There are two entities:
#Entity(name = "Account")
#Table(name = "accounts")
#NamedQuery(name = "findAccountByExtId",
query = "SELECT a " +
"FROM Account a " +
"WHERE a.accountDetails.extId = :extId " +
"AND a.deletedAt IS NULL")
public class Account extends DeletableAudit {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue
private UUID id;
#OneToOne(mappedBy = "parent", fetch = FetchType.EAGER, cascade = CascadeType.ALL)
private AccountDetails accountDetails;
and
#Entity(name = "AccountDetails")
#Table(name = "account_details")
public class AccountDetails extends DeletableAudit {
private static final long serialVersionUID = -1L;
#Id
#GeneratedValue
private Integer accDetId;
#OneToOne
#JoinColumn(name = "fk_account")
private Account parent;
#Column
private String extId;
Goal is to return Account and AccountDetials via the external ID. The program won't run due to error:
Failed to create query for method public abstract p.j.o.d.d.Account p.j.o.d.r.AccountRepository.findAccountByExtId(java.lang.String)! No property extId found for type Account!
Already tried different variations of #OneToOne mapping and query, however nothing seems to work.
Second question is whether it is possible to have AccountDetails reference the same ID as Account. I'd like to get rid of accDetId and just store these entities with the same UUID of their parent.
Related
I have an issue trying to generate multiple relationship in JPA with three Entities.
Order
Product
Modifier
I have an Entity to handle the relationship many to many.
OrderProducts (order_id and product_id)
Contains the relationship of one order can have multiple products
OrderDetails (order_products_id and modifier_id)
Contains the id of the previous relationship Order-Products and the Id of the modifier which is a set of multiple values that can affect the price of the product.
Not quite sure how to handle this kind of relationship in JPA as I'm new to it.
You need a join entity with a composite key. You will need to research it further.
Your entities:
#Entity
#Table(name = "ordertable")
#Data
public class Order {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#OneToMany(mappedBy = "order")
#EqualsAndHashCode.Exclude
private Set<OrderProductModifier> products;
}
#Entity
#Table(name = "product")
#Data
public class Product {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#EqualsAndHashCode.Exclude
private BigDecimal unitPrice;
}
#Entity
#Table(name = "modifier")
#Data
public class Modifier {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#EqualsAndHashCode.Exclude
private BigDecimal modifier;
}
And the entity that ties it all together will need to have the foreign keys for each of the above entities, as you have noted.
#Entity
#Table(name = "orderproductmodifier")
#Data
public class OrderProductModifier {
#EmbeddedId
private OrderProductModifierId id;
#MapsId("orderId")
#ManyToOne
#EqualsAndHashCode.Exclude
#ToString.Exclude
private Order order;
#MapsId("productId")
#ManyToOne
#EqualsAndHashCode.Exclude
private Product product;
#MapsId("modifierId")
#ManyToOne
#EqualsAndHashCode.Exclude
private Modifier modifier;
}
#SuppressWarnings("serial")
#Embeddable
#Data
public class OrderProductModifierId implements Serializable {
private Long orderId;
private Long productId;
private Long modifierId;
}
This is pretty simple to use:
private void run() {
EntityManagerFactory factory = Persistence.createEntityManagerFactory("UsersDB");
EntityManager em = factory.createEntityManager();
em.getTransaction().begin();
Product product = new Product();
product.setUnitPrice(BigDecimal.TEN);
em.persist(product);
Modifier modifier = new Modifier();
modifier.setModifier(new BigDecimal(".90"));
em.persist(modifier);
Order order = new Order();
em.persist(order);
OrderProductModifier opm = new OrderProductModifier();
opm.setId(new OrderProductModifierId());
opm.setOrder(order);
opm.setProduct(product);
opm.setModifier(modifier);
em.persist(opm);
em.getTransaction().commit();
em.clear();
Order o = em.createQuery("select o from Order o join fetch o.products where o.id = 1", Order.class).getSingleResult();
System.out.println("Order for " + o.getProducts());
System.out.println("Order cost " + o.getProducts().stream().map(p->p.getProduct().getUnitPrice().multiply(p.getModifier().getModifier()).doubleValue()).collect(Collectors.summingDouble(Double::doubleValue)));
}
The above query could be better, but that will give you something to work on.
