Related
I would like to change _ to - in all .md files from folder FOO. The code below does what I need but I don't how to save results in folder FOO or some other...
$mdfiles = gci *.md
gc $mdfiles | ForEach-Object {if ( $_ -match '^!') {$_ -replace '_', '-'} else {$_}} | out-file ...
A ForEach-Object is needed to iterate over the file names as well. Ternary expressions are in PowerShell Core, but I am not sure about Windows PowerShell. This is not tested, but might give a start.
Get-ChildItem -File -Path '.' -Filter '*.md' |
ForEach-Object {
$OutFile = ".\foo\$($_.Name)"
Get-Content -Path $_.FullName |
ForEach-Object { ($_ -match '^!') ? ($_ -replace '_','-') : ($_) } |
Out-File -FilePath $OutFile
}
Also, it is bad practice to use alias commands in a stored script.
I have a script that I am working on that reads in some text files and converts them to .csv and changes some values. I have two different file sources. One is a tab delimited .txt file and the other is a comma separated .txt file. Is there a way to determine which type of delimiter is being used to determine which export function is appropriate?
get-childitem $workingDir -filter *.txt -Recurse| ForEach-Object {
$targetfile = $_.Name
$targetFile = $_.FullName.Substring(0,$_.FullName.Length-4)
$targetFile = $targetfile += ".csv"
if( Get-Content -Delimiter = `t ){
Write-Host "The file is tab-delimited"
Get-Content -path $_.FullName
ForEach-Object {$_ -replace â`tâ,â,â } |
Out-File -filepath $targetFile -Encoding utf8
}
else {
Write-Host "The file is comma-separated"
Get-Content -path $_.FullName |
Out-File -filepath $targetFile -Encoding utf8
}
}
Another approach would be to use Select-String to check for tab character and set delimiter.
if(Get-Content $csvfile -First 1 | Select-String -Pattern "`t")
{
$delim = "`t"
}
else
{
$delim = ','
}
Import-Csv $csvfile -Delimiter $delim
Assuming that the comma-separated files never contain tabs (which would then be data), the most efficient approach is to inspect only the first line of each file for the presence of tab characters, which is most easily done with (Get-Content -First 1 $_.FullName) -match "`t" - see Get-Content and -match, the regular-expression matching operator.
# Determine the arguments to pass to Set-Content - later, via splatting -
# for writing the output file.
$setContentArgs = #{
LiteralPath = $_.BaseName + '.csv'
Encoding = 'utf8'
}
# Check the 1st line for containing a tab.
# (This assumes that the comma-separated files contain not tabs as data.)
if ((Get-Content -First 1 $_.FullName) -match "`t") {
Write-Host "The file is tab-delimited."
# Read line by line, replace tabs with commas, and write with UTF-8 encoding.
Get-Content $_.FullName | ForEach-Object { $_ -replace "`t", ',' } |
Set-Content #setContentArgs
}
else {
Write-Host "The file is comma-separated."
# Just read lines as-is and write with UTF-8 encoding.
Get-Content $_.FullName |
Set-Content #setContentArgs
}
Note the use of the .BaseName property on the input [System.IO.FileInfo], which conveniently reports the file name without its extension, which allows you to simply append the new extension.
Since you're dealing with text (strings) only, Set-Content, which is slightly more efficient, is preferable to Out-File.
For the technique of passing arguments via a hashtable (#{ ... }), see about_Splatting
If the files are smallish (easily fit into memory as a whole (possibly twice) each), you can significantly speed up processing by reading each file as a whole with -Raw and using
-NoNewLine (PSv5+) to write that (possibly modified) string as-is, without appending a trailing newline, to the output file.
Since you're then reading the entire file anyway, you can get away with a single Get-Content call and apply -replace "`t", ',' blindly, given that for comma-separated files this will simply be a (fast) no op.
(Get-Content -Raw $_.FullName) -replace "`t", ',' |
Set-Content ($_.BaseName + '.csv') -Encoding Utf8 -NoNewLine
I will use Import-Csv for this:
If(Import-Csv "File path to test if Tab-delimited file" -Delimiter "`t" -Ea SilentlyContinue){
"File is tab-delimited"
}
If(Import-Csv "File path to test if Comma-CSV file" -Ea SilentlyContinue){
"File is a comma-separated CSV"
}
I would like remove all quotations character in my exported csv file, it's very annoying when i generated a new csv file and i need to manually to remove all the quotations that include in the string. Could anyone provide me a Powershell script to overcome this problem? Thanks.
