Add empty buckets in mongo aggregation - mongodb

I have the following aggregation:
const buckets = await StatisticModel.aggregate([
{
$bucket: {
groupBy: '$ranking',
boundaries: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 11],
},
},
])
Which returns the following object:
[
{ _id: 3, count: 6 },
{ _id: 4, count: 98 },
{ _id: 5, count: 81 },
{ _id: 6, count: 25 },
{ _id: 7, count: 4 }
]
How can I add the missing (empty) buckets?
This is a simple example but I have more complexe ones where I generate the boundaries and I want to return to the front-end all the buckets and not only the filled ones.

You can use below aggregation
db.collection.aggregate([
{ "$facet": {
"data": [
{ "$bucket": {
"groupBy": "$ranking",
"boundaries": [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 11]
}}
]
}},
{ "$addFields": {
"data": {
"$map": {
"input": [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 11],
"as": "i",
"in": {
"_id": "$$i",
"count": {
"$cond": [
{ "$eq": [{ "$indexOfArray": ["$data._id", "$$i"] }, -1] },
0,
{ "$arrayElemAt": ["$data.count", { "$indexOfArray": ["$data._id", "$$i"] }] }
]
}
}
}
}
}},
{ "$unwind": "$data" },
{ "$replaceRoot": { "newRoot": "$data" }}
])
But better to do with javascript
const array = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 11]
const array2 = [
{ "_id": 3, "count": 6 },
{ "_id": 4, "count": 98 },
{ "_id": 5, "count": 81 },
{ "_id": 6, "count": 25 },
{ "_id": 7, "count": 4 }
]
array.map((ar) => {
const index = array2.map((e) => { return e._id }).indexOf(ar)
if (index === -1) {
array2.push({ _id: ar, count: 0 })
}
})
console.log(array2)

Starting in Mongo 5.1, it's a perfect use case for the new $densify aggregation operator:
// { ranking: 3, count: 6 }
// { ranking: 4, count: 98 }
// { ranking: 6, count: 25 }
// { ranking: 7, count: 4 }
db.collection.aggregate([
{ $densify: {
field: "ranking",
range: { step: 1, bounds: [0, 12] }
}},
{ $set: { count: { $cond: [ { $not: ["$count"] }, 0, "$count" ] } } }
])
// { ranking: 0, count: 0 } <=
// { ranking: 1, count: 0 } <=
// { ranking: 2, count: 0 } <=
// { ranking: 3, count: 6 }
// { ranking: 4, count: 98 }
// { ranking: 5, count: 0 } <=
// { ranking: 6, count: 25 }
// { ranking: 7, count: 4 }
// { ranking: 8, count: 0 } <=
// { ranking: 9, count: 0 } <=
// { ranking: 10, count: 0 } <=
// { ranking: 11, count: 0 } <=
This:
densifies documents ($densify) by creating new documents in a sequence of documents where certain values for a field (in our case field: "ranking") are missing:
the step for our densification is 1: range: { step: 1, ... } since our buckets are following each other with a size of 1.
and we densify within the range [0, 12]: bounds: [0, 12]
finally sets ($set) count to 0 only for new documents included during the densify stage ({ count: { $cond: [ { $not: ["$count"] }, 0, "$count" ] } })
Note that I'm assuming your buckets are of equal size (assuming the missing 10 in your list is an oversight).

