I can create a value in YAML as such:
MYVAL: 1
I can load this in my PERL as follows:
my $settings = YAML::XS::LoadFile...
my $number_mine = $settings->{'MYVAL'};
I would want to create now an array of strings in YAML.
I tried using - and --- but not seeing it
YAML?
MYARRAY: str1,str2,str3
PERL:
my #array_mine = $settings->{'MYARRAY'};
This:
MYARRAY: str1,str2,str3
is a YAML mapping, the same way as your
MYVAL: 1
is a YAML mapping. The difference is that the value for the key MYARRAY is a plain (i.e. non quoted) scalar string str1,str2,str3 and for the value MYVAL is the scalar integer 1
If you want a sequence of three strings as value on a single line, you would need to do:
MYARRAY: [str1,str2,str3]
(optionally with whitespace before and/or after the commas). That is a flow style sequence of three plain scalars: str1, str2 and str3.
An alternative is to use block style:
MYARRAY:
- str1
- str2
- str3
which is semantically equivalent to the flow style example above.
Dump out a list and see what it looks like:
$ perl -MYAML -E 'say YAML::Dump( { MYARRAY => ["str1","str2","str3"] })'
---
MYARRAY:
- str1
- str2
- str3
Related
I have a spark scala dataframe which has column "Name"
I have extracted the values of that column in to scala array[string]
org_name: Array[String] = Array(SARATOGA SENIOR HIGH SCHOOL)
I want to replace whitespaces with _ and encode that value in to utf-8 (any encoding is fine as long as it replaces special chars with something else)
so if there are any special chars those will be removed. later i want to use those in file path .
var org_name = orgsFlatDF.rdd.collect
.map( _.getString(2))
This is how i am extracting those vals ^^. I haven't found any method which I can use to do that. Replace or replaceall doesn't work on array
I tried this :
org_name.replace("\\s", "")
That didn't work .
Expected output : SARATOGA_SENIOR_HIGH_SCHOOL
if name is : new $ high school it should gets converted to new_$_high_school then encoded to new_%24_high_school
There are a couple of issues with what you are asking.
Java/Scala Arrays don't have a replace method. Even if they did have a replace method, would they replace the values they hold or the characters in a String they hold?
Let's assume this line org_name.replace("\\s", "") didn't compiled and org_name is indeed a an Array[String] holding one element.
scala> val org_name=Array("SARATOGA SENIOR HIGH SCHOOL")
val org_name: Array[String] = Array(SARATOGA SENIOR HIGH SCHOOL)
scala> org_name(0).replace(" ","_")
val res15: String = SARATOGA_SENIOR_HIGH_SCHOOL
replace("\\s","_") wouldn't work because it represents a \s string. "\" represents \. That's only way you'd be able to define strings containing other escape codes like \n or \t.
PS: to transform all the string in the array use org_name.map(_.replace(" ","_")), this gives you back another another array.
I am using Swift 4.2. I am getting extraneous characters when formatting one string (s1) from another string(s0) using the %# format code.
I have searched extensively for details of string formatting but have come up with only partial answers including the code in the second line below. I need to be able to format s1 so that I can customize output from a Swift process. I ask this because I have not found an answer while searching for ways to format a string from a string.
I tried the following three statements:
let s0:[String] = ["abcdef"]
let s1:[String] = [String(format:"%#",s0)]
print(s1)
...
The output is shown below. It may not be clear, here, but there are four leading spaces to the left of the abcdef string.
["(\n abcdef\n)"]
How can I format s1 so it does not include the brackets, the \n escape characters, and the leading spaces?
The issue here is you are using an array but a string in s0.
so the following index will help you.
let s0:[String] = ["abcdef"]
let s1:[String] = [String(format:" %#",s0[0])]
I am getting extraneous characters when formatting one string (s1) from another string (s0) ...
The s0 is not a string. It is an array of strings (i.e. the square brackets of [String] indicate an array and is the same as saying Array<String>). And your s1 is also array, but one that that has one element, whose value is the string representation of the entire s0 array of strings. That’s obviously not what you intended.
How can I format s1 so it does not include the brackets, the \n escape characters, and the leading spaces?
You’re getting those brackets because s1 is an array. You’re getting the string with the \n and spaces because its first value is the string representation of yet another array, s0.
So, if you’re just trying to format a string, s0, you can do:
let s0: String = "abcdef"
let s1: String = String(format: "It is ‘%#’", s0)
Or, if you really want an array of strings, you can call String(format:) for each using the map function:
let s0: [String] = ["abcdef", "ghijkl"]
let s1: [String] = s0.map { String(format: "It is ‘%#’", $0) }
By the way, in the examples above, I didn’t use a string format of just %#, because that doesn’t accomplish anything at all, so I assumed you were formatting the string for a reason.
FWIW, we generally don’t use String(format:) very often. Usually we do “string interpolation”, with \( and ):
let s0: String = "abcdef"
let s1: String = "It is ‘\(s0)’"
Get rid of all the unneccessary arrays and let the compiler figure out the types:
let s0 = "abcdef" // a string
let s1 = String(format:"- %# -",s0) // another string
print(s1) // prints "- abcdef -"
Suppose I have a char variable in Matlab like this:
x = 'hello my name $ is Sean $ Daley.';
I want to replace the first '$' with the symbol '&', and the second '$' with the symbol '#'.
Furthermore, if I have a more complicated char such that pairs of '$' repeat many times, I want to repeat the same pattern. So the following:
y = 'hello $ my $ name is $ Sean $ Daley $.$.';
would be transformed into:
'hello & my # name is & Sean # Daley &.#.'
I have tried coding this manually via for loops and while loops, but the code is just so ugly. Are there any simple functions that I can use?
Since you're dealing with single characters and non-nested pairs of flags, you can easily do this with a simple call to find and some indexed replacement:
y = 'hello $ my $ name is $ Sean $ Daley $.$.';
index = find(y == '$');
y(index(1:2:end)) = '&';
y(index(2:2:end)) = '#';
And the result:
y =
'hello & my # name is & Sean # Daley &.#.'
I have a user enter a multi string in an NSTextView.
var textViewString = textView.textStorage?.string
Printing the string ( print(textViewString) ), I get a multi-line string, for example:
hello this is line 1
and this is line 2
I want a swift string representation that includes the new line characters. For example, I want print(textStringFlat) to print:
hello this is line 1\n\nand this is line 2
What do I need to do to textViewString to expose the special characters?
If you just want to replace the newlines with the literal characters \ and n then use:
let escapedText = someText.replacingOccurrences(of: "\n", with: "\\n")
I have to read a textfile which contains a list of companycodes. The format of the textfile is:
[1233A12; 1233B88; 2342Q85; 2266738]
Even if I have read the file? Is it possible to compare these numbers with regular numbers? Because I have the codes from two different data-bases and one of them has regular firmnumbers (no characters) and the other has characters inside the firmnumbers.
Btw the file is big (50+mb).
Edit: I have added an additional number in the example because not all the numbers have a character inside
If you want to compare part of a string with a number, you could do it as follows:
combiString = '1234AB56'
myNumber= 1234
str2num(combiString(1:4))==myNumber
str2num(combiString(7:8))==myNumber
You can achieve this result by using regular expressions. For example, if str = '1233A12' you can write
nums = regexp(str, '(\d+)[A-Z]*(\d+)', 'tokens');
str1 = nums{1}(1);
num1 = str2num(str1{1});
str2 = nums{1}(2);
num2 = str2num(str2{1});