'result' is inaccessible due to 'internal' protection level - swift

Question

I want to create custom framework for universal API request using URLSession. So I have used this link. I will be using this project as a custom framework. So to use that I have changed its access specifier by open .And using thislink I have imported it in my project. And I have done the following code to call post request
import iOSCoreFramework
func callBySpeedyNetworking2() {
let trylogin = login(username: "****", password: "***")
SpeedyNetworking.removeToken()
SpeedyNetworking.postUrl(url: URL(string: GlobalConstants.loginFullURL), model: trylogin) { (response) in
if !response.success {
// show a network error
print("network error ",response.error)
return
}
// successful
print("RESPONSE 1 ------------> ")
dump(response.result(model: ModelResponse.self))
dump(response.jsonResults(model: ModelResponse.self))
}
}
But it's giving me an error for 'success', 'error' and on the following lines:
dump(response.result(model: ModelResponse.self))
dump(response.jsonResults(model: ModelResponse.self))
From various links I have made changes in SpeedyResponse class by the following
public class SpeedyResponse {
public var success : Bool!
public var statusCode = 0
public var error: Error?
public var data: Data?
public init (success : Bool, statusCode : Int,error : Error, data : Data){
self.success = success
self.statusCode = statusCode
self.error = error
self.data = data
}
public init(data: Data?, response: URLResponse?, error: Error?) {
self.error = error
self.data = data
if let httpResponse = response as? HTTPURLResponse {
statusCode = httpResponse.statusCode
}
success = statusCode == 200 && error == nil && data != nil ? true : false
}
public func jsonResults<T>(model: T.Type) -> T? {
if !success { return nil }
guard let responseData = data else { return nil }
do {
return try JSONSerialization.jsonObject(with: responseData) as? T
} catch {
return nil
}
}
public func result<T: Decodable>(model: T.Type) -> T? {
if !success { return nil }
guard let responseData = data else { return nil }
do {
return try JSONDecoder().decode(model, from: responseData)
} catch {
return nil
}
}
}
But still it wasn't fixed.

Answer 1

The underlying problem here is inside your struct all variables and methods are declared automatically with its scope as internal. So when you create a type like this:
public class Human {
let foo: String
let bar: String
}
You will not be able to access both foo and bar because they are actually declared as:
public class Human {
internal let foo: String
internal let bar: String
}
To fix this just add the access modifier to public.
In that sense your new model should look like this
public class SpeedyResponse {
public var success: Bool!
public var statusCode = 0
public var error: Error?
public var data: Data?
public init(data: Data?, response: URLResponse?, error: Error?) {
self.error = error
self.data = data
if let httpResponse = response as? HTTPURLResponse {
statusCode = httpResponse.statusCode
}
success = statusCode == 200 && error == nil && data != nil ? true : false
}
public func jsonResults<T>(model: T.Type) -> T? {
if !success { return nil }
guard let responseData = data else { return nil }
do {
return try JSONSerialization.jsonObject(with: responseData) as? T
} catch {
return nil
}
}
public func result<T: Decodable>(model: T.Type) -> T? {
if !success { return nil }
guard let responseData = data else { return nil }
do {
return try JSONDecoder().decode(model, from: responseData)
} catch {
return nil
}
}
}