$File = "c:\programfiles\programx\file.csv"
(Get-Content $File) | Foreach-Object {
$_ -replace """, ""
} | Set-Content $File
Next time you make one, export-csv in powershell 7 has a new option you may like:
export-csv -UseQuotes AsNeeded
It seems many of us have already explained that quotes are sometimes needed in CSV files. This is the case when:
the value contains a double quote
the value contains the delimiter character
the value contains newlines or has whitespace at the beginning or the end of the string
With PS version 7 you have the option to use parameter -UseQuotes AsNeeded.
For older versions I made this helper function to convert to CSV using only quotes when needed:
function ConvertTo-CsvNoQuotes {
# returns a csv delimited string array with values unquoted unless needed
[OutputType('System.Object[]')]
[CmdletBinding(DefaultParameterSetName = 'ByDelimiter')]
param (
[Parameter(Mandatory = $true, ValueFromPipeline = $true, ValueFromPipelineByPropertyName = $true, Position = 0)]
[PSObject]$InputObject,
[Parameter(Position = 1, ParameterSetName = 'ByDelimiter')]
[char]$Delimiter = ',',
[Parameter(ParameterSetName = 'ByCulture')]
[switch]$UseCulture,
[switch]$NoHeaders,
[switch]$IncludeTypeInformation # by default, this function does NOT include type information
)
begin {
if ($UseCulture) { $Delimiter = (Get-Culture).TextInfo.ListSeparator }
# regex to test if a string contains a double quote, the delimiter character,
# newlines or has whitespace at the beginning or the end of the string.
# if that is the case, the value needs to be quoted.
$needQuotes = '^\s|["{0}\r\n]|\s$' -f [regex]::Escape($Delimiter)
# a boolean to check if we have output the headers or not from the object(s)
# and another to check if we have output type information or not
$doneHeaders = $doneTypeInfo = $false
}
process {
foreach($item in $InputObject) {
if (!$doneTypeInfo -and $IncludeTypeInformation) {
'#TYPE {0}' -f $item.GetType().FullName
$doneTypeInfo = $true
}
if (!$doneHeaders -and !$NoHeaders) {
$row = $item.PsObject.Properties | ForEach-Object {
# if needed, wrap the value in quotes and double any quotes inside
if ($_.Name -match $needQuotes) { '"{0}"' -f ($_.Name -replace '"', '""') } else { $_.Name }
}
$row -join $Delimiter
$doneHeaders = $true
}
$item | ForEach-Object {
$row = $_.PsObject.Properties | ForEach-Object {
# if needed, wrap the value in quotes and double any quotes inside
if ($_.Value -match $needQuotes) { '"{0}"' -f ($_.Value -replace '"', '""') } else { $_.Value }
}
$row -join $Delimiter
}
}
}
}
Using your example to remove the unnecessary quotes in an existing CSV file:
$File = "c:\programfiles\programx\file.csv"
(Import-Csv $File) | ConvertTo-CsvNoQuotes | Set-Content $File
keeping in mind that this may trash your data if you have embedded double quotes in your data, here is yet another variation on the idea ... [grin]
what it does ...
defines the input & output full file names
grabs the *.tmp files from the temp dir
filters for the 1st three files & only three basic properties
creates the file to work with
loads the file content
replaces the double quotes with nothing
saves the cleaned file to the 2nd file name
displays the original & cleaned versions of the file
the code ...
$TestCSV = "$env:TEMP\Ted.Xiong_-_Test.csv"
$CleanedTestCSV = $TestCSV -replace 'Test', 'CleanedTest'
Get-ChildItem -LiteralPath $env:TEMP -Filter '*.tmp' -File |
Select-Object -Property Name, LastWriteTime, Length -First 3 |
Export-Csv -LiteralPath $TestCSV -NoTypeInformation
(Get-Content -LiteralPath $TestCSV) -replace '"', '' |
Set-Content -LiteralPath $CleanedTestCSV
Get-Content -LiteralPath $TestCSV
'=' * 30
Get-Content -LiteralPath $CleanedTestCSV
output ...
