2D Motion vectors - calculate location of object at a given time - swift

I am having problems understanding 2D motion vectors when moving certain objects at a given time. My knowledge of linear algebra is limited and I really don't know the exact search terms to look for, so I wanted to know whether anybody could help me or at least hint me in the right direction.
My problem looks like this:
I have two points, a startPoint, and an endPoint in space. They have each a specific location, denoted as (x_1, x_2) and (y_1, y_2) respectively. Both of these points have a time attached to it, named t_startPoint or t_endPoint, respectively. I now want to find out, for a given currentTime (= basically any point in time that is in between t_startPoint and t_endPoint), where exactly would a new point N be positioned on the connection line between those two points. I know the description is not trivial and that’s why I also added an image describing what I would like to do:
So far, this is what I have as my algorithm:
func update(_ time: Int64) {
let t_startPoint: Int64 = 1
let position_startPoint: = (1.0, 1.0)
let t_endPoint: Int64 = 5
let position_endPoint: Vector = (4.0, 5.0)
let currentTime = 3
let duration = t_endPoint - t_startPoint
let x = position_startPoint.x + ((position_endPoint.x - position_startPoint.x) / Float(duration)) * (Float(currentTime - t_startPoint))
let y = position_startPoint.y + ((position_endPoint.y - position_startPoint.y) / Float(duration)) * (Float(currentTime - t_startPoint))
//
However, no matter what I do, my objects keep overshooting, erratically moving back and forth, and I don't know where to start. Any help would be greatly appreciated!

For constant velocity moving there is relation:
(t-t1) / (t2-t1) = (x-x1) / (x2-x1)
x = x1 + (x2-t1) * (t-t1) / (t2-t1)
so your expresiion looks right. Check:
1 + (4-1) * (3-1) / (5-1) = 1 + 3 * 2 / 4 = 2.5 - exact middle, OK

Related

Finding area of n-sided polygon with array of decimal latitude and longitude

I am trying to find the area of a polygon generated by a users path. The path gives back an array of lat/lon. The path is always self closing. I have tried multiple methods that I found online. Below is what I currently have, I can't make sense of the outputted data. The area * 6378137.0 * 6378137.0 is meant to give me back an area in m^2, but the results are massive numbers.
My ideal solution would be to find a way to (with an assumed % of error) map my lat/lon to xy coordinates and apply the shoelace theorem. I understand that this is pretty hard to do accurately because of the curvature of the earth.
Building from the last paragraph, maybe the best way to map to x,y coordinates would be some sort of projection method. I have not gone too far down that path yet.
What would be the best method to try in order to solve this problem? If someone could set me on the right path or decipher the code I have already tried I would greatly appreciate it (code is done in swift playground). Thanks!
func deg2rad(_ number: Double) -> Double {
return number * .pi / 180
}
func areaCalc(lat: [Double]?, lon: [Double]?){
guard let lat = lat,
let lon = lon
else { return }
var area: Double = 0.0
if(lat.count > 2){
for i in stride(from: 0, to: lat.count - 1, by: 1) {
let p1lon = lon[i]
let p1lat = lat[i]
let p2lon = lon[i+1]
let p2lat = lat[i+1]
area = area + (deg2rad(p2lon - p1lon)) * (2 + sin(deg2rad(p1lat))) + (sin(deg2rad(p2lat)))
}
area = area * 6378137.0 * 6378137.0
area = abs(area / 2)
}
}

