Swift sort of array always in ascending order - swift

Question

i try to show a array list sorted by its Timestamp in an descending order (newest first --> highest ts first) therefore i created a downloading method and a sorting method:
func getBlogsByAuthor(){
self.allBlogs.removeAll()
for authorId in self.authorIds{
db.collection("Blogs").whereField("authorId", isEqualTo: authorId)
.getDocuments() { (querySnapshot, err) in
if let err = err {
print("Error getting documents: \(err)")
} else {
for document in querySnapshot!.documents {
let ts = document.get("ts") as! Int
let title = document.get("title") as! String
let body = document.get("body") as! String
let authorId = document.get("authorId") as! String
let state = document.get("stateios") as? String
let imageUrl = document.get("imageUrl") as! String
let id = document.documentID as! String
let blogObject = BlogObject.init(title: title , body: body, imageUrl: imageUrl , authorId: authorId , state: state ?? "Null" , id: id, ts: ts )
self.allBlogs.append(blogObject)
}
self.sortDataset()
}
}
}
}
func sortDataset(){
self.allBlogs.sorted(by: { $0.ts! < $1.ts! })
self.rv.reloadData()
}
The problem is that the values are showing always the lowest ts first no matter if i change it from self.allBlogs.sorted(by: { $0.ts! < $1.ts! })
to self.allBlogs.sorted(by: { $0.ts! > $1.ts! })

Answer 1

You need
self.allBlogs.sort { $0.ts! < $1.ts! } // mutating sort in place
as sorted(by returns a result that you ignore it and don't re-assign it would be
self.allBlogs = self.allBlogs.sorted(by: { $0.ts! < $1.ts! })