How to reference a Composite Secondary Key - jpa

The below examples show what I tried to reference an entity by a unique combination of columns that is not its primary key.
I want to do it that way because the referencing table contains all the necessary constituents of the referenced "Composite Secondary Key" but it does not contain the Primary Key.
How can I achieve this? (If possible without being Hibernate specific)
Base example
Suppose an entity has a primary key as well as a composite secondary key:
#Entity
#Table(name = "EXAMPLE_DATA",
uniqueConstraints = {
#UniqueConstraint(columnNames = {
"COMPOSITE_KEY_PART_1",
"COMPOSITE_KEY_PART_2"})
})
public class ExampleData {
#Id
#Column
private Long exampleDataId;
#Column(name = "COMPOSITE_KEY_PART_1")
private String compositeKeyPart1;
#Column(name = "COMPOSITE_KEY_PART_2")
private String compositeKeyPart2;
}
I would like to reference it from another table by its composite secondary key:
#Entity
#Table(name = "EXAMPLE")
public class Example {
#Id
#Column
private Long exampleId;
#Column(name = "COMPOSITE_KEY_PART_1")
private String compositeKeyPart1; // of ExampleData
#Column(name = "COMPOSITE_KEY_PART_2")
private String compositeKeyPart2; // of ExampleData
#MayToOne
#JoinColumn(name = "COMPOSITE_KEY_PART_1", insertable = false, updatable = false)
#JoinColumn(name = "COMPOSITE_KEY_PART_2", insertable = false, updatable = false)
private ExampleData exampleData;
}
However, this leads to
org.hibernate.AnnotationException:
A Foreign key refering com.example.ExampleData from com.example.Example has the wrong number of column. should be 1
Making a separate #Embeddable composite key
I tried making the secondary key embeddable
#Embeddable
public class CompositeKey implements Serializable {
#Column(name = "COMPOSITE_KEY_PART_1")
private String compositeKeyPart1;
#Column(name = "COMPOSITE_KEY_PART_2")
private String compositeKeyPart2;
}
and using it as an embedded object:
#Entity
#Table(name = "EXAMPLE_DATA",
uniqueConstraints = {
#UniqueConstraint(columnNames = {
"COMPOSITE_KEY_PART_1",
"COMPOSITE_KEY_PART_2"})
})
public class ExampleData {
#Id
#Column
private Long exampleDataId;
#Embedded
private CompositeKey compositeKey;
}
but that leads to the same exception:
org.hibernate.AnnotationException:
A Foreign key refering com.example.ExampleData from com.example.Example has the wrong number of column. should be 1
Using #EmbeddedId
Using #EmbeddedId instead of just #Embedded leads to issues with multiple keys
org.hibernate.AnnotationException:
com.example.CompositeKey must not have #Id properties when used as an #EmbeddedId: com.example.ExampleData.compositeKey
Having only a single key works but is undesirable
The only way I can actually make it work is by removing the primary key and making the composite key the primary key (but I don't want that)
#Entity
#Table(name = "EXAMPLE_DATA")
public class ExampleData {
// #Id // removing this primary key is undesirable
#Column
private Long exampleDataId;
#EmbeddedId // This now becomes the primary key
private CompositeKey compositeKey;
}

Related

Unable to create unique key constraint - Make sure that you use the correct column name which depends on the naming strategy in use

The full error message is:
Unable to create unique key constraint (aircraft_series_id, service_enum) on table aircraft_service: database column 'service_enum' not found. Make sure that you use the correct column name which depends on the naming strategy in use (it may not be the same as the property name in the entity, especially for relational types)
My entity is specified as:
#Entity
#Table(uniqueConstraints = { #UniqueConstraint(columnNames = { "aircraft_series_id", "service_enum" }) })
#Getter
#Setter
#NoArgsConstructor
#ToString
public class AircraftService {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#NotNull
private Integer minimumQuantity;
#NotNull
private Integer maximumQuantity;
#NotNull
private Integer defaultQuantity;
#NotNull
#ManyToOne(optional = false)
#JsonIgnore
private AircraftSeries aircraftSeries;
#NotNull
#Enumerated(EnumType.STRING)
private ServiceEnum serviceEnum;
}
If I comment out the #Table(uniqueConstraints = { #UniqueConstraint(columnNames = { "aircraft_series_id", "service_enum" }) }) annotation then the columns are created and I can see the field names when opening the table under the SQL client.
service_enum
aircraft_series_id
For now I'm running the application against the H2 database.
I could have the application running not throw an exception if the class is boasting the column annotations, as in:
#Column(name = "service_enum")
#ManyToOne(optional = false)
#JoinColumn(name = "service_profile_id")
I don't see why this is the case, as by default, the column names are exactly the same, when attributed by the application itself.