Related

Mongo db aggregation - $push and $slice top results

I have the following documents in my db:
{uid: 1, score: 10}
{uid: 2, score: 11}
{uid: 3, score: 1}
{uid: 4, score: 6}
{uid: 5, score: 2}
{uid: 6, score: 3}
{uid: 7, score: 8}
{uid: 8, score: 10}
I want to split them into buckets by score - i.e.:
score
uids
(bucket name in aggregation)
[0,4)
3,5,6
0
[4,7)
4
4
[7,inf
1,2,7,8
7
For this, I created the following aggregation which works just fine:
db.scores.aggregation(
[
{
$bucket:
{
groupBy: "$score",
boundaries: [0, 4, 7],
default: 7,
output:
{
"total": {$sum: 1},
"top_frustrated":
{
$push: {
"uid": "$uid", "score": "$score"
}
},
},
}
},
]
)
However, I would like to return only the top 3 of every bucket - i.e, buckets 0, 4 should be the same, but bucket 7 should have only uids 1,2,8 returned (as uid 7 has the lowest score) - but to include the total count of documents as well, i.e. output of bucket "7" should look like:
{ "total" : 4, "top_scores" :
[
{"uid" : 2, "score" : 11},
{"uid" : 1, "score" : 10},
{"uid" : 8, "score" : 10},
]
}
I tried using $addFields with $sortArray and $slice, but it either won't work or return errors.
I can of course use $project but I was wondering if there is a more efficient way.
I am using Amazon DocumentDB.
You can use the $topN accumulator, instead of $push, like this:
db.collection.aggregate([
{
"$bucket": {
"groupBy": "$score",
"boundaries": [
0,
4,
7
],
"default": 7,
"output": {
"total": {
"$sum": 1
},
"top_frustrated": {
"$topN": {
"n": 3,
"sortBy": {
"score": -1
},
"output": {
"uid": "$uid",
"score": "$score"
}
}
}
},
}
},
])
Playground link.
The only catch here is this operator is present in MongoDB 5.2 and above.
For older versions, this will work:
db.collection.aggregate([
{
"$sort": {
score: -1
}
},
{
$bucket: {
groupBy: "$score",
boundaries: [
0,
4,
7
],
default: 7,
output: {
"total": {
$sum: 1
},
"top_frustrated": {
$push: {
"uid": "$uid",
"score": "$score"
}
},
},
}
},
{
"$project": {
total: 1,
top_frustrated: {
"$slice": [
"$top_frustrated",
3
]
}
}
}
])
Playground link.

MONGODB Aggregate query to give $min value of array field by element

Hi I am converting my existing website from php / mysql to node / mongodb , it is a golf society site which I use to log scores for each members rounds and provide results and statistics into their games. The main collection contains an array of 18 scores which is great for my results queries but I am having a problem with the statistical side, ie Avg score by Hole by Course, Lowest score ever by Hole by Course (eclectic) . I have come up with this aggregate query which works and gives me the result I require but it is ugly !! I am sure there must be a more elegant solution out there and feel I am missing a trick somewhere, I have looked at $map as I thought that might help but don't think it will. I would appreciate it if someone could offer any suggestions in tidying this code up, Thx.
{ _id:
{ date_played: 2019-06-21T00:00:00.000Z,
course_played: 1,
player_id: 1 },
score: [ 8, 4, 7, 4, 7, 1, 7, 5, 6, 4, 5, 7, 6, 4, 7, 5, 6, 7 ],
handicap: 23,
cash_won: 0,
sort_order: 2,
gross_score: 100,
gross_sfpts: 31,
skins_group: 1,
score_differential: 26.2,
pcc_adjustment: 0 }
{ _id:
{ date_played: 2016-08-14T00:00:00.000Z,
course_played: 1,
player_id: 1},
score: [ 5, 4, 5, 6, 5, 4, 8, 6, 1, 3, 3, 4, 3, 6, 3, 6, 4, 5 ],
handicap: 18,
cash_won: 14,
sort_order: 4,
gross_score: 81,
gross_sfpts: 44,
skins_group: 1,
score_differential: 12.1,
pcc_adjustment: 0 }
[
{
'$match': {
'_id.course_played': 1
}
}, {
'$project': {
'player_name': 1,
'hole01': {
'$arrayElemAt': [
'$score', 0
]
},
'hole02': {
'$arrayElemAt': [
'$score', 1
]
},
'hole03': {
'$arrayElemAt': [
'$score', 2
]
},
'hole04': {
'$arrayElemAt': [
'$score', 3
]
},
'hole05': {
'$arrayElemAt': [
'$score', 4
]
},
'hole06': {
'$arrayElemAt': [
'$score', 5
]
},
'hole07': {
'$arrayElemAt': [
'$score', 6
]
},
'hole08': {
'$arrayElemAt': [
'$score', 7
]
},
'hole09': {
'$arrayElemAt': [
'$score', 8
]
},
'hole10': {
'$arrayElemAt': [
'$score', 9
]
},
'hole11': {
'$arrayElemAt': [
'$score', 10
]
},
'hole12': {
'$arrayElemAt': [
'$score', 11
]
},
'hole13': {
'$arrayElemAt': [
'$score', 12
]
},
'hole14': {
'$arrayElemAt': [
'$score', 13
]
},
'hole15': {
'$arrayElemAt': [
'$score', 14
]
},
'hole16': {
'$arrayElemAt': [
'$score', 15
]
},
'hole17': {
'$arrayElemAt': [
'$score', 16
]
},
'hole18': {
'$arrayElemAt': [
'$score', 17
]
}
}
}, {
'$sort': {
'_id.player_id': 1
}
}, {
'$group': {
'_id': '$_id.player_id',
'name': {
'$first': '$player_name'
},
'hole1': {
'$min': '$hole01'
},
'hole2': {
'$min': '$hole02'
},
'hole3': {
'$min': '$hole03'
},
'hole4': {
'$min': '$hole04'
},
'hole5': {
'$min': '$hole05'
},
'hole6': {
'$min': '$hole06'
},
'hole7': {
'$min': '$hole07'
},
'hole8': {
'$min': '$hole08'
},
'hole9': {
'$min': '$hole09'
},
'hole10': {
'$min': '$hole10'
},
'hole11': {
'$min': '$hole11'
},
'hole12': {
'$min': '$hole12'
},
'hole13': {
'$min': '$hole13'
},
'hole14': {
'$min': '$hole14'
},
'hole15': {
'$min': '$hole15'
},
'hole16': {
'$min': '$hole16'
},
'hole17': {
'$min': '$hole17'
},
'hole18': {
'$min': '$hole18'
},
'rounds': {
'$sum': 1
}
}
}, {
'$addFields': {
'total': {
'$add': [
'$hole1', '$hole2', '$hole3', '$hole4', '$hole5', '$hole6', '$hole7', '$hole8', '$hole9', '$hole10', '$hole11', '$hole12', '$hole13', '$hole14', '$hole15', '$hole16', '$hole17', '$hole18'
]
}
}
}, {
'$sort': {
'total': 1
}
}, {
'$limit': 10
}
]
Which gives this as an example when run against the total database, which is the result I want but I would like all the "hole" fields to be returned in an Array as per the original score field.
{ _id: 1,
hole1: 5,
hole2: 4,
hole3: 5,
hole4: 4,
hole5: 5,
hole6: 2,
hole7: 3,
hole8: 3,
hole9: 3,
hole10: 3,
hole11: 2,
hole12: 3,
hole13: 4,
hole14: 2,
hole15: 3,
hole16: 3,
hole17: 3,
hole18: 3,
rounds: 562,
total: 53 }
You might $unwind the scores array, keeping the index as the hole number, then $group by player, course, and hole to get the score for each hole, $sort by hole number to make sure of the order, and then $group by player and course, pushing the scores back into an array.
db.collection.aggregate([
{$match: {"_id.player_id": 1}},
{$unwind: {
path: "$score",
includeArrayIndex: "hole"
}},
{$group: {
_id: {
course_played: "$_id.course_played",
player_id: "$_id.player_id",
hole: "$hole"
},
minScore: {$min: "$score"},
rounds: {$sum: 1}
}},
{$sort: {"_id.hole": 1}},
{$group: {
_id: {
course_played: "$_id.course_played",
player_id: "$_id.player_id"
},
score: {$push: "$minScore"},
total: {$sum: "$minScore"},
rounds: {$first: "$rounds"}
}}
])
Playground

