Replace null by negative id number in not consecutive rows in hive - hiveql

I have this table in my database:
| id | desc |
|-------------|
| 1 | A |
| 2 | B |
| NULL | C |
| 3 | D |
| NULL | D |
| NULL | E |
| 4 | F |
---------------
And I want to transform this table into a table that replace nulls by consecutive negative ids:
| id | desc |
|-------------|
| 1 | A |
| 2 | B |
| -1 | C |
| 3 | D |
| -2 | D |
| -3 | E |
| 4 | F |
---------------
Anyone knows how can I do this in hive?


Below approach works
select coalesce(id,concat('-',ROW_NUMBER() OVER (partition by id))) as id,desc from database_name.table_name;

Related

PostgreSQL: Transforming rows into columns when more than three columns are needed

I have a table like the following one:
+---------+-------+-------+-------------+--+
| Section | Group | Level | Fulfillment | |
+---------+-------+-------+-------------+--+
| A | Y | 1 | 82.2 | |
| A | Y | 2 | 23.2 | |
| A | M | 1 | 81.1 | |
| A | M | 2 | 28.2 | |
| B | Y | 1 | 89.1 | |
| B | Y | 2 | 58.2 | |
| B | M | 1 | 32.5 | |
| B | M | 2 | 21.4 | |
+---------+-------+-------+-------------+--+
And this would be my desired output:
+---------+-------+--------------------+--------------------+
| Section | Group | Level1_Fulfillment | Level2_Fulfillment |
+---------+-------+--------------------+--------------------+
| A | Y | 82.2 | 23.2 |
| A | M | 81.1 | 28.2 |
| B | Y | 89.1 | 58.2 |
| B | M | 32.5 | 21.4 |
+---------+-------+--------------------+--------------------+
Thus, for each section and group I'd like to obtain their percents of fulfillment for level 1 and level 2. To achieve this, I've tried crosstab(), but using this function returns me an error ("The provided SQL must return 3 columns: rowid, category, and values.") because I'm using more than three columns (I need to maintain section and group as identifiers for each row). Is possible to use crosstab in this case?
Regards.

I find crosstab() unnecessary complicated to use and prefer conditional aggregation:
select section,
"group",
max(fulfillment) filter (where level = 1) as level_1,
max(fulfillment) filter (where level = 2) as level_2
from the_table
group by section, "group"
order by section;
Online example

