I want to obtain the records that the "FECHA_FIN" field is greater than or equal to today's date.
this is an example of my data:
but with this query:
db.getCollection('susp_programadas').find( {"FECHA_FIN":{ $gte: new Date("YYYY-mm-dd") }} )
I do not get results, what am I doing wrong? Thank you
You can convert the date to an ISO date and query that way. Since you stored the date as a string mongo has no idea how to query it against an ISO date without conversion.
If you stored your date in mongo as the default ISO date then you could have easily done this:
db.getCollection('susp_programadas').find({"FECHA_FIN":{$gte: new Date()}})
So this is how you can do it now:
db.getCollection('susp_programadas').aggregate([
{
$project: {
date: { $dateFromString: { dateString: '$FECHA_FIN' }}
}
},
{ $match: { date: { $gte: new Date() }}}
])
You can use the $dateFromString in an aggregate query with a $match to get the results you want. Note that $dateFromString is only available in MongoDB version 3.6 and up.
If there is no way to convert your data to ISODate or upgrade your DB you could also consider another solution which via $where:
db.getCollection('susp_programadas').find({
$where: function(){
return new Date(this.FECHA_FIN) > Date.now()
}
})
However that solution suffers from the fact that $where can not use indexes so have that in mind.
Related
I am having trouble converting "7/26/2020 18:34:25" into any date format from which Mongo can run aggregate operation.
The date in the Mongo is stored as string.
I have tried "$toDate", "$convert" and "$dateToString".
You need to use $dateFromString
$project: {
date: {
$dateFromString: {
dateString: '$dateFieldName',
format: '%m/%d/%Y %H:%M:%S'
}
}
}
playground
Try using Moment Library for converting you date
In your case this code can help you:
moment('7/26/2020 18:34:25').toDate();
You can test this code on browser side on this page
enter link description here
I can find an item with this search:
db.item.find({"startdate":{$gte: 1485521569000 }})
The date seems to correspond to
> new Date(1485521569000)
ISODate("2017-01-27T12:52:49Z")
But if I search
db.item.find({"startdate":{"$gte" : ISODate("2017-01-01T00:00:00Z")}})
I don't get any results. What am I doing wrong?
PS
the only way I found is
db.item.find({"startdate":{"$gte" : (new Date("2017-01-01")).getTime()}})
is that right or there is a better way?
Below one will work.
db.getCollection('test').find({
"key": {
"$gte": (ISODate("2017-01-01")).getTime()
}
})
Reason:
You have your data is in int64 or long
In the new Date query, you are converting date to time which return int. So get performs integer comparison.
In ISODate you are passing a date, it doesn't convert date to integer i.e milliseconds. So if you convert, both will work.
new Date() returns the current date as a Date object. The mongo shell wraps the Date object with the ISODate helper
var d = ISODate("2017-01-01")
print(d); //Sun Jan 01 2017 05:30:00 GMT+0530 (IST)
Hence, the comparison fails.
If i understand, you have timestamp in startdate field,
This is the option if helps you, Can do it with aggregate() function, using $toDate,
$toDate convert timestamp to ISO date
db.collection.aggregate([
{
$match: {
$expr: {
$gte: [
{
$toDate: "$startdate"
},
ISODate("2017-01-27T12:52:49.000Z")
]
}
}
}
])
Playground: https://mongoplayground.net/p/H7SFHsgOcCu
I need to query Mongo using the FIND function, I can't use the aggregate function.
My documents are like this:
{
"name": "Tom",
"priDate":2010-04-11T00:00:00.000Z
}
The query I would like to make is:
Find all documents where ("priDate" + 1 year) is lte today.
Is it possible to do this without using an aggregation query? I can't use the field value in find ..
The query that I would need, I think, would be like this one I made:
db.system.profile.find({
"priDate" :
{
$gte: new Date(ITSELF + 1 year??) ,
$lt : new Date()
}
})
Can you help me?
many thanks, i'm going crazy :)
see if this works:
db.collection.find(
{
$expr: {
$lte: ['$priDate', { $subtract: ['$$NOW', 31536000000] }]
}
}
)
https://mongoplayground.net/p/QJ3BbHTQlgh
Adding "1 year" can be be difficult because of leap years or daylight-saving-times.
I suggest moment.js, then solution would be
db.system.profile.find(
{
priDate: {
$gte: moment().add(1, "year").toDate(),
$lt: moment().toDate()
}
}
)
However priDate >= "today + 1 year" AND priDate < "today" is not possible. Change the condition according to your needs.
MongoDB stores dates as milliseconds since epoch, so you can advance a date one year by adding the number of milliseconds in a year using $add inside $expr, then test with $lte:
db.system.profile.find({$expr:{$lte:[{$add:["$priDate",31536000000]},new ISODate()]}})
Note that this will be off by a day around leap year unless you adjust the number of milliseconds for that.
You expressed the constraint that you cannot use aggregate, but with $expr in Mongo 3.6 onwards, you can use any and all aggregation operators in a find query as well.
https://docs.mongodb.com/manual/reference/operator/query/expr/#definition
I have a collection in which each document has a time field with value stored as similar to "21-Dec-2017".
I want to convert this to ISODate using projection.
My Query:
db.getCollection('orders').aggregate([{
$project:{time : {$add : new Date("$time")}}
}])
But this is returning me ISODate("1970-01-01T00:00:00.000Z") always.
you can try this,
db.getCollection('orders').aggregate([{
$project: {
time: {
$dateToString: {
format: "%d-%m-%G",
date: new Date("$time")
}
}
}
}
])
there is no any string function to get months name eg.Jan,Feb..Dec.
but you can refer https://docs.mongodb.com/manual/reference/operator/aggregation/dateToString/
to more information.
There is no problem in this ISODate("1970-01-01T00:00:00.000Z") format.
you should store date in ISO format but change format on client side according to you.
Basically you want to show date in dd/mm/yy format.
You can use http://momentjs.com/ to show date according to you.
I have a collection, Plans. I want to find everything within the range of one month. Here is a sample of what the data could look like:
{
"_id": "someid",
"dateStart": ISODate("2015-03-01T00:00:00Z"),
"dateEnd": ISODate("2015-03-31T00:00:00Z"),
"items": [
"someotherid"
]
}
How can I find the Plan such that today's date is between dateStart and dateEnd?
To find a Plan such that today's date is between the dateStart and dateEnd fields, create a date object that holds the current date then use the $lt and $gt query operators on the date fields to query documents where today's date falls between the two fields:
currentDate = new Date();
Plans.find({
dateStart: { $lt: currentDate },
dateEnd: { $gt: currentDate }
});
date1 = new Date('3/1/15');
date2 = new Date('4/1/15');
Plans.find({
startDate: {$gte: date1},
endDate: {$lt: date2}
});
New Date objects initialize to 00:00:000 so you can use that to your advantage here. Also note that "less than 4/1" is equivalent to "less than or equal to midnight on 3/31" - but the former is much easier to write.
Also note that moment is a super handy utility for doing manipulations like this. For example: moment().endOf('month').toDate()
To add the package just do:
$ meteor add momentjs:moment