Calculating worldFront like in SCNARView

In SCNARView I can access a property of camera node called worldFront, which represents camera rotation. I would like to calculate similar vector from CoreMotion values not using SCNARView, just data from CoreMotion. So that I can get a vector that would be equal to worldFront in SCNARView if camera was facing the same direction. Can someone explain me how to calculate such a value?
The attitude property probably could help
func rollCam(motion: CMDeviceMotion) {
let attitude = motion.attitude
let roll = Float(attitude.roll-M_PI/2)
let yaw = Float(attitude.yaw)
let pitch = Float(attitude.pitch)
camNode.eulerAngles = SCNVector3Make(roll, -yaw, pitch)
}
With this piece of code, quite long time ago, I experimented a bit with CoreMotion. I was trying to first detect human walking and then (with the startDeviceMotionUpdates data) move and roll the camera near to an "anchored" SCNBox. Later on ARKit solved my need with the ARAnchor class
What feature are you looking after?
I have found the answer:
override var cameraFrontVector: double3 {
guard let quaternion = motionService.deviceMotion?.attitude.quaternion else { return .zero }
let x = 2 * -(quaternion.x * quaternion.z + quaternion.w * quaternion.y)
let z = 2 * (quaternion.y * quaternion.z - quaternion.w * quaternion.x)
let y = 2 * (quaternion.x * quaternion.x + quaternion.y * quaternion.y) - 1
return double3(x: x, y: y, z: z)
}
This gives me values like worldFront in SCNNode.

Detect self intersection of a polygon with n sides?

I am using Google Maps SDK to allow a user to draw a polygon on the map by tapping. Everything works perfectly is the user is to draw a polygon following a path and continues on that path without crossing over lines. If that happens, this result is produced:
However, if the user is to make an error and cross over or change the direction of their "tapping" path this happens:
I need to either:
A) alert the user that they have created an invalid polygon, and must undo that action, or
B) correct the polygon shape to form a complete polygon.
With the research I have done, option A seems much more feasible and simple since option B would require rearranging the path of the polygon points.
I have done research and found algorithms and formulas to detect line intersection, but I am yet to find any piece of a solution in Swift to recognize if a polygon self-intersects based off of points (in this case, latitude and longitude). I don't need to know the point, just TRUE or FALSE to the question, "Does this Polygon self-intersect?" The polygon will typically have less than 20 sides.
Perhaps there is a solution built in with the GoogleMaps SDK, but I am yet to find it. Also, I understand that there are already algorithms for problems such as these, I am just having trouble implementing them into Swift 2 or 3. Any help is appreciated, thanks!
I'm guessing that you're trying to plot out the quickest way to get from point to point as the crow flies. You'll probably want to consider road direction too, which I won't here.
Both your options are possible. It's easy enough to iterate over every existing line when a new line is added and determine if they've crossed over. But your user would definitely rather not be told that they've screwed up, your app should just fix it for them. This is where it gets fun.
I am certain algorithms exist for finding the minimal polygon containing all points, but I didn't look them up, because where's the fun in that.
Here's how I would do it. In pseudocode:
if (line has intersected existing line)
find mean point (sum x sum y / n)
find nearest point to centre by:
taking min of: points.map(sqrt((x - centrex)^2 + (y-centrey)^2))
from the line between centre and nearest point, determine angle to every other line.
points.remove(nearest)
angles = points.map(cosine law(nearest to centre, centre, this point))
<- make sure to check if it crossed pi, at which point you must add pi.
sort angles so minimum is first.
starting at nearest point, add line to next point in the array of minimal angle points
I'm sorry I haven't put this into swift. I will update tomorrow with proper Swift 3.
This seems to be working pretty well for what I need. Adopted from Rob's answer here
func intersectionBetweenSegmentsCL(p0: CLLocationCoordinate2D, _ p1: CLLocationCoordinate2D, _ p2: CLLocationCoordinate2D, _ p3: CLLocationCoordinate2D) -> CLLocationCoordinate2D? {
var denominator = (p3.longitude - p2.longitude) * (p1.latitude - p0.latitude) - (p3.latitude - p2.latitude) * (p1.longitude - p0.longitude)
var ua = (p3.latitude - p2.latitude) * (p0.longitude - p2.longitude) - (p3.longitude - p2.longitude) * (p0.latitude - p2.latitude)
var ub = (p1.latitude - p0.latitude) * (p0.longitude - p2.longitude) - (p1.longitude - p0.longitude) * (p0.latitude - p2.latitude)
if (denominator < 0) {
ua = -ua; ub = -ub; denominator = -denominator
}
if ua >= 0.0 && ua <= denominator && ub >= 0.0 && ub <= denominator && denominator != 0 {
print("INTERSECT")
return CLLocationCoordinate2D(latitude: p0.latitude + ua / denominator * (p1.latitude - p0.latitude), longitude: p0.longitude + ua / denominator * (p1.longitude - p0.longitude))
}
return nil
}
I then implemented like this:
if coordArray.count > 2 {
let n = coordArray.count - 1
for i in 1 ..< n {
for j in 0 ..< i-1 {
if let intersection = intersectionBetweenSegmentsCL(coordArray[i], coordArray[i+1], coordArray[j], coordArray[j+1]) {
// do whatever you want with `intersection`
print("Error: Intersection # \(intersection)")
}
}
}
}

