This question already has answers here:
How to work with Unix timestamps in Matlab?
(2 answers)
Closed 3 years ago.
I have a unix timestamp (1.500641224636246e+09) and I am not sure how to extract whether it is AM or PM time from it via MATLAB.
You can combine timeofday and datetime:
>> timestamp = timeofday(datetime(1.500641224636246e+09,'ConvertFrom','posixtime'));
>> isPM = timestamp > hours(12) + minutes(0) + seconds(0)
isPM =
logical
1
Related
This question already has answers here:
How to format current time using a yyyyMMddHHmmss format?
(6 answers)
Convert time.Time to string
(6 answers)
Parsing RFC-3339 / ISO-8601 date-time string in Go
(8 answers)
Parse string as a time.Time value [duplicate]
(1 answer)
Parsing date/time strings which are not 'standard' formats
(4 answers)
Closed 2 months ago.
I have a date string I can't control that I'm trying to parse into a Date.
The format most closely resembles RFC822Z.
RFC822Z = "02 Jan 06 15:04 -0700"
Reference: https://yourbasic.org/golang/format-parse-string-time-date-example/
However, it does not have the leading zero.
Example: "5 Dec 2022 20:15:21 +0000"
The way I saw in other posts, is to write a manual format.
parseTime, timeParseError = time.Parse("2 Jan 2006 15:04:21 -0700", stringDate)
However, when I try that, I get a warning:
parsing time "2 Jan 2006 15:04:21 -0700" as "2 Jan 2006 15:04:21 -0700": cannot parse " -0700" as "1" (SA1002)
Running it despite the warning fails to part, unsurprisingly.
Your time format doesn't match - in your example you have "5 Dec 2022", but you are using "2 Jan 06", and in your reference format you hvae "15:04:21" but it should be "15:04:05".
Your reference format should be 2 Jan 2006 15:04:05 -0700 not 2 Jan 06 15:04:21 -0700
https://go.dev/play/p/Shc381WgB6_7
This question already has answers here:
How to format DateTime in Flutter
(16 answers)
Closed 2 years ago.
I want to output my date like this " Today is Feb 25, 2018 ", it is possible? using intl package?
May be you can try to use formatDate
For example:
Text('Today is 'formatDate(checkDate, [dd, '/', mm, '/', yyyy, ' '])
This question already has answers here:
Extracting only date portion from LastLogonDate
(3 answers)
Closed 3 years ago.
I'm running a powershell script and exporting the output for a rapport.
Tried different format possibilities to change dd-MM-YYYY HH-MM-SS to just showing dd-MM-YYYY but can't figure it out
#{Name="Date"; Expression={[DateTime]::FromFileTime($_.LastLogonTimestamp)}}
I'm getting 30-10-2017 10:07:10 and only want to get the output 30-10-2017
Just convert them to the required format using the below statement.
#{Name="Date"; Expression={[DateTime]::FromFileTime($_.LastLogonTimestamp).ToString('dd-MM-yyyy')}}
Check this documentation for more reference!
https://learn.microsoft.com/en-us/dotnet/standard/base-types/custom-date-and-time-format-strings
https://learn.microsoft.com/en-us/dotnet/standard/base-types/standard-date-and-time-format-strings
If you already have the value as a DateTime, e.g.
$date = [DateTime]::FromFileTime($_.LastLogonTimestamp)
You can use one of the ToString overloads provided by the object type, e.g.
$formattedDate = $date.ToString("dd-MM-yyyy")
You can get further information about formatting options on this link.
This question already has answers here:
Counting characters in a specific text file
(4 answers)
Closed 4 years ago.
I have data in a file like below.
text1|text2
text3|text4|
I'm looking for a Power Shell command to count number of pipes present in thisfile.
Normally I would want you to show some effort but this is trivial enough I won't bother:
$pipeCount = (get-content file.txt -Raw).Split('|').count - 1
$pipeCount
This question already has answers here:
How do I convert a date/time to epoch time (unix time/seconds since 1970) in Perl?
(14 answers)
Closed 6 years ago.
I need a quick way to convert date "Tue Jul 02 17:50:55 MDT 2024" into epoch time.
Effectively, I need the shell equivalent of date -d "Tue Jul 02 17:50:55 MDT 2024" +%s
I currently use the following in perl but it requires a lot of conversion. Hoping to find a simpler and more elegant solution.
$current_epoch = timelocal($seconds, $minute, $hour, $day_of_month, $month_num, $year)
I currently use Perl 5.8 ; I dont believe it has "Time::Piece"
I am only interested in solutions that do not require downloading another library
The Date::Parse module can turn datetime stamps into epoch times. In general, if you have something you need to do, search the Comprehensive Perl Archive Network for a module to handle it. Searching Stackoverflow is another good way to get answers to common questions.