I am using JPA with JSF datatable with lazy loading.
Here One car can be owned by many users. So when i logged in to the application i want the cars which is owned by the user logged in(assume it as userId=1).
I have a mapping table "Cars_User" that contains carId and userId columns.
My Entities are like this
My Car Class
#Entity
#Table(name="car")
public class Car implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private String id;
#Transient
private boolean myCar;
#NotNull
#Size(min = 1, max = 50)
public String name;
#OneToMany(cascade = { CascadeType.REFRESH }, fetch = FetchType.LAZY, orphanRemoval = true)
#JoinTable(name = "Cars_User", joinColumns = #JoinColumn(name = "carId"), inverseJoinColumns = #JoinColumn(name = "userId"))
private List<User> carUsers = new ArrayList<User>();
getters ...
setters ...
}
User Class
#Entity(name = "User")
public class User implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private int id;
private String firstName;
private String lastName;
}
I have found one answer for Lists of String collection in this link but how can be achieved in my case.
I wanted to do get all Cars entities in criteria api that contains the logged in user id "userId" in carUsers Lists. can anyone please help?
I found the solution. I have passed the logged in user Object "user" in isMember function. This may help for somebody.
CriteriaBuilder criteriaBuilder = em.getEntityManagerFactory().getCriteriaBuilder();
CriteriaQuery<Car> criteria = criteriaBuilder.createQuery(Car.class);
Root<Car> root = criteria.from(Car.class);
criteria.where(criteriaBuilder.isMember(user, root.get(Car_.carUsers)));
List<Car> cars = em.createQuery(criteria).getResultList();
I have three tables each mapping to one of these entities. The 'assigned' table acts as the relationship between 'users' and 'roles' with a foreign key to each table. How would I map this on my entities so that I can get a Set of EntityRoles from the UserEntity? I can't quite figure out how to make this work. Is this even possible?
#Entity
#Table(name = "users")
public class UserEntity {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name="user_id")
private long id;
#Column(name="user_username")
private String username;
#Column(name="user_password")
private String password;
#Column(name="user_email")
private String email;
//I want to be able to get a set of RoleEntities
#OneToMany(fetch = FetchType.LAZY, mappedBy = "id")
private Set<RoleEntity> roles;
}
#Entity
#Table(name = "assigned")
public class AssignedEntity implements Serializable {
#Id
//#Column(name = "assigned_role")
#ManyToOne(targetEntity = RoleEntity.class, fetch = FetchType.LAZY)
#JoinColumn(name = "fk_role")
private long roleId;
#Id
//#Column(name = "assigned_user")
#ManyToOne(targetEntity = UserEntity.class, fetch = FetchType.LAZY)
#JoinColumn(name = "fk_user")
private long userId;
}
#Entity
#Table(name = "roles")
public class RoleEntity implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name="role_id")
#OneToOne(fetch = FetchType.LAZY, mappedBy="roleId")
private long id;
#Column(name="role_name")
private String name;
}
You are using an incorrect/inconvenient mapping. Always keep things as simply as possible.
#Entity
#Table(name = "users")
public class User {
#Id
#GeneratedValue
private Long id;
#ManyToMany(fetch = FetchType.LAZY)
private List<Role> roles;
}
#Entity
#Table(name = "roles")
public class Role {
#Id
private Long id;
#Column
private String name;
}
A persistent provider will create a (valid) join table for you. You can specify the name of the join table using #JoinTable annotation. Also you will need to think about auto generation values of id for the Role entity: the roles table is something like a reference data table. So, probably, you will need to hardcode the id values.
To get user roles (in the persistent context):
user.getRoles()
I followed by tutorial : http://www.codejava.net/frameworks/hibernate/hibernate-one-to-one-mapping-with-foreign-key-annotations-example
I have following code:
#Entity
#Table(name = DomainConstant.TABLE_USER)
public class User{
#Id
#Column(name = DomainConstant.DOMAIN_USER_ID)
#GeneratedValue
private Long userId;
private UserActivationCode userActivationCode;
///////////////////// CONSTRUCTOR....