JPA Get an entity by intermediate entity

I have 3 entities named Student, Course, and StudentCourse as follows
#Entity
#Table(name = "student")
public class Student {
#Id
#GeneratedValue
private Integer id;
private String fullName;
}
#Entity
#Table(name = "course")
public class Course {
#Id
#GeneratedValue
private Integer id;
private String courseName;
}
#Entity
#Table(name = "student_course")
public class StudeCourse {
#Id
#GeneratedValue
private Integer studentId;
private Integer courseId;
private String extraColumn;
}
Restrictions: There are a couple of restrictions
One student can have only one course or no course at all
An extra entity (StudentCourse) is required to hold the relation with primary key as studentId only
StudentCourse is required and hence cannot be skipped
Get Student with Course entity if there is one registered
Help required in some magical code to retrieve Course of Student if there is one assigned.
#Entity
#Table(name = "student")
public class Student {
#Id
#GeneratedValue
private Integer id;
private String fullName;
// this is not correct code but just what I want
#JoinEntity(entity=StudentCourse, column="courseId")
private Course course;
}
StudentCourse is required and hence cannot be skipped
Ok, lets work with that.
One student can have only one course or no course at all
Implies that there is a #OneToOne relationship between Student and StudentCourse.
With the given information, the following entity model will work:
#Entity
#Table(name = "student")
public class Student {
#Column(name = "id")
#Id
#GeneratedValue
private Integer id;
#Column(name = "full_name")
private String full_name;
#OneToOne
#PrimaryKeyJoinColumn
private StudentCourse studentCourse;
}
#Entity
#Table(name = "student_course")
public class StudentCourse {
#Column(name = "id")
#Id
#GeneratedValue
private Integer id;
#JoinColumn(name = "id", nullable = false, updatable = false)
#MapsId
#OneToOne
private Student student;
#JoinColumn(name = "course_id")
#ManyToOne
private Course course;
...
}
A quick review:
#OneToOne on the Student.studentCourse field signifies that for every Student, there can be only one StudentCourse, and no more.
#PrimaryKeyJoinColumn on the Student.studentCourse field signifies that the value of the primary key column for Student should be used as the foreign key for the related entity, that is, StudentCourse.
#OneToOne on the StudentCourse.student field signifies that for every StudentCourse, there can be only one Student.
#MapsId on the StudentCourse.student field signifies that the primary key column for StudentCourse should be used as the join column for the association.
To check if a student has a course assigned, simply check if student.getStudentCourse() != null and then get the assigned course as student.getStudentCourse().getCourse().

How to name Foreign Key with #CollectionTable in JPA?

I need help with resolving our problem with naming FK in JPA. We have one embeddable entity e.g. Foo which is used as collection in another one entity Bar.
embeddable entity:
#Embeddable
public class Foo{
#Column(name = "foo1")
private String foo1;
#Column(name = "foo2")
private String foo2;
}
main entity:
#Entity
#Table(name = "Bar")
public class Bar {
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "id")
#Id
private Long id;
#ElementCollection
#CollectionTable(name = "foos", joinColumns = #JoinColumn(name = "bar_id", foreignKey = #ForeignKey(name = "foo_bar_fk"), nullable = false))
private List<Bar> bars;
}
When I generated tables in database (postgres) foreign key is called fdk44l345k64 instead foo_bar_fk. Can you tell me how to fix it? Thanks.

Exception while persisting JPA object in DB having one to many relation

hi have two tables in picture table a and table b as follows :
#Entity
#Table(name = "A")
public class A implements Serializable {
#Id
#SequenceGenerator(name = "JOURNAL_CATEGORY_ID_GENERATOR", allocationSize = 1, sequenceName = "clm_jounal_category_config_seq")
#GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "JOURNAL_CATEGORY_ID_GENERATOR")
#Column(name = "CLAIM_ID")
private String claimId;
#Column(name = "name")
private String name;
#OneToMany(cascade = CascadeType.ALL, mappedBy = "country")
private List<ClaimDTLS> claimDetails;
}
B Primary Key:
#Embeddable
public class BPK implements Serializable {
#Column(name = "code")
private String code;
#Column(name = "CLAIM_ID")
private String claimId;
}
B Entity:
#Entity
#Table(name = "B")
public class B implements Serializable {
#EmbeddedId
protected BPK bpk;
#Column(name = "name")
private String name;
#MapsId("country_code")
#JoinColumn(name = "claimId", referencedColumnName = "claimId", insertable = false, updatable = false)
#ManyToOne
private A a;
}
when i try to persist object of A type in Db the value of table b claim id is not set and is intialized with zero.
Also primary key of table A is generated with a oracle sequence.
any help will be welcomed.
thanks in advance
Sequence values are numbers and when JPA use them as a generator it call the setter method of the entity PK. Now, you defined your PK as a string while you use a sequence and so no matching setter can be found. Change the type of you PK to be Long and things shall work

#ElementCollection of #Embeddable containing #ManyToOne

I have the following model
#Entity
#Table(name = "GRAPH")
public class Graph {
[...]
#ElementCollection
#CollectionTable(name = "ROOT", joinColumns = #JoinColumn(name = "GRAPH", nullable = false))
private Set<Root> roots;
}
#Entity
#Table(name = "NODE")
public class Node {
[...]
}
#Embeddable
public class Root {
[...]
#ManyToOne(optional = false)
#JoinColumn(name = "NODE", nullable = false)
private Node node;
}
I use EclipseLink as the JPA Provider. When letting EclipseLink generate the DDL for this structure, the following stuff happens:
The is no primary key on the ROOT table (OK, it is an #Embeddable, and it does not have an identity)
A foreign key is generated from ROOT.GRAPH to GRAPH.ID (As expected)
There is no foreign key from ROOT.NODE to NODE.ID (That's something I can not understand)
Can you help explain me the cause for this behavior? Is there something that can be done about the primary key and the missing foreign key?
Thanks,
M.