"Name","LastWriteTime","Length"
"hd4130E.tmp","2020-03-13 5:23:06 PM","0"
"hd418D4.tmp","2020-03-12 11:47:59 PM","0"
"hd41F7D.tmp","2020-03-13 5:23:09 PM","0"
==============================
Name,LastWriteTime,Length
hd4130E.tmp,2020-03-13 5:23:06 PM,0
hd418D4.tmp,2020-03-12 11:47:59 PM,0
hd41F7D.tmp,2020-03-13 5:23:09 PM,0
As above, the quotations are valid for csv, but to remove them you need to escape the quote mark in the replace operation as is a special character:
$File = "c:\programfiles\programx\file.csv"
(Get-Content $File) | Foreach-Object {
$_ -replace "`"", ""
} | Set-Content $File
Why are you manually in a text editor read Csv files?
You exported them to that format for a reason. To read them, just import them back in and view them on screen and or Read them back in and send the readout to notepad for reading.
Export-Csv -Path D:\temp\book1.csv
Import-Csv -Path D:\temp\book1.csv |
Clip |
Notepad # then press crtl+v, then save the notepad file with a new name.
If you don't want Csv, then don't export as Csv, just output as a flat-file, using Out-File instead.
Update
Since your last comment to me indicated your final use case. CSV into SQL is a very common thing. A quick web search will show you how even provide you with a script. You should also be looking at the PowerShell DBATools module.
How to import data from .csv in SQL Server using PowerShell?
Importing CSV files into a Microsoft SQL DB using PowerShell
ImportingCSVsIntoSQLv1.zip
Four Easy Ways to Import CSV Files to SQL Server with PowerShell
Find-Module -Name '*dba*'
<#
Version Name Repository Description
------- ---- ---------- -----------
1.0.101 dbatools PSGallery The community module that enables SQL Server Pros to automate database development and server administration
...
#>
Update
You mean this...
Get-Content 'D:\temp\book1.csv'
<#
# Results
"Site","Dept"
"Main","aaa,bbb,ccc"
"Branch1","ddd,eee,fff"
"Branch2","ggg,hhh,iii"
#>
Get-ChildItem -Path 'D:\temp' -Filter 'book1.csv' |
ForEach {
$NewFile = New-Item -Path 'D:\Temp' -Name "$($PSItem.BaseName).txt"
Get-Content -Path $PSItem.FullName |
ForEach-Object {
Add-Content -Path $NewFile -Value ($PSItem -replace '"') -WhatIf
}
}
<#
What if: Performing the operation "Add Content" on target "Path: D:\Temp\book1.txt".
What if: Performing the operation "Add Content" on target "Path: D:\Temp\book1.txt".
What if: Performing the operation "Add Content" on target "Path: D:\Temp\book1.txt".
What if: Performing the operation "Add Content" on target "Path: D:\Temp\book1.txt"
#>
Get-ChildItem -Path 'D:\temp' -Filter 'book1.csv' |
ForEach {
$NewFile = New-Item -Path 'D:\Temp' -Name "$($PSItem.BaseName).txt"
Get-Content -Path $PSItem.FullName |
ForEach-Object {
Add-Content -Path $NewFile -Value ($PSItem -replace '"')
}
}
Get-Content 'D:\temp\book1.txt'
<#
# Results
Site,Dept
Main,aaa,bbb,ccc
Branch1,ddd,eee,fff
Branch2,ggg,hhh,iii
#>
Of course, you need to use a wildcard for the csv files and use the -Resurse to get all directories and an error handler to make sure you don't have file name collisions.
One solution for dont remove the double quote into the string quoted :
$delimiter=","
$InputFile="c:\programfiles\programx\file.csv"
$OutputFile="c:\programfiles\programx\resultfile.csv"
#import file in variable (not necessary if your faile is big repeat this import where i use $ContentFile)
$ContentFile=import-csv $InputFile -Delimiter $delimiter -Encoding utf8
#list of property of csv file
$properties=($ContentFile | select -First 1 | Get-Member -MemberType NoteProperty).Name
#write header into new file
$properties -join $delimiter | Out-File $OutputFile -Encoding utf8
#write data into new file
$ContentFile | %{
$RowObject=$_ #==> get row object
$Line=#() #==> create array
$properties | %{$Line+=$RowObject."$_"} #==> Loop on every property, take value (without quote) inot row object
$Line -join $delimiter #==> join array for get line with delimer and send to standard outut
} | Out-File $OutputFile -Encoding utf8 -Append #==> export result to output file
An extra double quote can be used to escape a double quote in a string:
$File = "c:\programfiles\programx\file.csv"
(Get-Content $File) | Foreach-Object { $_ -replace """", "" } | Set-Content $File
After you have exported the CSV file with Export-CSV, you can use Get-Content to load the CSV file into an array of strings, then use Set-Content and replace to remove the quotation marks:
Set-Content -Path sample.csv -Value ((Get-Content -Path sample.csv) -replace '"')
As mklement0 helpfully pointed out, this could potentially corrupt the CSV if some lines need quoting. This solution simply goes through the whole file and replaces every quote with ''.