/// STANDARD GET AND SET....
#OneToOne(cascade = CascadeType.ALL)
#JoinColumn(name = DomainConstant.DOMAIN_ACTIVATION_LINK_ID)
public UserActivationCode getUserActivationCode() {
return userActivationCode;
}
}
#Entity
#Table(name = DomainConstant.TABLE_USER_ACTIVATON_LINK)
public class UserActivationCode {
#Id
#Column(name = DomainConstant.DOMAIN_ACTIVATION_LINK_ID)
#GeneratedValue
private Long userActivationCodeId;
#Column(name = DomainConstant.DOMAIN_ACTIVATION_DATE)
#Temporal(javax.persistence.TemporalType.DATE)
private Date date;
#Column(name = DomainConstant.DOMAIN_ACTIVATION_CODE)
private String code;
///////////////////// CONSTRUCTOR....
/// STANDARD GET AND SET....
}
When I save the User object it does not make record in UserActivationCode, why?
Like this:
User newUser = new User();
newUser.setUserActivationCode(new UserActivationCode("this is example"));
userDao.save(newUser);
I have record only in user table.
Can you tell me why?
Your problem is that you are mixing access types. In the User entity you have specified #Id on a field (private Long userId) whereas you have defined the join mapping on a property (the getter to UserActivationCode). If you specify the join mapping on the field, it should work as is.
#Entity
#Table(name = DomainConstant.TABLE_USER)
public class User{
#Id
#Column(name = DomainConstant.DOMAIN_USER_ID)
#GeneratedValue
private Long userId;
#OneToOne(cascade = CascadeType.ALL)
#JoinColumn(name = DomainConstant.DOMAIN_ACTIVATION_LINK_ID)
private UserActivationCode userActivationCode;
///////////////////// CONSTRUCTOR....
/// STANDARD GET AND SET....
public UserActivationCode getUserActivationCode() {
return userActivationCode;
}
}
For more information on access and access types, see Access, Java EE 7
I am bit beginner on JPA and need some help on fetching the Many to One relationship in JPA.
I have below entities.
User which stores all user information . User extends Audiatable abstract class which is for holding auidt paramters like last modified date, creation date etc.
I am trying to add another fields as lastUpdatedByUser which should get fetched from lastUpdatedBy for which I amtrying to add Many-One relationship.
But the relation is not working somehow, am I doing something wrong here?
AuditableEntity.java
public abstract class AuditableEntity<T extends Entity<T, ID>, ID> implements Auditable {
private static final long serialVersionUID = 1L;
#Column(name = "cruserid")
private Long createdBy;
#Column(name = "crdate")
#Type(type = JpaConstants.TYPE_LOCAL_DATE_TIME)
private LocalDateTime createdOn;
#Column(name = "chuserid")
private Long lastUpdatedBy;
#Column(name = "chdate")
#Type(type = JpaConstants.TYPE_LOCAL_DATE_TIME)
private LocalDateTime lastUpdatedOn;
#Transient
#ManyToOne(fetch = FetchType.LAZY, targetEntity = User.class)
#JoinColumn(name = "usrId", referencedColumnName = "chuserid")
private User lastUpdatedByUser;
User.java
public class User extends AuditableEntity<User, Long> {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "usrId")
private Long id;
#Column(name = "usrName")
private String name;
#Column(name = "loginame")
private String loginName;
}
Well, you marked the association with #Transient, which means that the field is not persistent and should be ignored by JPA.
And you also seem to have two different fields to store the same information: lastUpdatedBy and lastUpdateByUser. Remove the first one, and map the second one as
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumn(name = "chuserid")
private User lastUpdatedByUser;
This tells that the association is a ManyToOne to the User entity (no need to specify the targetEntity since it's the type of the field), and that this association is materialized by the join column named "chuserid", in the auditable entity's table, and referencing the ID of the User entity (referencedColumnName is only useful when you use composite IDs, or when you reference an entity by a column which is the the ID)