Find and Replace numbers in a string - tsql

Question

If I input a string as given below, I should be able to convert as mentioned below.
Ex 1: String - 5AB89C should be converted as 0000000005AB0000000089C
Ex 2: String GH1HJ should be converted as GH0000000001HJ
Ex 3: String N99K7H45 should be B0000000099K0000000007H0000000045
Each number should be complimented with 10 leading zeros including the number. In Ex:1, number 5 is complemented with 9 leading zeros making 10 digits, same way 89 is complimented with 8 leading zeros making total of 10 digits. Alphabets and any special characters should be untouched.

Answer 1

Once you get a copy of PatternSplitCM This is easy as pie.
Here's how we do it with one value:
DECLARE #string VARCHAR(8000) = '5AB89C'
SELECT CASE f.[matched] WHEN 1 THEN '00000000'+'' ELSE '' END + f.item
FROM dbo.patternsplitCM(#String,'[0-9]') AS f
ORDER BY f.ItemNumber
FOR XML PATH('');
Returns: 000000005AB0000000089C
Now against a table:
-- sample data
DECLARE #table TABLE (StringId INT IDENTITY, String VARCHAR(8000));
INSERT #table(String)
VALUES('5AB89C'),('GH1HJ'),('N99K7H45');
SELECT t.StringId, oldstring = t.String, newstring = f.padded
FROM #table AS t
CROSS APPLY
(
SELECT CASE f.[matched] WHEN 1 THEN '00000000'+'' ELSE '' END + f.item
FROM dbo.patternsplitCM(t.String,'[0-9]') AS f
ORDER BY f.ItemNumber
FOR XML PATH('')
) AS f(padded);
Returns:
StringId oldstring newstring
----------- ----------------- --------------------------------------
1 5AB89C 000000005AB0000000089C
2 GH1HJ GH000000001HJ
3 N99K7H45 N0000000099K000000007H0000000045
... and that's it. The code to create PatternSplitCM is below.
PatternSplitCM Code:
CREATE FUNCTION dbo.PatternSplitCM
(
#List VARCHAR(8000) = NULL
,#Pattern VARCHAR(50)
) RETURNS TABLE WITH SCHEMABINDING
AS
RETURN
WITH numbers AS (
SELECT TOP(ISNULL(DATALENGTH(#List), 0))
n = ROW_NUMBER() OVER(ORDER BY (SELECT NULL))
FROM
(VALUES (0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) d (n),
(VALUES (0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) e (n),
(VALUES (0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) f (n),
(VALUES (0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) g (n))
SELECT
ItemNumber = ROW_NUMBER() OVER(ORDER BY MIN(n)),
Item = SUBSTRING(#List,MIN(n),1+MAX(n)-MIN(n)),
Matched
FROM (
SELECT n, y.Matched, Grouper = n - ROW_NUMBER() OVER(ORDER BY y.Matched,n)
FROM numbers
CROSS APPLY (
SELECT Matched = CASE WHEN SUBSTRING(#List,n,1) LIKE #Pattern THEN 1 ELSE 0 END
) y
) d
GROUP BY Matched, Grouper