Displaying 4 textures using for loop

I'm creating a game using Swift 2.0 and Sprite-Kit with Xcode7. I want to implement 4 purple balls that are suppose to resemble lives. So every time the player gets hit he loses one purple ball. They are supposed to appear side by side. I was wondering if instead of hardcoding 4 balls on to the scene I could instead use a for loop to display 4 balls.
let purpleBall = SKSpriteNode(texture: purpleTexture)
purpleBall.position = CGPointMake(self.frame.size.width * 0.65, self.frame.size.height * 0.92)
self.addChild(purpleBall)
I haven't been successful on getting 4 balls to appear on the scene. This was one of my attempts.
for(var i = 0.50; i <= 0.90; i = i + 0.10) {
let purpleBall = SKSpriteNode(texture: purpleTexture)
purpleBall.position = CGPointMake(self.frame.size.width * i, self.frame.size.height * 0.92)
self.addChild(purpleBall)
}
Here I get an error: Binary operator cannot be applied to operands of type 'CGFloat' and 'Double'
Do I have to convert i to CGFloat? and will this code actually place 4 different balls side by side or only move the single one to each new position.
Your code has an off by one error in the for loop. It should be a less than sign rather than less than or equal too. Your current code is going to create five purple balls.
You shouldn't really let i equal anything but an integer it's confusing. You could rewrite the code like this and it would do the same thing, without the worry of the float/double errors you're currently getting. Note that I will also use a constant called maxBalls, and distanceBetweenBalls so that you can easily change the number of balls and the distance without any complicated rewriting:
let maxBalls = 4
for(var i = 0; i < maxBalls; i++) {
let purpleBall = SKSpriteNode(texture: purpleTexture)
let ballXPosition = .50 + (i * .1)
purpleBall.position = CGPointMake(self.frame.size.width * ballXPosition, self.frame.size.height * 0.92)
self.addChild(purpleBall)
This should avoid the issues you were facing before, hope that helps.

Distance between two coordinates in php using haversine

I've looked around and seen mention of the haversine formula to determine distance between two coordinates (lat1, lng1) and (lat2, lng2).
I've implemented this code:
function haversineGreatCircleDistance(
$latitudeFrom, $longitudeFrom, $latitudeTo, $longitudeTo, $earthRadius = 6371000)
{
// convert from degrees to radians
$latFrom = deg2rad($latitudeFrom);
$lonFrom = deg2rad($longitudeFrom);
$latTo = deg2rad($latitudeTo);
$lonTo = deg2rad($longitudeTo);
$latDelta = $latTo - $latFrom;
$lonDelta = $lonTo - $lonFrom;
$angle = 2 * asin(sqrt(pow(sin($latDelta / 2), 2) +
cos($latFrom) * cos($latTo) * pow(sin($lonDelta / 2), 2)));
return $angle * $earthRadius;
}
And am trying to determine:
1) what units this is returning? (goal being in feet)
2) is this equation written the right way?
For example what should be the distance between these two points?
(32.8940695525,-96.7926336453) and (33.0642604502, -96.8064332754)?
I'm getting 18968.0903312 from the formula above.
Thanks!
1) what units this is returning? (goal being in feet)
Whatever units in which you supply the Earth's radius.
2) is this equation written the right way?
Test it. You can compare your results with an existing Haversine formula implementation, like this one.