I am using Quartz for performing some jobs, every thing is working perfect but problem is that
I want to set time particular time to start quartz
i want to run quartz every day at 6:00PM how to set this time, right now my quartz is running after every 5 seconds
I am using java, jsf and primefaces.
===UPDATE===
I used the expression that elbraulio suggested and it is ok. But Quartz cron is not working,
here was my previous code :
<schedule>
<job>
<name>AJob</name>
<group>AGroup</group>
<description>Print a welcome message</description>
<job-class>com.mkyong.scheduler.SchedulerJob</job-class>
</job>
<trigger>
<cron>
<name>dummyTriggerName</name>
<job-name>AJob</job-name>
<job-group>AGroup</job-group>
<!-- It will run every 5 seconds -->
<cron-expression>0/30 * * * * ?</cron-expression>
</cron>
</trigger>
</schedule>
now i have changed it in this but not working.
<schedule>
<job>
<name>AJob</name>
<group>AGroup</group>
<description>Print a welcome message</description>
<job-class>com.mkyong.scheduler.SchedulerJob</job-class>
</job>
<trigger>
<cron>
<name>dummyTriggerName</name>
<job-name>AJob</job-name>
<job-group>AGroup</job-group>
<!-- It will run every 5 seconds -->
<cron-expression>0 0 18 ? * * *</cron-expression>
</cron>
</trigger>
</schedule>
is there any time zone problem?
This is the expression you need to run every day at 6:00PM
0 0 18 ? * * *
Also, you can use this site to generate expressions easily.
Related
My simulation fails to stop until an inbuilt timeout is reached. The default is 3600 seconds. How do I set this to a different time period?
The openCPI version is 2.4.3.
Any suggestions?
This is my first use of OpenCPI.
You can change the default timeout for tests using the Timeout attribute in the Tests element of your test XML like below:
<Tests UseHdlFileIO="true" Timeout="30">
<Case>
<!-- Inputs and Outputs in here -->
</Case>
</Tests>
The timeout is defined in seconds. More information can be found in section 13.3.5 of the OpenCPI Component Development Guide
Scheduling jobs using code is easy, but I would like to schedule jobs based on contents of a folder.
For example:
I want the folder in "\MyApp\Jobs\" to contain some XML files that will have the information about the IJob to be scheduled.
The thing is that I want this folder to be watched for changes (for XML files) and when a new file is found, a new IJob will be schedule using the information contained in the XML.
What should I do to implement a mechanism like this?
Thanks
The class java.io.File has a few listFiles() methods which will list the contents of your directory. Use a FileFilter or FilenameFilter if you want to limit the filenames returned in some way. Do this in a loop with a "sleep", something like 60 seconds, to avoid chewing up all your CPU.
Hope this helps.
you dont need to watch for changes in file using file watcher.
while creating quartz property file it have option as
org.quartz.plugin.jobInitializer.scanInterval = 5
which scans for xml file changes.so in above case it scans every 5 seconds
my complete quartz.property file as follow
org.quartz.scheduler.instanceName = MyScheduler
org.quartz.threadPool.threadCount = 3
org.quartz.jobStore.class = org.quartz.simpl.RAMJobStore
org.quartz.plugin.jobInitializer.class =org.quartz.plugins.xml.XMLSchedulingDataProcessorPlugin
org.quartz.plugin.jobInitializer.fileNames =C:/Users/Admin/Documents/NetBeansProjects/QXmlTest/src/java/quartz-config.xml
org.quartz.plugin.jobInitializer.failOnFileNotFound =true
org.quartz.plugin.jobInitializer.scanInterval = 5
org.quartz.plugin.jobInitializer.wrapInUserTransaction= true
and i define jobs and trigger inside this quartz-config.xml file as follows :
<?xml version="1.0" encoding="UTF-8"?>
<job-scheduling-data
xmlns="http://www.quartz-scheduler.org/xml/JobSchedulingData"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.quartz-scheduler.org/xml/JobSchedulingData
http://www.quartz-scheduler.org/xml/job_scheduling_data_1_8.xsd"
version="1.8">
<schedule>
<job>
<name>AJob</name>
<group>AGroup</group>
<description>Print a welcome message</description>
<job-class>mypackage.SchedulerJob</job-class>
</job>
<trigger>
<cron>
<name>dummyTriggerName</name>
<job-name>AJob</job-name>
<job-group>AGroup</job-group>
<!-- It will run every 5 seconds -->
<cron-expression>0/5 * * * * ?</cron-expression>
</cron>
</trigger>
</schedule>
</job-scheduling-data>
Please note that i am using quartz java api.
I found some predefined fileNamePatterns for TimeBasedRollingPolicy.
Here's one that does every minute.
<appender name="FILE" class="ch.qos.logback.core.rolling.RollingFileAppender">
<file>logfile.log</file>
<rollingPolicy class="ch.qos.logback.core.rolling.TimeBasedRollingPolicy">
<fileNamePattern>logfile.%d{yyyy-MM-dd_HH-mm}.log</fileNamePattern>
</rollingPolicy>
</appender>
Does anyone know how do i do this for every x days?
Could I extend RollingFileAppender? I am doing this in Scala.
Regardless of using Scala or Java, the answer is easy for x == 1 and x == 7.
For daily rollover, use
<fileNamePattern>logfile.%d{yyyy-MM-dd}.log</fileNamePattern>
and for weekly, write
<fileNamePattern>logfile.%d{yyyy-ww}.log</fileNamePattern>
(actually it rolls over at the start of the week depending on your locale, and not every seven days).
If you want a more general solution, you have to implement your custom RollingPolicy, but I don't know why would you need that. If you have problems with this size of the log, you should note that the log can be rolled over when a a specific size is reached. There are plenty of examples at http://logback.qos.ch/manual/appenders.html
I used this trigger to run job every 1 hour from 12 AM- 8 AM. But this is not triggering at all. Is this expression correct?
0 0/60 12,8 * * ?
You can this site to build and check expressions based on "Quartz Cron" format.
The correct expression is this:
0 0 0-8 * * ?
I don't know if the below expression is correct:
<property name="cronExpression" value="0 0 12 2 * MON-FRI ?"/>
I try to configure my trigger to fire every second day of every month, no matter the year, at noon, and the day of week has to be between Monday and Friday.
I'd really appreciate if someone could help me. Thanks in advance.
I'm assuming you meant "every second day (every other day), as long as it's MON-FRI".
According to Quartz CronTrigger Tutorial:
'1/3' in the day-of-month field means "fire every 3 days starting on
the first day of the month".
So, 1/2 would mean "fire every second day starting on the first day of the month". A cronExpression like 0 0 12 1/2 * MON-FRI * should then be close to what you want. Checking with
org.quartz.CronExpression.isValidExpression("0 0 12 1/2 * MON-FRI *")
...says that the expression is valid.
However, testing it a little further with:
CronExpression e = new CronExpression("0 0 12 1/2 * MON-FRI *");
e.isSatisfiedBy(new DateTime(2012, 9, 26, 12, 0, 0, 0).toDate());
...throws an exception:
> Exception in thread "main" java.lang.UnsupportedOperationException:
> Support for specifying both a day-of-week AND a day-of-month parameter
> is not implemented.
So, seems like jhouse is right and you just can't do that with a cronExpression.
Maybe something like this would work as a workaround: Quartz cron expression for cron triggers executed every Nth Hour/Day/Week/Month
You cannot specify both a day of month and a day of week - it is not supported.