Mongodb sum after unwinding array of nested objects

I am new to mongodb aggregations. Given the following collection:
[
{
"ft": 1,
"pippo": 10,
"pluto": 5,
"detail": [
{
"ft": 1,
"pippo": 1,
"pluto": 2
},
{
"ft": 2,
"pippo": 1,
"pluto": 2
},
{
"ft": 1,
"pippo": 1,
"pluto": 2
},
{
"ft": 3,
"pippo": 1,
"pluto": 2
}
]
},
{
"ft": 2,
"pippo": 4,
"pluto": 3
}, {
"ft": 1,
"pippo": 1,
"pluto": 1
}
]
I would like to calculate the sum of all items having "ft":1.
I have tried this aggregation after unwinding the items contained in the array:
[
{
'$unwind': '$detail'
}, {
'$group': {
'_id': '$ft',
'count': {
'$sum': 1
},
'ft': {
'$first': '$ft'
},
'pippo': {
'$sum': '$pippo'
},
'pluto': {
'$sum': '$pluto'
}
}
}
]
And getting the following wrong result:
_id: 1,
count: 4,
pippo: 40,
pluto: 20
The correct result should be:
_id: 1,
count: 4, // all items having ft === 1
pippo: 13, // the sum of all pippo in all items where ft === 1
pluto: 10 // the sum of all pluto items where ft === 1