Serial Number in logical order without gaps

I'm trying to generate a serial number based on a few conditions.
My dataset:
+--------+------------+------------+---------+--------+
| Client | Start_Date | End_date | Product | Ser_No |
+--------+------------+------------+---------+--------+
| 44 | 22-01-2018 | 31-12-2018 | A | |
+--------+------------+------------+---------+--------+
| 44 | 24-02-2018 | 01-01-2019 | B | |
+--------+------------+------------+---------+--------+
| 44 | 12-03-2018 | 01-01-2019 | C | |
+--------+------------+------------+---------+--------+
| 100 | 24-01-2018 | 30-11-2018 | A | |
+--------+------------+------------+---------+--------+
| 100 | 26-01-2018 | 15-12-2018 | D | |
+--------+------------+------------+---------+--------+
| 100 | 26-01-2018 | 01-02-2019 | E | |
+--------+------------+------------+---------+--------+
| 100 | 01-03-2018 | 31-01-2019 | F | |
+--------+------------+------------+---------+--------+
What I did to configure my serial number:
RANK() OVER(PARTITION BY Client ORDER BY Client, Start_date ASC)
So now it generates a serial number for my which looks like this:
+--------+------------+------------+---------+--------+
| Client | Start_Date | End_date | Product | Ser_No |
+--------+------------+------------+---------+--------+
| 44 | 22-01-2018 | 31-12-2018 | A | 1 |
+--------+------------+------------+---------+--------+
| 44 | 24-02-2018 | 01-01-2019 | B | 2 |
+--------+------------+------------+---------+--------+
| 44 | 12-03-2018 | 01-01-2019 | C | 3 |
+--------+------------+------------+---------+--------+
| 100 | 24-01-2018 | 30-11-2018 | A | 1 |
+--------+------------+------------+---------+--------+
| 100 | 26-01-2018 | 15-12-2018 | D | 2 |
+--------+------------+------------+---------+--------+
| 100 | 26-01-2018 | 01-02-2019 | E | 2 |
+--------+------------+------------+---------+--------+
| 100 | 01-03-2018 | 31-01-2019 | F | 4 |
+--------+------------+------------+---------+--------+
What goes wrong for my analysis is the last line, it generates the serial number. What it has to be is 3.
Can anayone help me to generate it in this order?
Thanks in advance!
Extra
In addition to my question from yesterday, there is something extra that I need to do. Because the Ser_No has to be the same when my Start_Date is the same, but the Ser_No has also be the same when my folowing records is the same product (also when it has a different Start_Date)
So what I I expect and what I get right now:
+--------+------------+------------+---------+--------+------------+
| Client | Start_Date | End_date | Product | Ser_No | Ser_No New |
+--------+------------+------------+---------+--------+------------+
| 44 | 22-01-2018 | 31-12-2018 | A | 1 | 1 |
+--------+------------+------------+---------+--------+------------+
| 44 | 24-02-2018 | 01-01-2019 | B | 2 | 2 |
+--------+------------+------------+---------+--------+------------+
| 44 | 12-03-2018 | 01-01-2019 | C | 2 | 2 |
+--------+------------+------------+---------+--------+------------+
| 100 | 24-01-2018 | 30-11-2018 | A | 1 | 1 |
+--------+------------+------------+---------+--------+------------+
| 100 | 26-01-2018 | 15-12-2018 | D | 2 | 2 |
+--------+------------+------------+---------+--------+------------+
| 100 | 26-01-2018 | 01-02-2019 | E | 2 | 2 |
+--------+------------+------------+---------+--------+------------+
| 100 | 01-03-2018 | 31-01-2019 | F | 3 | 3 |
+--------+------------+------------+---------+--------+------------+
| 100 | 11-04-2018 | 31-03-2019 | F | 4 | 3 |
+--------+------------+------------+---------+--------+------------+
| 100 | 20-04-2018 | 31-01-2019 | G | 5 | 4 |
+--------+------------+------------+---------+--------+------------+
| 100 | 21-04-2018 | 31-01-2019 | A | 6 | 5 |
+--------+------------+------------+---------+--------+------------+
| 100 | 21-04-2018 | 31-01-2019 | B | 6 | 5 |
+--------+------------+------------+---------+--------+------------+
| 100 | 01-05-2018 | 31-01-2019 | B | 7 | 5 |
+--------+------------+------------+---------+--------+------------+
Any idea on how to achieve this, because I won't get it

You need to use DENSE_RANK instead:
This function returns the rank of each row within a result set partition, with no gaps in the ranking values.
DENSE_RANK() OVER(PARTITION BY Client ORDER BY Start_date) AS Ser_no
Additionaly the Client in ORDER BY has no effect because it has the same value per partition.

