Catching scanamo errors within scala - scala

Question

I'm using scanamo to query a dynamodb table.
I want to create a healthcheck method that will return true as long as dynamo can be scanned (i don't care if there are records in the table, i just want to know that the table is there and can be scanned). And i want false to be returned if the table is not present (i fudge the table name as a test).
This is the scala code i have right now:
trait DynamoTestTrait extends AbstractDynamoConfig {
def test(): Future[List[Either[DynamoReadError, T]]] =
ScanamoAsync.exec(client)(table.consistently.limit(1).scan())
}
and it works when the table is present:
val r = reg.test()
.map(
_.headOption.forall(_.isRight)
)
val e = Await.result(r, scala.concurrent.duration.Duration(5, "seconds"))
but when the table name is incorrect i get an unexpected error:
Unexpected server error: 'Cannot do operations on a non-existent table (Service: AmazonDynamoDBv2; Status Code: 400; Error Code: ResourceNotFoundException;
I would have thought that i was trapping that error in my Left.
How can i trap this error? does scala have a try/catch construct i could use?
I also tried this but the error still gets thrown and not my catch it seems:
trait DynamoTestTrait extends AbstractDynamoConfig {
def test(): Future[Boolean] =
try {
ScanamoAsync
.exec(client)(table.consistently.limit(1).scan())
.map(
_.headOption.forall(_.isRight)
)
} catch {
case e: ResourceNotFoundException => Future.successful(false)
}
}
this seems more scalathonic, but always returns true:
trait DynamoTestTrait extends AbstractDynamoConfig {
def test: Future[Boolean] = {
val result = Try(ScanamoAsync
.exec(client)(table.consistently.limit(1).scan())
.map(
_.headOption.forall(_.isRight)
))
result match{
case Success(v) => Future.successful(true)
case Failure(e) => Future.successful(false)
}
}
}