Coming out of an Oracle background converting dates from any format to any format is really easy.
How is this done in SQLite? I've searched and searched for answers and most of the answers simply say... Save your date/strings in SQLite in one single format which is YYYY-MM-DD HH:MM:SS.SSS. This seems rigid to me.
I don't have that luxury as my data is stored in this format DD/MM/YYYY HH:MI:SS am ex. 3/7/2020 8:02:31 AM.
NOTE: For single days/months my date values do not contain leading zeros and my time is NOT in military time.
How do I tell SQLite what my date format is so that I can correctly convert my stored dates to SQLite datetime formats?
Convert from SQLite Date Format to Oracle Date Example:
In Oracle I would simply use the to_date function like so
to_date('2019-03-07 15:39:34', 'YYYY-MM-DD HH24:MI:SS')
All one needs to do is to tell the function what the date format is... and then it spits out a date.... easy peasy. What this example does is convert a SQLite date formated string to a date that Oracle recognizes as a date. It doesn't matter what the format is in as I tell the function what format to expect.
How do I Convert Dates in SQLite from any format to the SQLite Format?
Converting from SQLite's date format string to ANY date is easy as there are functions built in that do this easily... but how to do this the other way round?
Related
I've date in dd-mm-yyyy format, I need the date in yyyy-mm(month) format. I'm using postgresql.
Thanks in advance.
date values don't have any format. Any formatting you see is applied by your SQL client. To turn a date into a string with a specific format, you can use to_char()
to_char(the_column, 'yyyy-mm')
I need to execute a INSERT statement writing a date with a YYYY-MM-DD format.
Would to_date('2021-09-28','YYYY-MM-DD') work?
YYYY-MM-DD is the the ISO 8601 standard date format and unambiguous default in Postgres. Just insert your date literally.
The type date is stored as a 4-byte integer quantity internally, which does not preserve any format. You can format any way you like on output with some basic locale settings or settings of your client, or explicitly with to_char().
Input with to_date('2021-09-28','YYYY-MM-DD') works, too. But you don't need to_date() while operating with ISO format.
I'm working with a large CSV file with millions of rows. I'm using OpenRefine to manipulate this large data set.
I have a column with date strings in this format "2017-08-17 04:36:00". And I would like to convert them to Unix time in integer format like 1502944560.
I see many Q&A on converting Unix time to Date String but not the other way around. Is this possible in OpenRefine?
value.toDate().datePart("time")
(see the bottom of this documentation for other conversion strings)
When importing a text file into Access 2007 with date/time values like
2014-07-02T16:09:49-07:00
Access is unable to convert to date and shows the same as text. How do I convert the same in to date/time in Access?
You will probably need to import the ISO 8601 date/time values into a Text field, then use an Update query to convert those string values and write them to a Date/Time field. The question
Parsing an ISO8601 date/time (including TimeZone) in Excel
has several answers that include VBA functions you might be able to adapt depending on your specific requirements (and possibly some slight differences in date handling between Excel and Access).
I am reading a csv file with date fields of formatted mm/dd/yyyy. I expected the same kind of format from a Postgres table after the import, but I see yyyy-mm-dd hh:mm:ss.
The date fields in my table are defined as timestamp without time zone data type.
How do I maintain the same format of data? I am using PostgreSQL 9.3.
Postgresql only stores the value, it doesn't store formatting (which would waste space).
You can use the to_char function in your query if you like to get the output formatted in a special way. Details are in the manual.