postgresql : self join with array

My question is about forming Postgres SQL query for below use case
Approach#1
I have a table like below where I generate the same uuid across different types(a,b,c,d) like mapping different types.
+----+------+-------------+
| id | type | master_guid |
+----+------+-------------+
| 1 | a | uuid-1 |
| 2 | a | uuid-2 |
| 3 | a | uuid-3 |
| 4 | a | uuid-4 |
| 5 | a | uuid-5 |
| 6 | b | uuid-1 |
| 7 | b | uuid-2 |
| 8 | b | uuid-3 |
| 9 | b | uuid-6 |
| 10 | c | uuid-1 |
| 11 | c | uuid-2 |
| 12 | c | uuid-3 |
| 13 | c | uuid-6 |
| 14 | c | uuid-7 |
| 15 | d | uuid-6 |
| 16 | d | uuid-2 |
+----+------+-------------+
Approach#2
I have a created two tables for id to type and then id to master_guid, like below
table1:
+----+------+
| id | type |
+----+------+
| 1 | a |
| 2 | a |
| 3 | a |
| 4 | a |
| 5 | a |
| 6 | b |
| 7 | b |
| 8 | b |
| 9 | b |
| 10 | c |
| 11 | c |
| 12 | c |
| 13 | c |
| 14 | c |
| 15 | d |
| 16 | d |
+----+------+
table2
+----+-------------+
| id | master_guid |
+----+-------------+
| 1 | uuid-1 |
| 2 | uuid-2 |
| 3 | uuid-3 |
| 4 | uuid-4 |
| 5 | uuid-5 |
| 6 | uuid-1 |
| 7 | uuid-2 |
| 8 | uuid-3 |
| 9 | uuid-6 |
| 10 | uuid-1 |
| 11 | uuid-2 |
| 12 | uuid-3 |
| 13 | uuid-6 |
| 14 | uuid-7 |
| 15 | uuid-6 |
| 16 | uuid-2 |
+----+-------------+
I want to get output like below with both approaches:
+----+------+--------+------------+
| id | type | uuid | mapped_ids |
+----+------+--------+------------+
| 1 | a | uuid-1 | [6,10] |
| 2 | a | uuid-2 | [7,11] |
| 3 | a | uuid-3 | [8,12] |
| 4 | a | uuid-4 | null |
| 5 | a | uuid-5 | null |
+----+------+--------+------------+
I have tried self-joins with array_agg on ids and grouping based on uuid but not able to get the desired output.
Use below query to populate data:
Approach#1
insert into table1 values
(1,'a','uuid-1'),
(2,'a','uuid-2'),
(3,'a','uuid-3'),
(4,'a','uuid-4'),
(5,'a','uuid-5'),
(6,'b','uuid-1'),
(7,'b','uuid-2'),
(8,'b','uuid-3'),
(9,'b','uuid-6'),
(10,'c','uuid-1'),
(11,'c','uuid-2'),
(12,'c','uuid-3'),
(13,'c','uuid-6'),
(14,'c','uuid-7'),
(15,'d','uuid-6'),
(16,'d','uuid-2')
Approach#2
insert into table1 values
(1,'a'),
(2,'a'),
(3,'a'),
(4,'a'),
(5,'a'),
(6,'b'),
(7,'b'),
(8,'b'),
(9,'b'),
(10,'c'),
(11,'c'),
(12,'c'),
(13,'c'),
(14,'c'),
(15,'d'),
(16,'d')
insert into table2 values
(1,'uuid-1'),
(2,'uuid-2'),
(3,'uuid-3'),
(4,'uuid-4'),
(5,'uuid-5'),
(6,'uuid-1'),
(7,'uuid-2'),
(8,'uuid-3'),
(9,'uuid-6'),
(10,'uuid-1'),
(11,'uuid-2'),
(12,'uuid-3'),
(13,'uuid-6'),
(14,'uuid-7'),
(15,'uuid-6'),
(16,'uuid-2')

demo: db<>fiddle
Using window function ARRAY_AGG allows you to aggregate your ids per groups (in your case the groups are your uuids)
SELECT
id, type, master_guid as uuid,
array_agg(id) OVER (PARTITION BY master_guid) as mapped_ids
FROM table1
ORDER BY id
Result:
| id | type | uuid | mapped_ids |
|----|------|--------|------------|
| 1 | a | uuid-1 | 10,6,1 |
| 2 | a | uuid-2 | 16,2,7,11 |
| 3 | a | uuid-3 | 8,3,12 |
| 4 | a | uuid-4 | 4 |
| 5 | a | uuid-5 | 5 |
| 6 | b | uuid-1 | 10,6,1 |
| 7 | b | uuid-2 | 16,2,7,11 |
| 8 | b | uuid-3 | 8,3,12 |
| 9 | b | uuid-6 | 15,13,9 |
| 10 | c | uuid-1 | 10,6,1 |
| 11 | c | uuid-2 | 16,2,7,11 |
| 12 | c | uuid-3 | 8,3,12 |
| 13 | c | uuid-6 | 15,13,9 |
| 14 | c | uuid-7 | 14 |
| 15 | d | uuid-6 | 15,13,9 |
| 16 | d | uuid-2 | 16,2,7,11 |
These arrays currently contain also the id of the current row (mapped_ids of id = 1 contains the 1). This can be corrected by remove this element with array_remove:
SELECT
id, type, master_guid as uuid,
array_remove(array_agg(id) OVER (PARTITION BY master_guid), id) as mapped_ids
FROM table1
ORDER BY id
Result:
| id | type | uuid | mapped_ids |
|----|------|--------|------------|
| 1 | a | uuid-1 | 10,6 |
| 2 | a | uuid-2 | 16,7,11 |
| 3 | a | uuid-3 | 8,12 |
| 4 | a | uuid-4 | |
| 5 | a | uuid-5 | |
| 6 | b | uuid-1 | 10,1 |
| 7 | b | uuid-2 | 16,2,11 |
| 8 | b | uuid-3 | 3,12 |
| 9 | b | uuid-6 | 15,13 |
| 10 | c | uuid-1 | 6,1 |
| 11 | c | uuid-2 | 16,2,7 |
| 12 | c | uuid-3 | 8,3 |
| 13 | c | uuid-6 | 15,9 |
| 14 | c | uuid-7 | |
| 15 | d | uuid-6 | 13,9 |
| 16 | d | uuid-2 | 2,7,11 |
Now for example id=4 contains an empty array instead of a NULL value. This can be achieved by using the NULLIF function. This gives NULL if both parameters are equal, else it gives out the first parameter.
SELECT
id, type, master_guid as uuid,
NULLIF(
array_remove(array_agg(id) OVER (PARTITION BY master_guid), id),
'{}'::int[]
) as mapped_ids
FROM table1
ORDER BY id
Result:
| id | type | uuid | mapped_ids |
|----|------|--------|------------|
| 1 | a | uuid-1 | 10,6 |
| 2 | a | uuid-2 | 16,7,11 |
| 3 | a | uuid-3 | 8,12 |
| 4 | a | uuid-4 | (null) |
| 5 | a | uuid-5 | (null) |
| 6 | b | uuid-1 | 10,1 |
| 7 | b | uuid-2 | 16,2,11 |
| 8 | b | uuid-3 | 3,12 |
| 9 | b | uuid-6 | 15,13 |
| 10 | c | uuid-1 | 6,1 |
| 11 | c | uuid-2 | 16,2,7 |
| 12 | c | uuid-3 | 8,3 |
| 13 | c | uuid-6 | 15,9 |
| 14 | c | uuid-7 | (null) |
| 15 | d | uuid-6 | 13,9 |
| 16 | d | uuid-2 | 2,7,11 |