You could also speed this up with using the -Raw switch with Get-Content, which returns a whole string with the newlines preserved, instead of an array of newline delimited strings:
Set-Content -NoNewline -Path sample.csv -Value ((Get-Content -Raw -Path sample.csv) -replace '"')
I would like remove all quotations character in my exported csv file, it's very annoying when i generated a new csv file and i need to manually to remove all the quotations that include in the string. Could anyone provide me a Powershell script to overcome this problem? Thanks.
$File = "c:\programfiles\programx\file.csv"
(Get-Content $File) | Foreach-Object {
$_ -replace """, ""
} | Set-Content $File
Next time you make one, export-csv in powershell 7 has a new option you may like:
export-csv -UseQuotes AsNeeded
It seems many of us have already explained that quotes are sometimes needed in CSV files. This is the case when:
the value contains a double quote
the value contains the delimiter character
the value contains newlines or has whitespace at the beginning or the end of the string
With PS version 7 you have the option to use parameter -UseQuotes AsNeeded.
For older versions I made this helper function to convert to CSV using only quotes when needed:
function ConvertTo-CsvNoQuotes {
# returns a csv delimited string array with values unquoted unless needed
[OutputType('System.Object[]')]
[CmdletBinding(DefaultParameterSetName = 'ByDelimiter')]
param (
[Parameter(Mandatory = $true, ValueFromPipeline = $true, ValueFromPipelineByPropertyName = $true, Position = 0)]
[PSObject]$InputObject,
[Parameter(Position = 1, ParameterSetName = 'ByDelimiter')]
[char]$Delimiter = ',',
[Parameter(ParameterSetName = 'ByCulture')]
[switch]$UseCulture,
[switch]$NoHeaders,
[switch]$IncludeTypeInformation # by default, this function does NOT include type information
)
begin {
if ($UseCulture) { $Delimiter = (Get-Culture).TextInfo.ListSeparator }
# regex to test if a string contains a double quote, the delimiter character,
# newlines or has whitespace at the beginning or the end of the string.
# if that is the case, the value needs to be quoted.
$needQuotes = '^\s|["{0}\r\n]|\s$' -f [regex]::Escape($Delimiter)
# a boolean to check if we have output the headers or not from the object(s)
# and another to check if we have output type information or not
$doneHeaders = $doneTypeInfo = $false
}
process {
foreach($item in $InputObject) {
if (!$doneTypeInfo -and $IncludeTypeInformation) {
'#TYPE {0}' -f $item.GetType().FullName
$doneTypeInfo = $true
}
if (!$doneHeaders -and !$NoHeaders) {
$row = $item.PsObject.Properties | ForEach-Object {
# if needed, wrap the value in quotes and double any quotes inside
if ($_.Name -match $needQuotes) { '"{0}"' -f ($_.Name -replace '"', '""') } else { $_.Name }
}
$row -join $Delimiter
$doneHeaders = $true
}
$item | ForEach-Object {
$row = $_.PsObject.Properties | ForEach-Object {
# if needed, wrap the value in quotes and double any quotes inside
if ($_.Value -match $needQuotes) { '"{0}"' -f ($_.Value -replace '"', '""') } else { $_.Value }
}
$row -join $Delimiter
}
}
}
}
Using your example to remove the unnecessary quotes in an existing CSV file:
$File = "c:\programfiles\programx\file.csv"
(Import-Csv $File) | ConvertTo-CsvNoQuotes | Set-Content $File
keeping in mind that this may trash your data if you have embedded double quotes in your data, here is yet another variation on the idea ... [grin]
what it does ...
defines the input & output full file names
grabs the *.tmp files from the temp dir
filters for the 1st three files & only three basic properties
creates the file to work with
loads the file content
replaces the double quotes with nothing
saves the cleaned file to the 2nd file name
displays the original & cleaned versions of the file
the code ...
