I want to keep the output of this command on the same line:
((Get-ADUser -filter {employeetype -eq "Employee"}).SamAccountName) | Sort-Object | Get-ADUser | ForEach-Object {$_.Name,$_.Department,$_mail}
Currently the output shows up like this:
James Roberts
Accounting
jroberts#email.tld
But, I need to have it show up like:
James Roberts Accounting jroberts#email.tld
I've also tried using (based on a suggestion I found):
((Get-ADUser -filter {employeetype -eq "Employee"}).SamAccountName) | Sort-Object | Get-ADUser | ForEach-Object {$_.Name;$_.Department;$_mail}
but, I get the same three lines of output and not one line.
If you want to create customized objects:
… | Select-Object -Property Name,Department,Mail
If you want to make strings:
… | ForEach-Object { $_.Name,$_.Department,$_.Mail -join " " }
If you just want to display the table nicely (not going to use this output afterwards):
… | Format-Table -Property Name,Department,Mail -AutoSize
Related
I am looking to see what the cleaner way of writing this one liner would be.
Get-AdGroup -Filter * -Properties Name,Description,whenCreated,whenChanged,ObjectClass,GroupCategory,GroupScope,SamAccountName,DistinguishedName |
Sort-Object Name |
Select-Object Name,Description,whenCreated,whenChanged,ObjectClass,GroupCategory,GroupScope,SamAccountName,DistinguishedName |
Select *,#{Name="Members";Expression={Get-ADGroupMember $_.Name | %{$_.SamAccountName+';'}}} |
Export-Csv -Path .\Group.csv -NoTypeInformation
And assign the property names to a variable so they are written out in full twice, and combine Select-Object and select together:
$properties = "Name,Description,whenCreated,whenChanged,ObjectClass,GroupCategory,GroupScope,SamAccountName,DistinguishedName";
Get-AdGroup -filter * -properties $properties |
Select-Object $properties,#{Name="Members";Expression={Get-ADGroupMember $_.Name | %{$_.SamAccountName+';'}}} |
Sort-Object Name |
Export-Csv -Path .\Group.csv -NoTypeInformation
Note: It's a one liner command but I've spaced it out for readability.
I'm trying to get a dump of all user records and their associated groups for a user ID revalidation effort. My security officer wants it in CSV format.
This works great:
Get-ADUser -Filter * -Properties * | Select-Object -Property Name,SamAccountName,Description,EmailAddress,LastLogonDate,Manager,Title,Department,whenCreated,Enabled,Organization | Sort-Object -Property Name | ConvertTo-CSV
However, that does not include the groups the user is a member of.
Attempts at something like this have failed:
Get-ADUser -Filter * -Properties * | Select-Object -Property Name,SamAccountName,Description,EmailAddress,LastLogonDate,Manager,Title,Department,whenCreated,Enabled,Organization, #{$_.MemberOf |Get-Group|ForEach-Object {$_.Name}} | Sort-Object -Property Name | ConvertTo-CSV
This also failed:
Get-ADUser -Filter * -Properties * | Sort-Object -Property Name | ForEach-Object {
$_ | Format-List -Property Name,SamAccountName,Description,EmailAddress,LastLogonDate,Manager,Title,Department,whenCreated,Enabled
$_.MemberOf | Get-ADGroup | ForEach-Object {$_.Name} | Sort-Object
} | ConvertTo-CSV
I'm probably missing something simple.
Any help would be greatly appreciated.
Thanks!
From a Windows Server OS execute the following command for a dump of the entire Active Director:
csvde -f test.csv
This command is very broad and will give you more than necessary information. To constrain the records to only user records, you would instead want:
csvde -f test.csv -r objectClass=user
You can further restrict the command to give you only the fields you need relevant to the search requested such as:
csvde -f test.csv -r objectClass=user -l DN, sAMAccountName, department, memberOf
If you have an Exchange server and each user associated with a live person has a mailbox (as opposed to generic accounts for kiosk / lab workstations) you can use mailNickname in place of sAMAccountName.
For posterity....I figured out how to get what I needed. Here it is in case it might be useful to somebody else.