Try this:
select
t1.id, t1.type, t1.master_guid, array_agg (distinct t2.id)
from
table1 t1
left join table1 t2 on
t1.master_guid = t2.master_guid and
t1.id != t2.id
group by
t1.id, t1.type, t1.master_guid
I don't come up with exactly the same results you listed, but I thought it was close enought that maybe there was a mistaken expectation on your side or only a small error on mine... either way, a potential starting point.
-- EDIT --
For approach #2, I think you just need to add an inner join to Table2 to get the GUID:
select
t1.id, t1.type, t2.master_guid,
array_agg (t2a.id)
from
table1 t1
join table2 t2 on t1.id = t2.id
left join table2 t2a on
t2.master_guid = t2a.master_guid and
t2a.id != t1.id
where
t1.type = 'a'
group by
t1.id, t1.type, t2.master_guid

left join 2 tables not working

I have 2 tables:
Table1: 'op_ats'
| ID1 | numero |id_cofre | id_chave | estadoAT
| 1 | 111 | 1 | 3 | 1
| 2 | 222 | 3 | 3 | 2
| 3 | 333 | 1 | 4 | 2
| 4 | 444 | 1 | 2 | 3
Table_2: 'op_ats_cofres_chaves'
| ID2 | num_chave |
| 1 | A |
| 2 | B |
| 3 | C |
| 4 | D |
| 5 | E |
I have this SQL:
SELECT chaves.*, ats.numero numAT, ats.estadoAT
FROM op_ats_cofres_chaves chaves
LEFT JOIN op_ats ats ON ats.id_chave_cofre = chaves.id AND ats.id_cofre = 1
With this I get the following result:
| ID2 | num_chave | numAT | estadoAT |
| 1 | A | 444 | 3 |
| 2 | B | NULL | NULL |
| 3 | C | 111 | 1 |
| 4 | D | 333 | 2 |
| 5 | E | NULL | NULL |
Now the problem is that I want to filter the rows that are in Table1 but only that have the column 'estadoAT' with values 1 and 2. I've tried to add the line
WHERE op_ats.estadoAT = 1 OR op_ats.estadoAT = 2
But this makes the following result:
| ID2 | num_chave | numAT | estadoAT |
| 1 | A | 444 | 3 |
| 3 | C | 111 | 1 |
| 4 | D | 333 | 2 |
Resuming...
My intention is to get ALL rows in the Table2 and join the Table1 rows that have the 'id_cofre = 1' and '(estadoAT = 1 OR estadoAT = 2)'.
Any help is appreciated.

You have to move condition to JOIN clause instead of WHERE.
SELECT chaves.*, ats.numero numAT, ats.estadoAT
FROM op_ats_cofres_chaves chaves
LEFT JOIN op_ats ats ON ats.id_chave_cofre = chaves.id AND ats.id_cofre = 1
AND op_ats.estadoAT = 1 OR op_ats.estadoAT = 2;

how to return number of records as a part of a select statement?