$TestCSV = "$env:TEMP\Ted.Xiong_-_Test.csv"
$CleanedTestCSV = $TestCSV -replace 'Test', 'CleanedTest'
Get-ChildItem -LiteralPath $env:TEMP -Filter '*.tmp' -File |
Select-Object -Property Name, LastWriteTime, Length -First 3 |
Export-Csv -LiteralPath $TestCSV -NoTypeInformation
(Get-Content -LiteralPath $TestCSV) -replace '"', '' |
Set-Content -LiteralPath $CleanedTestCSV
Get-Content -LiteralPath $TestCSV
'=' * 30
Get-Content -LiteralPath $CleanedTestCSV
output ...
"Name","LastWriteTime","Length"
"hd4130E.tmp","2020-03-13 5:23:06 PM","0"
"hd418D4.tmp","2020-03-12 11:47:59 PM","0"
"hd41F7D.tmp","2020-03-13 5:23:09 PM","0"
==============================
Name,LastWriteTime,Length
hd4130E.tmp,2020-03-13 5:23:06 PM,0
hd418D4.tmp,2020-03-12 11:47:59 PM,0
hd41F7D.tmp,2020-03-13 5:23:09 PM,0
As above, the quotations are valid for csv, but to remove them you need to escape the quote mark in the replace operation as is a special character:
$File = "c:\programfiles\programx\file.csv"
(Get-Content $File) | Foreach-Object {
$_ -replace "`"", ""
} | Set-Content $File
Why are you manually in a text editor read Csv files?
You exported them to that format for a reason. To read them, just import them back in and view them on screen and or Read them back in and send the readout to notepad for reading.
Export-Csv -Path D:\temp\book1.csv
Import-Csv -Path D:\temp\book1.csv |
Clip |
Notepad # then press crtl+v, then save the notepad file with a new name.
If you don't want Csv, then don't export as Csv, just output as a flat-file, using Out-File instead.
Update
Since your last comment to me indicated your final use case. CSV into SQL is a very common thing. A quick web search will show you how even provide you with a script. You should also be looking at the PowerShell DBATools module.
How to import data from .csv in SQL Server using PowerShell?
Importing CSV files into a Microsoft SQL DB using PowerShell
ImportingCSVsIntoSQLv1.zip
Four Easy Ways to Import CSV Files to SQL Server with PowerShell
Find-Module -Name '*dba*'
<#
Version Name Repository Description
------- ---- ---------- -----------
1.0.101 dbatools PSGallery The community module that enables SQL Server Pros to automate database development and server administration
...
#>
Update
You mean this...
Get-Content 'D:\temp\book1.csv'
<#
# Results
"Site","Dept"
"Main","aaa,bbb,ccc"
"Branch1","ddd,eee,fff"
"Branch2","ggg,hhh,iii"
#>
Get-ChildItem -Path 'D:\temp' -Filter 'book1.csv' |
ForEach {
$NewFile = New-Item -Path 'D:\Temp' -Name "$($PSItem.BaseName).txt"
Get-Content -Path $PSItem.FullName |
ForEach-Object {
Add-Content -Path $NewFile -Value ($PSItem -replace '"') -WhatIf
}
}
<#
What if: Performing the operation "Add Content" on target "Path: D:\Temp\book1.txt".
What if: Performing the operation "Add Content" on target "Path: D:\Temp\book1.txt".
What if: Performing the operation "Add Content" on target "Path: D:\Temp\book1.txt".
What if: Performing the operation "Add Content" on target "Path: D:\Temp\book1.txt"
#>
Get-ChildItem -Path 'D:\temp' -Filter 'book1.csv' |
ForEach {
$NewFile = New-Item -Path 'D:\Temp' -Name "$($PSItem.BaseName).txt"
Get-Content -Path $PSItem.FullName |
ForEach-Object {
Add-Content -Path $NewFile -Value ($PSItem -replace '"')
}
}
Get-Content 'D:\temp\book1.txt'
<#
# Results
Site,Dept
Main,aaa,bbb,ccc
Branch1,ddd,eee,fff
Branch2,ggg,hhh,iii
#>
Of course, you need to use a wildcard for the csv files and use the -Resurse to get all directories and an error handler to make sure you don't have file name collisions.
