Shortest way to call a function without using its argument label? - swift

Question

This question is just having fun with Swift. Please don't take it too seriously...
In Swift, given this function:
func greet(name: String) {
print("Hello \(name)!")
}
the proper way of calling it is like this:
greet(name: "Bob") // "Hello Bob!"
If you omit the argument label name:
greet("Bob")
you get the error: Missing argument label 'name:' in call
But treating the function as a closure allows you to call it without the argument label:
let g = greet; g("Bob") // "Hello Bob!"
This made me wonder, what is the most concise way of calling a function without using its argument label?
Wrap it in a tuple?
I thought wrapping the function in a tuple and then extracting it would work:
(greet).0("Bob")
but this resulted in the error: Value of type '(String) -> ()' has no member '0'.
This works:
(greet,greet).0("Bob") // "Hello Bob!"
So apparently, Swift treats simple tuples of 1 value as just the value itself.
Giving the tuple argument a label works:
(g:greet).g("Bob") // "Hello Bob!"
(g:greet).0("Bob") // "Hello Bob!"
Put it in an array?
So far, the most concise way I have found is to put the function into an array:
[greet][0]("Bob") // "Hello Bob!"
This uses only 5 characters more than greet("Bob") which would seem to be the shortest possible call if it worked.
Is there any shorter way to call the greet(name:) function without using the argument label than this?