File name with full path & number of rows in the file - powershell

Question

I'm able to get the file name, number of rows in the file and file size, but unable to get the file's full path.
$measure = Get-Content C:\Users\Documents\Daily_files_YYYY-MM-DD.txt | Measure-Object
$lines = $measure.Count
echo "line count is: ${lines}"
Get-ChildItem C:\Users\Documents\ -Recurse|
? {! $_.PSIsContainer} |
Select-Object Name, #{Name='Size'; Expression={([string]([int]($_.Length / 1KB))) + " KB"}}
How can i get in the below format?
File Name : Daily_files_2019-01-10.txt
Path : C:\Users\Documents\
Line count is: 27723
File Size : 23 KB or MB or GB

Answer 1

Use Get-Content and expand the ReadCount property to get the number of lines. The full path to the directory of a file is stored in its DirectoryPath property.
Get-ChildItem 'C:\Users\Documents' -Recurse |
Where-Object {-not $_.PSIsContainer} |
Select-Object #{n='File Name';e={$_.Name}}, #{n='Path';e={$_.DirectoryPath}},
#{Get-Content $_.FullName | Select-Object -Expand ReadCount -Last 1}},
#{n='File Size';e={$_.Length}}
I would not recommend doing calculations with the file size or converting it to a string unless the value is meant solely for (human-readable) output.
Note that PowerShell v3 introduced a new parameter -Directory for Get-ChildItem, so you don't need the extra Where-Object pipeline step when using a recent enough version.