In my db i have long string with which length is not fixed
e.g.
4504065148...Leaving VENDOR on 01-01-1990;Please allow 7 - 10 days
Case escalated, pending ETA
Tentatively Leaving XYZ on 01-01-1990. Please allow 3 - 5 days.
so now I want to extract the number after allow key word i.e.7 or 3 using tablue
I had tried my work around but unable to find any solution
I'm assuming the number after allow is always a single digit.
if find([Column],'allow')>0 then mid([Column],find([Column],'allow')+6,1) end
[Column] is your column name. So if "allow" is present, then extract the next character after "allow ".
Related
i want to select cases with particular first 3 characters.
for example cases with first 3 characters containing "I22".
the length of whole value can vary. e,g "I228" or "I2279" but they have common first three characters "I22"
i usually use compute variable_name= "I228".
but this is tedious as i have to enter all variation of "I22" e.g "I228", "I229" and so on..
it would be much easier if i can just select cases based upon same first 3 characters
you can use the char.cubstr function to find out what the first three characters are in your string variable. For example:
if char.substr(variable_name,1,3)="I22" keep_this=1.
or:
select cases if char.substr(variable_name,1,3)="I22".
I have to extract a value from string and I am working on cognos application that doesn't support regex. It has some built in functions like substring and position
My string is similar to
/content/folder[#name='ab_Salary Reports']/folder[#name='INT Salary Reports']/folder[#name='INT Sal Sche']/jobDefinition[#name='Salary Rep R025']
And I have to extract Salary Rep R025, ie. the last name value.
Static substring will not work because string is variable.
Use the position function to locate the starting and ending point of your target substring. Try
position('/jobDefinition', [pathstring])
combined with substring:
substring( [pathstring], position('/jobDefinition', [pathstring]) + 22, length([pathstring]) - position('/jobDefinition', [pathstring]) + 22)
This will start 22 characters after where it finds /jobDefinition, meaning it will start just past '/jobDefinition[#name='', and will proceed for the remaining length of the string, determined by subtracting the starting point from the full length.
You may need to adjust by +1 or -1 in order to include or exclude your quotes.
Also note that this is using Report Studio functions. The source for Cognos reports is queries on tables, so you may have native functions available depending on your source. For example, most of the reports I work with come out of an Oracle database, so I can use oracle string functions instead of Report Studio functions. They work better, and are processed on the database side rather than on the Cognos Dispatcher, which is always faster.
A web form collects data on students in a band organization at school. The form data is fed into a google sheet that then populates a merge template and the merged forms are emailed to the recipient. A parent needs to print, sign and turn in the forms. There are hundreds of kids in this band and at registration time when the forms are turned in it is easier to sort all the papers in the stack if you have a short sort number in the corner... Volunteer kids don't apply alphabetization well. I'm trying to create a formula that will give me that sorting number to merge onto the header of each page of the PDF they receive after submitting the form. I want it based on last name and then first name and be able to create that number (in the google sheet) on the fly because the merging happens almost instantly when the user submits the form. Hence, an excel type formula is desired that will result in a number representing the kids name. I'd like for each number to be unique but some names are the same for the first few letters, also some names are only 2 characters long. I tried making A=10, B=11, z=35 etc. (so all are 2 digits) So, using only the first 3 characters, Bob Jones would = 192423112411 - hardly easy to sort the paper at a glance and it doesn't really differentiate between Bob Janes either. 4 digits is preferable. I also looked at =code() formula and it came out with long numbers too. Any advice is appreciated. Thanks!
Side note: What method do spreadsheets use to sort text? Do they weight the characters or what? Before I got the automerge thing to work I assigned each kid in the list a number higher than the one below and lower than above (on the sheet), then did the merge.
One option is to:
sort the name list alphabetically
add a sort number column, and put a =TEXT(row(),"0000") formula to generate a unique ID
on the merge spreadsheet, use a VLOOKUP function to retrieve the unique ID for that specific name.
First off, that wall of text was kind of hard to read through. Please try and do a little formatting so the people trying to help you can easily follow what you're trying to convey.
Personally I would suggest a hyphenated system. First initial of last name converted to a number, followed by a hyphen, followed by the first two letters of their first name converted to numbers.
Bob Jones becomes 11-1956 assuming you differentiate between upper and lower case, or 11-1924 if you convert everything to upper case, which I guess makes more sense.
