Crystal Reports - Remove Carriage Returns - crystal-reports

I am writing a report for my company right now and am running into issues with one data set in particular. Our accounting team puts unnecessary (as I see it) carriage returns when typing in data in one of our MISC_COMMENT fields.
Example data:
2 Returns
For warping
Cost = $1
RGA# 123
This comes out on the report as such... The report requester has asked that the data be as follows:
2 Returns For Warping Cost = $1 RGA 123
Is there anyway to strip out the carriage returns? Data will vary in characters and length. Not sure if a substring is still applicable then?
Thanks for the help!

Use the replace function to replace one or both of Chr(10) and Chr(13) depending on whether one or both exist inside your text.
Replace(Replace(MISC_COMMENT, Chr(13), " "), Chr(10), " ")

Related

Postgresql: How to replace multiple substrings in a string and with regexp

Postgresql 9.4: 1 column in 1 table is a string of text representing a route of flight for an aircraft.
The complete field consists of "Fixes" and "Routes" up to 80
characters in total length.
Routes and Fixes can be either 3 or 5 characters in length.
Routes and Fixes can have the same name.
There may be zero, one, or two Routes
Routes are followed by a single non-zero digit or a hash.
Routes and Fixes can be preceded or followed by a "+" or "*".
The field may contain CR/LF or double-triple spaces which should remain.
Each schema contains 6-20000s fields in this table
There are nearly 1800 Route names, but generally only 40-80 per schema
Examples:
"KIND ROCKY1 STL BUM OATHE CLASH5 KDEN"
"+MEARZ7 OKK+
KIND OKK FWA MIZAR3 KDTW"
"KIND OOM OOM5 WEGEE PXV J131 LIT BYP5 KDFW"
"KIND MEARZ# OKK ECK YEE YXI N171B VALIEE***EGSS"
The task is to clean up the lazy use of the hash instead of a digit and to update the Route versions (the trailing numbers). I.e. replace-in-place the Route with the correct digit rather than the # or what might be a wrong number. So every instance of "MEARZ7" or "MEARZ#" becomes "MEARZ9" and "OOM5" becomes "OOM6" but "OOM " stays "OOM ".
Currently I have been testing this:
UPDATE target SET detail =
CASE WHEN POSITION('CLASH' in detail) > 0
AND SUBSTRING(detail,POSITION('CLASH' in detail)+5,1) != ' '
THEN REGEXP_REPLACE (detail, 'CLASH.', 'CLASH5')
WHEN POSITION('MEARZ' in detail) > 0
AND SUBSTRING(detail,POSITION('MEARZ' in detail)+5,1) != ' '
THEN REGEXP_REPLACE (detail, 'MEARZ.', 'MEARZ9')
WHEN POSITION('OOM' in detail) > 0
AND SUBSTRING(detail,POSITION('OOM' in detail)+3,1) != ' '
THEN REGEXP_REPLACE (detail, 'OOM.', 'OOM6')
WHEN POSITION('ROCKY' in fsrtedtail) > 0
AND SUBSTRING(detail,POSITION('ROCKY' in detail)+5,1) != ' '
THEN REGEXP_REPLACE (detail, 'ROCKY.', 'ROCKY1')
ELSE detail END;
My logic was to:
Find the Route name.
Check if it's followed by a space.
If not, replace it with the correct Route+digit
I hadn't yet attempted to avoid "+" or "* ". I was thinking I could first replace the "#" with a number, then update the Route+digit as to not worry about the # and this would eliminate the need to look for the "+" or "* ". Then I could just look for a trailing space.
The second Route (in order of the WHEN statements) does not get updated so I guess am barking up the wrong tree.
They other big obstacle is there can be 80 or more Routes in a schema so if I have to nest a statement, it's gonna be huge.
I have tried array_to_string(array_replace(string_to_array( but it leaves behind double quotes, commas, and curly brackets so doesn't seem feasible.
At this point I'm thinking a function is the way to go, but I don't know where to start.