$alist = "Name`tAccountName`tDescription`tEmailAddress`tLastLogonDate`tManager`tTitle`tDepartment`tCompany`twhenCreated`tAcctEnabled`tGroups`n"
$userlist = Get-ADUser -Filter * -Properties * | Select-Object -Property Name,SamAccountName,Description,EmailAddress,LastLogonDate,Manager,Title,Department,Company,whenCreated,Enabled,MemberOf | Sort-Object -Property Name
$userlist | ForEach-Object {
$grps = $_.MemberOf | Get-ADGroup | ForEach-Object {$_.Name} | Sort-Object
$arec = $_.Name,$_.SamAccountName,$_.Description,$_.EmailAddress,$_LastLogonDate,$_.Manager,$_.Title,$_.Department,$_.Company,$_.whenCreated,$_.Enabled
$aline = ($arec -join "`t") + "`t" + ($grps -join "`t") + "`n"
$alist += $aline
}
$alist | Out-File D:\Temp\ADUsers.csv
csvde -f test.csv
This command will perform a CSV dump of every entry in your Active Directory server. You should be able to see the full DN's of users and groups.
You will have to go through that output file and get rid off the unnecessary content.
the first command is correct but change from convert to export to csv, as below,
Get-ADUser -Filter * -Properties * `
| Select-Object -Property Name,SamAccountName,Description,EmailAddress,LastLogonDate,Manager,Title,Department,whenCreated,Enabled,Organization `
| Sort-Object -Property Name `
| Export-Csv -path C:\Users\*\Desktop\file1.csv
HI you can try this...
Try..
$Ad = Get-ADUser -SearchBase "OU=OUi,DC=company,DC=com" -Filter * -Properties employeeNumber | ? {$_.employeenumber -eq ""}
$Ad | Sort-Object -Property sn, givenName | Select * | Export-Csv c:\scripts\ceridian\NoClockNumber_2013_02_12.csv -NoTypeInformation
Or
$Ad = Get-ADUser -SearchBase "OU=OUi,DC=company,DC=com" -Filter * -Properties employeeNumber | ? {$_.employeenumber -eq $null}
$Ad | Sort-Object -Property sn, givenName | Select * | Export-Csv c:\scripts\cer
Hope it works for you.
I run this command and I get all computer hostnames in the names.txt file.
Each hostname in the file is on a separate line, but every hostname is followed with white spaces which cause an issue when I try to read this file. How can I output to this file without getting the white spaces on each line?
Get-ADComputer -Filter * | Select-Object -property name | Sort-Object -Property name | out-file -filepath C:\temp\names.txt
You have the problem that you don't just have names, you have objects with the property 'name', and you also have the problem that Out-File runs complex objects through some kind of formatting before sending them to the file.
To fix both, expand the name out to just text, and generally use Set-Content instead:
Get-ADComputer -filter * | Select-Object -ExpandProperty Name | Sort-Object | Set-Content C:\temp\names.txt
or in short form
Get-ADComputer -filter * | Select -Expand Name | Sort | sc C:\temp\names.txt
or
(Get-ADComputer -filter *).Name | sort | sc C:\temp\names.txt
expandproperty should get rid of the #()
Get-ADComputer -Filter * | sort Name | Select -expandproperty Name | %{ $_.TrimEnd(" ") } | out-file -filepath C:\temp\names
Untested no AD#home
Piping it through this should work (before piping to the out-file):
EDIT: Piping through % { $_.name } should convert #{name=VALUE} to VALUE:
% { $_ -replace ' +$','' } | % { $_.name }
Like this:
Get-ADComputer -Filter * | Select-Object -property name | Sort-Object -Property name | % { $_ -replace ' +$','' } | % { $_.name } | out-file -filepath C:\temp\names.txt
I'm new to scripting with Powershell for Active Directory, and attempting to pull out users in a list and enumerating their groups; however when I do so the resultant information contains just the name of the group which is duplicated under many differently named OUs. Looking at them in AD Users and Computers under the Member Of tab shows the Name and the Active Directory Domain Services Folder which contains exactly the differentiating info I need, or alternately I could use the DistinguishedName which isn't as nicely formatted for readability but would also work.
