Retrieving list of objects from application.conf - scala

Question

I have the following entry in Play for Scala application.conf:
jobs = [
{number: 0, dir: "/dir1", name: "General" },
{number: 1, dir: "/dir2", name: "Customers" }
]
I want to retrieve this list of objects in a Scala program:
val conf = ConfigFactory.load
val jobs = conf.getAnyRefList("jobs").asScala
println(jobs)
this prints
Buffer({number=0, name=General, dir=/dir1}, {number=1, name=Customers, dir=/dir2})
But how to convert the result to actual Scala objects?

Answer 1

Try this one:
case class Job(number: Int, dir: String, name: String)
object Job {
implicit val configLoader: ConfigLoader[List[Job]] = ConfigLoader(_.getConfigList).map(
_.asScala.toList.map(config =>
Job(
config.getInt("number"),
config.getString("dir"),
config.getString("name")
)
)
)
}
Then from Confugutation DI
Configuration.get[List[Job]]("jobs")

Answer 2

Here is a Config object which will extract data from a config file into a type that you specify.
Usage:
case class Job(number: Int, dir: String, name: String)
val jobs = Config[List[Job]]("jobs")
Code:
import com.typesafe.config._
import org.json4s._
import org.json4s.jackson.JsonMethods._
object Config {
private val conf = ConfigFactory.load()
private val jData = parse(conf.root.render(ConfigRenderOptions.concise))
def apply[T](name: String)(implicit formats: Formats = DefaultFormats, mf: Manifest[T]): T =
Extraction.extract(jData \\ name)(formats, mf)
}
This will throw an exception if the particular config object does not exist or does not match the format of T.