I'd like to know if there is a way to include row numbers (basically telling me how many records I'm getting back from a database query).
I have the following SQL query
SELECT w.widget_id, w.class_id, wg.name classname, wg.label AS classgroup, c.label, c.seq,
g.name AS group, p.name, p.type, CASE WHEN v.value IS NOT NULL THEN v.value WHEN g2p.value IS NOT NULL THEN g2p.value ELSE p.value END AS value
FROM widgets_to_categories w
INNER JOIN widget_classes c ON w.class_id = c.class_id
JOIN classes_to_param_groups t2g ON c.class_id = t2g.class_id
JOIN widget_groups g ON t2g.group_id = g.group_id
JOIN param_groups_to_params g2p ON t2g.group_id = g2p.group_id
JOIN provisioning_params p ON g2p.param_id = p.param_id
INNER JOIN widget_cat_groups wg ON c.class_group_id = wg.class_group_id
LEFT JOIN widget_values v ON(w.widget_id=v.device_id AND p.param_id=v.param_id AND g.name=v.group_name )
WHERE w.widget_id=8 ORDER BY c.class_id ASC
And it returns data like:
widget_id | class_id | classname | classgroup | label | seq | group | name | type | value
8 | 1 | toy | group A | test label | 1 | toy | reg | text | af
8 | 1 | toy | group A | test label | 1 | reg2 | fall | text | 25327
8 | 1 | toy | group A | test label | 1 | reg2 | pd | text | dvaa
8 | 1 | toy | group A | test label | 1 | reg2 | ext | text | 28235
8 | 1 | toy | group A | test label | 1 | reg1 | ext | text | 28230
8 | 1 | toy | group A | test label | 1 | toy | meec | text | 094F22DE501
8 | 1 | toy | group A | test label | 1 | toy | mmap | text | 0|
8 | 1 | toy | group A | test label | 1 | reg1 | fna | text | 26014
8 | 1 | toy | group A | test label | 1 | reg1 | fall | text | t-123
8 | 1 | toy | group A | test label | 1 | toy | uen | boolean | false
8 | 1 | toy | group A | test label | 1 | toy | adminpd |
I'd like to know if there's a way to have the database auto generate and return another column that is just an identifier for the row, like so:
id |widget_id | class_id | classname | classgroup | label | seq | group | name | type | value
1 | 8 | 1 | toy | group A | test label | 1 | toy | reg | text | af
2 | 8 | 1 | toy | group A | test label | 1 | reg2 | fall | text | 25327
3 | 8 | 1 | toy | group A | test label | 1 | reg2 | pd | text | dvaa
4 | 8 | 1 | toy | group A | test label | 1 | reg2 | ext | text | 28235
5 | 8 | 1 | toy | group A | test label | 1 | reg1 | ext | text | 28230
6 | 8 | 1 | toy | group A | test label | 1 | toy | meec | text | 094F22DE501
7 | 8 | 1 | toy | group A | test label | 1 | toy | mmap | text | 0|
8 | 8 | 1 | toy | group A | test label | 1 | reg1 | fna | text | 26014
9 | 8 | 1 | toy | group A | test label | 1 | reg1 | fall | text | t-123
10 | 8 | 1 | toy | group A | test label | 1 | toy | uen | boolean | false
11 | 8 | 1 | toy | group A | test label | 1 | toy | adminpd | boolean | false
I think I can do this by selecting into a temporary table.. I haven't figured out the syntax on how to do it yet... But I'm also wondering if there's another simpler way.
Once I get the data back from the database, having this ID field makes it eaiser to manipulate.
Thanks.

You can use the row_number window function to keep track of each row number.
Like so:
create table foo
(
id serial,
val text
);
INSERT INTO foo (val)
VALUES ('One'), ('Two'), ('Three');
SELECT f.*, row_number() OVER(ORDER BY val)
FROM foo AS f
ORDER BY val;
Here's an SQL Fiddle which shows this:
http://sqlfiddle.com/#!15/0c434/2
Additional options:
You could count the result with a query of the form:
SELECT count(*)
FROM
(
SELECT *
FROM foo
);
Or you may be able to get the row count back as part of the Postgres library you're using. For example, psycopg2 (Python) and DBI (Perl) allow for this (with some caveats). The library you're using may offer something similar.