Problem with simplified examples: If a group name is the same across different OUs (like "TestUsers") then the script currently dumps multiple group names without differentiation "TestUsers, TestUsers, TestUsers" instead of showing the underlying OUs in a clean format "Michigan\TestUsers, NewYork\TestUsers" or Distinguished Name format "CN=TestUsers,CN=Michigan,etc";"CN=TestUsers,CN=NewYork,etc".
$alist = "Name`tAccountName`tDescription`twhenCreated`tAcctEnabled`tGroups`n"
$userlist = Get-ADUser -SearchBase "OU=Service Accounts,OU=Information Systems,DC=conteso,DC=local" -Filter * -Properties * | Select-Object -Property Name,SamAccountName,Description,EmailAddress,LastLogonDate,Manager,Title,Department,Company,whenCreated,Enabled,MemberOf | Sort-Object -Property Name
$userlist | ForEach-Object {
$grps = $_.MemberOf | Get-ADGroup | ForEach-Object {$_.Name} | Sort-Object
$arec = $_.Name,$_.SamAccountName,$_.Description,$_.whenCreated,$_.Enabled
$aline = ($arec -join "`t") + "`t" + ($grps -join "`t") + "`n"
$alist += $aline
}
$alist | Out-File C:\psscripts\service_accounts_groups.csv
Any help is appreciated!
I agree that DistinguishedName already has this information but I think it is easier to just use Get-AdGroup to get some friendlier information. A little string manipulation on the CanonicalName of the group, while not as efficient maybe, would be easier to work with.
$grps = $_.MemberOf | Get-AdGroup -Properties CanonicalName | ForEach-Object{
$CN = ($_.CanonicalName -Split "/")
"{0}\{1}" -f $CN[-2],$CN[-1]
}
or as a one liner if you prefer.
$grps = $_.MemberOf | Get-AdGroup -Properties CanonicalName | ForEach-Object{$CN = ($_.CanonicalName -Split "/"); "{0}\{1}" -f $CN[-2],$CN[-1]}
What we do is take the CanonicalName which can be considered the path of the object in Active Directory. Since you only wanted the parent container we split up the path and join only the last two parts. The group object and its container.
Same result could come from just getting the second last element from CanonicalName and appending the group name to it. Might look at little nicer
$grps = $_.MemberOf | Get-AdGroup -Properties CanonicalName | ForEach-Object{"{0}\{1}" -f ($_.CanonicalName -Split "/")[-2],$_.Name}
Since the "$_.memberof" property already has the Distinguished name, you don't need to pass it to Get-Adgroup again. so simply replace your $grps line like this
$grps = $_.MemberOf -replace "CN=","" -replace "OU=","" -replace "DC=","" -replace ",","\" | Sort-Object
Or if you still want to proceed with your approach, use it with distinguishedname property instead of name property - like this (with the text replace)
$grps = $_.MemberOf | Get-ADGroup | ForEach-Object {$_.DistinguishedName -replace "CN=","" -replace "OU=","" -replace "DC=","" -replace ",","\"} | Sort-Object
Or as suggested by Matt in the comment, simply use canonicalname property.
$grps = $_.MemberOf | Get-ADGroup -Properties canonicalname | select -ExpandProperty canonicalname
Cheers, GJ
Get-WmiObject -list | where-object {$_.name -match "win32"} | Select-Object
name,methods,properties
This displays the name, methods and properties of each Win32 class and I wanted to get this information into a CSV file.
The following however outputs doesn't output the same information.
Get-WmiObject -list | where-object {$_.name -match "win32"} | Select-Object
name,methods,properties | Export-CSV "c:\output.csv"
How can I do this?
(Updated my script as it had an error.)
You need to do some extra manual work and make sure you expand the names and join them by some delimiter:
$methods = #{n='Methods';e={ ($_.Methods | select -expand Name) -join ';'}}
$properties = #{n='Properties';e={ ($_.Properties | select -expand Name) -join ';'}}
Get-WmiObject -List |
Where-Object {$_.Name -like "Win32_*"} |
Select-Object Name,$methods,$properties |
Export-Csv .\win32.csv -NoTypeInformation
The problem here is that each WMI Object has properties that themselves are arrays and Output-CSV can't really handle that.
To fix this, you'd need to handle the arrays of arrays explicitly.
WHat specifically do you want to be output?