One solution for dont remove the double quote into the string quoted :
$delimiter=","
$InputFile="c:\programfiles\programx\file.csv"
$OutputFile="c:\programfiles\programx\resultfile.csv"
#import file in variable (not necessary if your faile is big repeat this import where i use $ContentFile)
$ContentFile=import-csv $InputFile -Delimiter $delimiter -Encoding utf8
#list of property of csv file
$properties=($ContentFile | select -First 1 | Get-Member -MemberType NoteProperty).Name
#write header into new file
$properties -join $delimiter | Out-File $OutputFile -Encoding utf8
#write data into new file
$ContentFile | %{
$RowObject=$_ #==> get row object
$Line=#() #==> create array
$properties | %{$Line+=$RowObject."$_"} #==> Loop on every property, take value (without quote) inot row object
$Line -join $delimiter #==> join array for get line with delimer and send to standard outut
} | Out-File $OutputFile -Encoding utf8 -Append #==> export result to output file
An extra double quote can be used to escape a double quote in a string:
$File = "c:\programfiles\programx\file.csv"
(Get-Content $File) | Foreach-Object { $_ -replace """", "" } | Set-Content $File
After you have exported the CSV file with Export-CSV, you can use Get-Content to load the CSV file into an array of strings, then use Set-Content and replace to remove the quotation marks:
Set-Content -Path sample.csv -Value ((Get-Content -Path sample.csv) -replace '"')
As mklement0 helpfully pointed out, this could potentially corrupt the CSV if some lines need quoting. This solution simply goes through the whole file and replaces every quote with ''.
You could also speed this up with using the -Raw switch with Get-Content, which returns a whole string with the newlines preserved, instead of an array of newline delimited strings:
Set-Content -NoNewline -Path sample.csv -Value ((Get-Content -Raw -Path sample.csv) -replace '"')
I'm doing a number of string replacements in a PowerShell script.
foreach ($file in $foo) {
$outfile = $outputpath + $file
$content = Get-Content ($file.Fullname) -replace 'foo','bar'
Set-Content -path $outfile -Force -Value $content
}
I've validated (through console logging of $outfile and $content, which I don't show in the above code) that the proper files are being selected, the -replace is accuratly updating the content, and the $outfiles are being created. However, each of the output files a 0 byte file. The Set-Content line does not appear to be writing the data to the files. I've tried piping Set-Content to Out-File, but that just gives me an error.
When I replace Set-Content with Out-File, I get a runtime error Out-File : A parameter cannot be found that matches parameter name 'path'. even though I can output $outfile to the console and see that it's a valid path.
Is there an additional step (like a close-File or save-file command) I need to take or a different order in which I need to pipe something to get the $content to write to my $outfile? What component am I missing?
The Out-File cmdlet does not have a -Path parameter, however it does have a -FilePath parameter. Here is an example of how to use it:
Out-File -FilePath test.txt -InputObject 'Hello' -Encoding ascii -Append;
You will also need to wrap the Get-Content command in parentheses, as it does not have a parameter called -replace.
(Get-Content -Path $file.Fullname) -replace 'foo','bar';
I'd also recommend adding the -Raw parameter to Get-Content, so that you ensure that you're only dealing with a single line of text, rather than an array of strings (one [String] per line in the text file).
(Get-Content -Path $file.Fullname -Raw) -replace 'foo','bar';
There isn't enough information to completely understand what's going on, but here is a filled out example of what I think you're trying to do:
# Create some dummy content (source files)
mkdir $env:SystemDrive\test;
1..5 | % { Set-Content -Path $env:SystemDrive\test\test0$_.txt -Value 'foo'; };
# Create the output directory
$OutputPath = mkdir $env:SystemDrive\test02;
# Get a list of the source files
$FileList = Get-ChildItem -Path $env:SystemDrive\test -Filter *.txt;
# For each file, get the content, replace the content, and
# write to new output location
foreach ($File in $FileList) {
$OutputFile = '{0}\{1}' -f $OutputPath.FullName, $File.Name;
$Content = (Get-Content -Path $File.FullName -Raw) -replace 'foo', 'bar';
Set-Content -Path $OutputFile -Value $Content;
}