT 10
Info: The query gets the latest message of every conversation with any other user, If user_id 2, sends a message to user_id 3, that too is displayed, as it indicates the start of a conversation. The latest message of every conversation with any other user is displayed
To solve groupwise-max in pg you can use DISTINCT ON. Like this:
SELECT
DISTINCT ON(pm.user_id)
pm.user_id,
pm.text
FROM
private_messages AS pm
WHERE pm.recipient_id= <my user id>
ORDER BY pm.user_id, pm.id DESC;
http://sqlfiddle.com/#!12/4021d/19
To get the latest X however we will have to use it in a subselect:
SELECT
q.user_id,
q.id,
q.text
FROM
(
SELECT
DISTINCT ON(pm.user_id)
pm.user_id,
pm.id,
pm.text
FROM
private_messages AS pm
WHERE pm.recipient_id=2
ORDER BY pm.user_id, pm.id DESC
) AS q
ORDER BY q.id DESC
LIMIT 10;
http://sqlfiddle.com/#!12/4021d/28
To get both sent and recieved threads:
SELECT
q.user_id,
q.recipient_id,
q.id,
q.text
FROM
(
SELECT
DISTINCT ON(pm.user_id,pm.recipient_id)
pm.user_id,
pm.recipient_id,
pm.id,
pm.text
FROM
private_messages AS pm
WHERE pm.recipient_id=2 OR pm.user_id=2
ORDER BY pm.user_id,pm.recipient_id, pm.id DESC
) AS q
ORDER BY q.id DESC
LIMIT 10;
http://sqlfiddle.com/#!12/4021d/42
Paste it after your WHERE clause
ORDER BY "ColumnName" [ASC, DESC]
UNION Description at W3Schools it combines the result of this 2 statements.
SELECT "ColumnName" FROM "TableName"
UNION
SELECT "ColumnName" FROM "TableName"
For large data sets I think you might like to try running the two statements and then consolidating the results, as an index scan on (user_id and id) or (recipient_id and id) ought to be very efficient at getting the 10 most recent conversations of each type.
with sent_messages as (
SELECT *
FROM private_messages
WHERE user_id = my_user_id
ORDER BY id desc
LIMIT 10),
received_messages as ( SELECT *
FROM private_messages
WHERE recipient_id = my_user_id
ORDER BY id desc
LIMIT 10),
all_messages as (
select *
from sent_messages
union all
select *
from received_messages)
select *
from all_messages
order by id desc
limit 10
Edit: Actually another query worth trying might be:
select *
from private_messages
where id in (
select id
from (
SELECT id
FROM private_messages
WHERE user_id = my_user_id
ORDER BY id desc
LIMIT 10
union all
SELECT id
FROM private_messages
WHERE recipient_id = my_user_id
ORDER BY id desc
LIMIT 10) all_ids
order by id desc
limit 10) last_ten_ids
order by id desc
This might be better in 9.2+, where the indexes alone could be used to get the id's, or in cases where the most recent number to retrieve is very large. Still a bit unclear on that though. If in doubt I'd go for the former version.