Mongodb aggregate $group for non-existing items

I have document like this :
Documents :
{score: 1, value: 10}
{score: 3, value: 10}
{score: 1, value: 10}
{score: 4, value: 10}
{score: 1, value: 10}
{score: 5, value: 10}
{score: 5, value: 10}
{score: 10, value: 10}
In this collection, there is no score for 2,6,7,8,9 but I need output like below.
Output :
{score: 1, avg: 10}
{score: 2, avg: 0}
{score: 3, avg: 10}
{score: 4, avg: 10}
{score: 5, avg: 10}
{score: 6, avg: 0}
{score: 7, avg: 0}
{score: 8, avg: 0}
{score: 9, avg: 0}
{score: 10, avg: 10}
Any option in Mongo aggregate which will generate this. Please assist
You can try that using aggregation :
db.collection.aggregate([
{ $group: { _id: '$score', avg: { $avg: '$value' } } },
{ $group: { _id: '', min: { $min: '$_id' }, max: { $max: '$_id' }, data: { $push: '$$ROOT' } } },
{ $project: { _id: 0, data: 1, nums: { $range: ['$min', "$max", 1] } } },
{ $project: { data: { $concatArrays: ["$data", { $map: { input: { $setDifference: ["$nums", "$data._id"] }, in: { _id: '$$this', avg: 0 } } }] } } },
{ $unwind: '$data' }, { $replaceRoot: { newRoot: "$data" } }
])
Test : MongoDB-Playground
Assuming you know the range of scores, there's a trick to achieve exactly what you want :
1 - Insert in your collection a document for each score, with value field not set or set to null :
db.collection.insertMany([
{
score: 1,
},
{
score: 2,
},
{
score: 3,
},
{
score: 4,
},
{
score: 5,
},
{
score: 6,
},
{
score: 7,
},
{
score: 8,
},
{
score: 9,
},
{
score: 10,
}
]);
It's important for value field not to be set, because a value set at 0 will affect average calculation
Of course this operation must be performed only once.
Then you can apply the following aggregation, which will output exactly what you need :
db.collection.aggregate([
{
$bucket: {
groupBy: "$score",
boundaries: [
0,
1,
2,
3,
4,
5,
6,
7,
8,
9,
10,
11
],
output: {
avg: {
$avg: "$value"
}
}
}
},
{
$project: {
score: "$_id",
avg: {
$ifNull: [
"$avg",
0
]
},
_id: 0
}
}
])
Will output :
[
{
"avg": 10,
"score": 1
},
{
"avg": 0,
"score": 2
},
{
"avg": 10,
"score": 3
},
{
"avg": 10,
"score": 4
},
{
"avg": 10,
"score": 5
},
{
"avg": 0,
"score": 6
},
{
"avg": 0,
"score": 7
},
{
"avg": 0,
"score": 8
},
{
"avg": 0,
"score": 9
},
{
"avg": 10,
"score": 10
}
]
You can test it here.

MongoDB aggregation framework to get frequencies of fields' values

I have a collection that is populated with documents that conform to the following schema:
{
_id,
name: String,
actionTime: Date,
n1: Number, // 1<=n1<=10
n2: Number, // 1<=n2<=10
n3: Number // 1<=n3<=20
}
I want to get the frequencies of each possible numbers of n1,n2,n3. So, for example if we have the following documents:
{
_id: 1,
name: 'label1',
actionTime: Date.now,
n1: 4,
n2: 9,
n3: 18
},
{
_id: 2,
name: 'label2',
actionTime: Date.now,
n1: 1,
n2: 6,
n3: 11
},
{
_id: 3,
name: 'label3',
actionTime: Date.now,
n1: 4,
n2: 2,
n3: 5
}
I would like to have a result document of the form (or like this):
{
"n1": {
"_id": 1, "total": 1,
"_id": 2, "total": 0,
...
"_id": 4, "total": 2,
...
},
"n2": {
"_id": 1, "total": 0,
"_id": 2, "total": 1,
...
"_id": 6, "total": 1,
...
_id: 9, 'total': 1,
...
},
"n3": {
"_id": 1, "total": 0,
...
"_id": 5, "total": 1,
...
"_id": 11, "total": 1,
...
"_id": 18, "total": 1,
...
}
}
Right now, I have used the aggregation framework with the following command:
db.col.aggregate( [ { $group: { _id: "$n1", total: { $sum: 1 } } }, { $sort: { _id: 1 } } ] )
To get desired result but only for one field (n1). I could iterate this process for all interesting fields, but I would like to know if there is a more compact query to get all at once.