C++ overloading operator, compiler doesn't see the operator - operator-overloading

Question

CMagazin.h
class CMagazin
{
char *m_nume;
list<CProdus*>List_produse;
public:
void printExpirabile( const char* data);
~CMagazin();
};
CMagazin.cpp
void CMagazin::printExpirabile(const char *xdata)
{
list<CProdus*>::iterator it;
for (it = List_produse.begin(); it != List_produse.end(); ++it)
{
CProdus* p = *it;
if (p->get_tip()=='A')
{
**if (p > xdata)**->this problem
}
}
}
CAliment.h
class CAliment :
public CProdus
{
char *m_expirare;
public:
bool operator >(const char*date);
~CAliment();
};
CAliment.cpp
bool CAliment::operator>(const char * date)
{
if (atoi(this->m_expirare) < atoi(date))
{
return 1;
}
else
{
return 0;
}
}
its about ">" operator.in CMagazin.cpp dont use my operator...i need help.
what can i do?I need ">" in CMagazin class. class CAliment its a class derived from CProdus.

Answer 1

Answer is: in Class CProdus the operator must be declared virtual, and in
CMagazin.cpp
void CMagazin::printExpirabile(const char *xdata)
{
list<CProdus*>::iterator it;
for (it = List_produse.begin(); it != List_produse.end(); ++it)
{
CProdus* p = *it;
if (p->get_tip()=='A')
{
if (p->operator>( xdata))-> make this!
{
p->print();
}
}
}
}

Answer 2

CProdus*p - is a pointer , need to have object for use this operator -> Try (*p)>xdata
void CMagazin::printExpirabile(const char *xdata)
{
list<CProdus*>::iterator it;
for (it = List_produse.begin(); it != List_produse.end(); ++it)
{
CProdus* p = *it;
if (p->get_tip()=='A')
{
if ((*p)>( xdata))-> make this!
{
p->print();
}
}
}
}