You could use this VBA function to convert names to a system like that:
Function ConvertToIndex(strInput As String) As String
Dim strLast As String
Dim arrName() As String
Dim strFirst1 As String
Dim strFirst2 As String
arrName = Split(strInput, " ")
strLast = Mid(arrName(1), 1, 1)
strFirst1 = Mid(arrName(0), 1, 1)
strFirst2 = Mid(arrName(0), 2, 1)
ConvertToIndex = Asc(UCase(strLast)) - 55 & "-" & Asc(UCase(strFirst1)) - 55 & Asc(UCase(strFirst2)) - 55
'MsgBox ConvertToIndex
End Function
Thank you Tim, Nutsch and Mad Tech for your responses. I appreciate your input. Sorry the paragraph was so long, I get wordy. Because the members get their merged PDF sheet immediately after submitting I need the number to be based on the name as soon as it's entered, not after the fact; so I was looking for a formula that would reside in the sheet. Interesting VBA function too though. I'll settle for numbering them afterwards, maybe when the sheets are turned in. By then I'll know all who are in the band and can assign numbers like before. Thanks again!
I've prepared a macro in Notepad++ to transform a ldif file in a csv file with a few fields. Everything is OK but I have a final problem: I have to have 2 fields with a specific length and in this moment I cannot ensure that length because in the source file they are not coming so
For instance, I generate this line:
12345,namenamename,123456
And I have to ensure that the 2nd and 3rd fields have 30 (filling with spaces at right side) and 9 (filling with zeros at left) characters, so in this case I should generate:
12345,namenamename ,000123456
I haven't found how Notepad++ could match a pattern in order to add spaces/zeros, so I have though in to add 1 space/zero to the proper field and repeat this step so many times as needed to ensure the lengths (this is, 29 and 8, because they cannot come empty) and search with the length in the regex (for instance: \d{1,8} for the third field)
My question is: can I repeat only one step of the macro several times (and the rest of the macro only 1 repetition)?
I've read the wiki related to this point (http://sourceforge.net/apps/mediawiki/notepad-plus/index.php?title=Editing_Configuration_Files#.3CMacros.3E) and I don't found anything neither
If not possible, how could be a good solution? Create another 2 different macros and after execute the main one, execute this new 2 macros several times?
Thanks in advance!
A two pass solution with Notepad++ is possible. Find a pair of characters or two short sequence of characters that never occurs in your data file. I will use =#<= and =>#= here.
First pass, generate or convert the input text into the form 12345,=#<=namenamename______________________________,000000000123456=>#=. Ie add 30 spaces after the name and nine zeroes before the number (underscores used here just to make things clearer).
Second pass, do a regular expression search for =#<=(.{30})_*,0*(\d{9})=>#= and replace with \1,\2.
I have just suggested a similar solution in special timestamp format of csv
I'm trying to set up an error check between two systems and need to compare week numbers in different formats. One system produces week numbers in a text format e.g "8-15, 18, 31-32" and the other produces discrete values. How would I see whether a value e.g 16 fell within a multiple range like the one above?
It's part of a bigger issue where I'm checking a reference number, day, time and week number (e.g XXX111 Weds 9:00 9) in one system against the output of another system (e.g XXX111 Wed 9:00 7:11, 13, 16, 52-63 or XXX111 Thu 9:00 5, 6, 11-16). Despite lots of searching I've hit a wall with the bit above so any help would be greatly appreciated.
I'd rather not use VBA if possible. Thanks in advance for your wisdom.
Assumed:
7:11 should be 7-11
63 should be 53
A number not part of a range (eg 18) is not a problem
Ranges are in Text format
I hope the following helps or at least is ‘a step in the right direction’:
A Parse the components
Eg for 8-15, 18, 31-32, paste into a cell (say A1) and Data > Data Tools - Text to Columns > Delimited > Next > check Comma, Space and Treat consecutive delimiters as one > Next > Select Columns as required > select Text for each > Finish
May be easier to deal with a single column so select data, Copy > Select A2 > Paste Special > Transpose > OK and Delete contents of Row1.
B Add your search value (16) into B1
C Copy the formula below into B2 and copy down as required:
=AND(B$1>=VALUE(LEFT($A2,SEARCH("-",$A2)-1)),B$1<=VALUE(RIGHT($A2,LEN($A2)-SEARCH("-",$A2)))))
The result should be TRUE where the search value is within or on either bound of the discrete range:
The formula uses the hyphen to ‘recognise’ a discrete range. SEARCH looks for where it is positioned (because there could be one or two characters either side of it). LEFT and RIGHT are for the lower and upper bounds (in the case of RIGHT used in conjunction with LEN to address whether the upper bound is one or two characters). VALUE is required to convert the Text into something that can be equated to the search value. AND is for the process to consider both bounds in determining whether ‘in range’.
“I’d rather not use VBA if possible” – but might be advisable!
However, use of some fixed references ($) should make it a little easier than otherwise with standard formulae only because the given discrete ranges (which may be appended in ColumnA) can be queried for various search values by copying the formulae across to the right/down as required and entering (as Number format) further search values in Row1.