Azure Data Factory - Dynamic Skip Lines Expression

I am attempting to import a CSV into ADF however the file header is not the first line of the file. It is dynamic therefore I need to match it based on the first column (e.g "TestID,") which is a string.
Example Data (Header is on Line 4)
Date:,01/05/2022
Time:,00:30:25
Test Temperature:,25C
TestID,StartTime,EndTime,Result
TID12345-01,00:45:30,00:47:12,Pass
TID12345-02,00:46:50,00:49:12,Fail
TID12345-03,00:48:20,00:52:17,Pass
TID12345-04,00:49:12,00:49:45,Pass
TID12345-05,00:50:22,00:51:55,Fail
I found this article which addresses this issue however I am struggling to rewrite the expression from using an integer to using a string.
https://kromerbigdata.com/2019/09/28/adf-dynamic-skip-lines-find-data-with-variable-headers
First Expression
iif(!isNull(toInteger(left(toString(byPosition(1)),1))),toInteger(rownum),toInteger(0))
As the article states, this expression looks at the first character of each row and if it is an integer it will return the row number (rownum)
How do I perform this action for a string (e.g "TestID,")
Many Thanks
Jonny
I think you want to consider first line that starts with string as your header and preceding lines that starts with numbers should not be considered as header. You can use isNan function to check if the first character is Not a number(i.e. string) as seen in the below modified expression:
iif(isNan(left(toString(byPosition(1)),1))
,toInteger(rownum)
,toInteger(0)
)
Following is a breakdown of the above expression:
left(toString(byPosition(1)),1): gets first character fron left side of the first column.
isNan: checks if the character is "not a number".
iif: not a number, true then return rownum, false then return 0.
Or you can also use functions like isInteger() to check if the first character is an integer or not and perform actions accordingly.
Later on as explained in the cited article you need to find minimum rownum to skip.
Hope it helps.

Please explain what the sentence REPLACE(tablecolumn,CHR(13),'') really mean in db2 (Native SQL)

Please help me in understanding what does the below code really mean?
CASE WHEN REPLACE(tablename.columnname,CHR(13),'') <> ''
THEN
REPLACE(tablename.columnname,CHR(13), '')
ELSE
REPLACE(tablename.columnname,CHR(13),'')
For your reference:
tablename.columname = mara.matnr
mara is a table and matnr is a field name in the table Mara.
CHR(13) is a carriage return, sometimes seen in text fields. I've worked on a number of solutions where I had to strip those out of strings so that when I displayed them on a reporting front-end (such as Excel), they didn't go to a new row. That is essentially what this code is doing - removing carriage returns by replacing them with a zero-length string.
The CASE expression you reference above is essentially useless, since it is using the same expression in both the THEN and ELSE. The entire script could be rewritten as:
REPLACE(tablename.columnname,CHR(13),'')

T-SQL trim not working - let spaces on the result

I have a trim function that apply ltrim and rtrim
CREATE FUNCTION dbo.TRIM(#string VARCHAR(MAX))
RETURNS VARCHAR(MAX)
BEGIN
RETURN LTRIM(RTRIM(#string))
END
GO
I do the following query:
SELECT distinct dbo.trim([subject]) as subject
FROM [DISTR]
The result has rows like:
"A"
"A "
"B"
...
I thought that thoose chars maybe weren't spaces but when I got the ascii code, it returns 32 which is the code for space.
My only guess is that I had to change the collaction of the database to: SQL_Latin1_General_CP1_CI_AI
Can that be the problem? Any ideas?
Thanks
Maybe your field contains more than spaces. Remember than " " could be a space, tab, and many other "blank" chars. It's possible to match it using ASCII or building a CLR implementation of trim that uses regular expressions

How do I insert a lot of whitespace in Perl?

I need to buff out a line of text with a varying but large number of whitespace. I can figure out a janky way of doing a loop and adding whitespace to $foo, then splicing that into the text, but it is not an elegant solution.
I need a little more info. Are you just appending to some text or do you need to insert it?
Either way, one easy way to get repetition is perl's 'x' operator, eg.
" " x 20000
will give you 20K spaces.
If have an existing string ($s say) and you want to pad it out to 20K, try
$s .= (" " x (20000 - length($s)))
BTW, Perl has an extensive set of operators - well worth studying if you're serious about the language.
UPDATE: The question as originally asked (it has since been edited) asked about 20K spaces, not a "lot of whitespace", hence the 20K in my answer.
If you always want the string to be a certain length you can use sprintf:
For example, to pad out $var with white space so it 20,000 characters long use:
$var = sprintf("%-20000s",$var);
use the 'x' operator:
print ' ' x 20000;