Using puttys pscp -r folder\to\copy\* user#server:/path/to/copy/folder/to it only copies the content of path\to\copy\folder\* and does not include the "main" folder which the subfiles and subdirectories are in.
What I need is that the folder itself is also copied such that I get a folder with the same name as the one I copied with the content inside.
I know I just can create a parent-folder for the one I want to copy and parse that as the path\to\copy\folder\* but that is not the case
Just use pscp -r folder\to\copy user#server:/path/to/copy/folder/to.
Related
I'm unable to use the rm command to remove files remotely from another directory. I'm a beginner so I apologise for my inability to elaborate properly.
Here's what I'm trying to do:
I'm trying to delete all .srt files from a sub directory. It works when I cd into the specific directory like so:
Command 1:
cd /users/jakubdonovan/library/cloudstorage/iCloud\ drive/the-modern-python3-bootcamp/target_folder
Command 2:
rm *.srt
However, let's say I want to quickly delete a specific file type from a folder without first using the "cd" command, like so:
rm *.srt /users/jakubdonovan/library/cloudstorage/iCloud\ drive/the-modern-python3-bootcamp/target_folder
It returns with "No matches for wildcard '*.srt'. See help expand."
Which is strange because I can use the touch, cp and and all the other commands remotely without a problem.
Is there a way to make the command "rm *.filetype" remove all the files with that specific filetype from a folder and all its subfolders in one swoop?
If you would like to rm in a sub-directory you just have to specify that sub-directory in the command.
rm /path/to/folder/*.filetype
or if you know that the folder is inside your current directory you can try...
rm ./folder/*.filetype
Okay so I want to know how I would go about doing this, using grep to locate .txt files named "cocacola1", "cocacola2", "cocacola3" & then copying them to another directory. So searching for files named "cocacola" &/even if it contains other characters within the file name to then copy them to another directory/location.
You can just use unix find. Assuming the files you're searching for are in 'source' and you want to copy to 'destination':
find source -name '*cocacola*' -exec cp {} destination \;
I put the wildcard '*' before and after cocacola since you said other characters might exist in the file name.
Suppose I have a directory structure like
C:\Users\Desktop\abc\d
I want to rar archive the abc folder so that the structure of rar is:
abc\d
When I try using powershell to archive, winrar replicates the full path inside the archive, like:
\Users\Desktop\abc\d
I dont want the full path to be created inside the archive
Here's the script:
https://gist.github.com/saurabhwahile/50f1091fb29c2bb327b7
What am I doing wrong?
Use the command line:
Rar.exe a -r -ep1 Test.rar "C:\Users\Desktop\abc"
Rar.exe is the console version of WinRAR stored in same directory as WinRAR.exe. You can use this command line also with WinRAR.exe if you want to see the compression process in a graphic window.
a is the command and means add files to archive.
-r is a switch to recursively add all files and subdirectories including empty subdirectories to the archive.
-ep1 is another switch which results in execluding base directory.
For this command line the base directory is "C:\Users\Desktop\" and therefore the created archive Test.rar contains only abc and all files and subdirectories in directory abc which is what you want.
One more hint: Using the command line
Rar.exe a -r -ep1 Test.rar "C:\Users\Desktop\abc\"
results in adding all files and subdirectories of directory abc to the archive, but without directory name abc being also stored in the archive. The backslash at end makes this difference.
In other words: On using switch -ep1 everything up to last backslash in file/directory specification is not added to the archive.
For more information about available switches see the text file Rar.txt in the program files directory of WinRAR.
example
There is a file "sample.rar".
Folder structure is: "rising\dawn\ and here there are many (folders1, folders2 and file1, file2)" in this archive.
i have used following command
7z.exe x "sample.rar" "rising\dawn\*" -oi:\delete
The result is:
all files and folders in "rising\dawn\" are extracted to "i:\delete" folder but the empty parent folders "rising\dawn\" are also created in destination folder.
e.g. destination looks:
i:\delete\rising\dawn\folder1\file1.bmp
i:\delete\rising\dawn\folder2\subfolder
i:\delete\rising\dawn\file1.txt
i:\delete\rising\dawn\file2.txt
i don't want "rising\dawn\" empty folders to be created but the folder structure there onwards must be as is in the archive.
i want the result:
i:\delete\folder1\file1.bmp
i:\delete\folder2\subfolder
i:\delete\file1.txt
i:\delete\file2.txt
at last i found a way out solution. thanks to the winrar support. i have accepted it as an answer below.
if you find the question useful don't forget to click the up-vote button.
Finally this gave me the result.
Thanks to winrar support.
rar x -ep1 sample.rar rising\dawn\* d:\e\delete\
i have tried other answers given here, this is the only correct answer.
don't forget to upvote.
You can extract the archive normally and
1) move the lower level folder/files to where you would like it, then
2) remove the extra top level archive folders.
Code to do so will depend on the exact task.
Using e command instead of x and add -r option works well.
Like this:
7z.exe e -r "sample.rar" "rising\dawn\*" -oi:\delete
My executable version is "7-Zip [64] 9.20 2010-11-18",
And the platform is Windows 8.1.
This command line eliminates unnecessary parent folders and preserves the hierarchy of folders.
You need to use the e command rather than the x command:
7z.exe e "sample.rar" "scholar\update\*" -oi:\delete
Using e instead of x means 7zip will extract all matching files into the same folder (as specified via the -so switch, or the current directory if this isn't specified) rather than preserving the folder structure from inside the archive.
I'm trying to automate the install of my platform. I've made a script for compressing the build of the deployables to a 7zip file.
Now i need to uncompress partially some folders to a specific destination.
Package
-app1
--folder11
---folder111
--folder12
-app2
--folder21
--folder22
...
I need to create a powershell script to extract the content of 'app1' to a destination folder.
I've been trying to use the following command but the result is not the as i expected.
I've been receiving the full path and not the content from folder11 recursivelly.
Set-Alias zip $ZipCommand
zip x $FilePath app1\folder11 -oc:DeployableFolder -r
Any ideas? Suggestions?
Thanks.
I tried and had no issue.
set-alias zip "c:\Program Files\outils\7-Zip\7z.exe"
zip x program.7z python-core-2.6.1\lib -oc:\data
I eventually got a c:\data\python-core-2.6.1 which only contains the lib folder with all its subfolders & files.
The only difference I see is the backslash \ in the output path.
HTH