I am trying to train a GPR model and a tensorflow model together. The training part has no issue. But for prediction using the trained model I receive a type error in a tf.placeholder op.
pred, uncp=sess.run([my, yv], feed_dict={X:xtr})
The code is similar to the 2nd example from https://gpflow.readthedocs.io/en/master/notebooks/advanced_usage.html
import numpy as np
import tensorflow as tf
import gpflow
float_type = gpflow.settings.float_type
gpflow.reset_default_graph_and_session()
def cnn_fn(x, output_dim):
out= tf.layers.dense(inputs=x, units=output_dim, activation=tf.nn.relu)
print(out)
return out
N = 150
xtr = np.random.rand(N,1)
ytr = np.sin(12*xtr) + 0.66*np.cos(25*xtr) + np.random.randn(N,1)*0.1 + 3
xtr = np.random.rand(N,28)
print(xtr.shape, ytr.shape)
nepoch=50
gp_dim=xtr.shape[1]
print(gp_dim)
minibatch_size = 16
X = tf.placeholder(tf.float32, [None, gp_dim])
Y = tf.placeholder(tf.float32, [None, 1])
with tf.variable_scope('cnn'):
f_X = tf.cast(cnn_fn(X, gp_dim), dtype=float_type)
k = gpflow.kernels.Matern52(gp_dim)
gp_model = gpflow.models.GPR(f_X, tf.cast(Y, dtype=float_type), k)
loss = -gp_model.likelihood_tensor
m, v = gp_model._build_predict(f_X)
my, yv = gp_model.likelihood.predict_mean_and_var(m, v)
with tf.variable_scope('adam'):
opt_step = tf.train.AdamOptimizer(0.001).minimize(loss)
tf_vars = tf.get_collection(tf.GraphKeys.GLOBAL_VARIABLES, scope='adam')
tf_vars += tf.get_collection(tf.GraphKeys.GLOBAL_VARIABLES, scope='cnn')
## initialize
sess = tf.Session()
sess.run(tf.variables_initializer(var_list=tf_vars))
gp_model.initialize(session=sess)
for i in range(nepoch):
shind=np.array(range(len(xtr)))
np.random.shuffle(shind)
for j in range(int(len(xtr)/minibatch_size)):
ind=shind[j*minibatch_size: (j+1)*minibatch_size]
sess.run(opt_step, feed_dict={X:xtr[ind], Y:ytr[ind]})
Executing the code above runs fine. But adding the following line gives an error:
pred, uncp=sess.run([my, yv], feed_dict={X:xtr})
with the following error:
<ipython-input-25-269715087df2> in <module>
----> 1 pred, uncp=sess.run([my, yv], feed_dict={X:xtr})
[...]
InvalidArgumentError: You must feed a value for placeholder tensor 'Placeholder_1' with dtype float and shape [?,1]
[[node Placeholder_1 (defined at <ipython-input-24-39ccf45cd248>:2) = Placeholder[dtype=DT_FLOAT, shape=[?,1], _device="/job:localhost/replica:0/task:0/device:GPU:0"]()]]
The reason your code fails is because you are not actually feeding in a value to one of the placeholders. This is easier to spot if you actually give them names:
X = tf.placeholder(tf.float32, [None, gp_dim], name='X')
Y = tf.placeholder(tf.float32, [None, 1], name='Y')
Tensorflow requires the entire compute graph to be well-defined, and the GPR model you are using depends on both X and Y. If you run the following line, it works fine:
pred, uncp = sess.run([my, yv], feed_dict={X: xtr, Y: ytr})
Update: as user1018464 pointed out in the comment, you are using the GPR model, in which the predictions directly depend on the training data (e.g. see equations (2.22) and (2.23) on page 16 of http://www.gaussianprocess.org/gpml/chapters/RW2.pdf). Hence you will need to pass in both xtr and ytr to make predictions.
Other models such as SVGP represent the function through "inducing features", commonly "pseudo input/output" pairs that summarise the data, in which case you won't need to feed in the original input values at all (I got it wrong when I first answered).
You could set up the model as follows:
gp_model = gpflow.models.SVGP(f_X, tf.cast(Y, dtype=float_type), k, gpflow.likelihoods.Gaussian(), xtr.copy(), num_data=N)
Then pred, uncp=sess.run([my, yv], feed_dict={X:xtr}) works as expected.
If you want to predict at different points Xtest, you need to set up a separate placeholder, and reuse the cnn (note the reuse=True in the variable_scope with the same name), as in example 2 of the notebook:
Xtest = tf.placeholder(tf.float32, [None, Mnist.input_dim], name='Xtest')
with tf.variable_scope('cnn', reuse=True):
f_Xtest = tf.cast(cnn_fn(Xtest, gp_dim), dtype=float_type)
Set up the model as before using f_X, but use f_Xtest in the call to _build_predict:
m, v = gp_model._build_predict(f_Xtest)
my, yv = gp_model.likelihood.predict_mean_and_var(m, v)
Now you need to pass in both X, Y, and Xtest into the session's run():
pred, uncp = sess.run([my, yv], feed_dict={X: xtr, Y: Ytr, Xtest: xtest})
where xtest is the numpy array with points at which you want to predict.
The GPflow manages TensorFlow sessions for you and you don't need to create your own TF session, when you use GPflow alone. In your case, tf.layers.dense makes
new variables, which should be initialized and I would advise to use a session which were created by GPflow. Essentially, you need to replace these lines
## initialize
sess = tf.Session()
sess.run(tf.variables_initializer(var_list=tf_vars))
gp_model.initialize(session=sess)
with:
sess = gpflow.get_default_session()
sess.run(tf.variables_initializer(var_list=tf_vars)
or wrap your code with default session context:
with tf.Session() as session:
... build and run
Related
Python version: 3.8
Pytorch version: 1.9.0+cpu
Platform: Anaconda Spyder5.0
To reproduce this problem, just copy every code below to a single file.
The ILSVRC2012_val_00000293.jpg file used in this code is shown below, you also need to download it and then change its destination in the code.
Some background of this problem:
I am now working on a project that aims to develop a hardware accelerator to complete the inference process of the MobileNet V2 network. I used pretrained quantized Pytorch model to simulate the outcome, and the result comes out very well.
In order to use hardware to complete this task, I wish to know every inputs and outputs as well as intermidiate variables during runing this piece of pytorch code. I used a package named torchextractor to fetch the outcomes of first layer, which in this case, is a 3*3 convolution layer.
import numpy as np
import torchvision
import torch
from torchvision import transforms, datasets
from PIL import Image
from torchvision import transforms
import torchextractor as tx
import math
#########################################################################################
##### Processing of input image
#########################################################################################
normalize = transforms.Normalize(mean=[0.485, 0.456, 0.406],
std=[0.229, 0.224, 0.225])
test_transform = transforms.Compose([
transforms.Resize(256),
transforms.CenterCrop(224),
transforms.ToTensor(),
normalize,])
preprocess = transforms.Compose([
transforms.Resize(256),
transforms.CenterCrop(224),
transforms.ToTensor(),
transforms.Normalize(mean=[0.485, 0.456, 0.406], std=[0.229, 0.224, 0.225]),
])
#image file destination
filename = "D:\Project_UM\MobileNet_VC709\MobileNet_pytorch\ILSVRC2012_val_00000293.jpg"
input_image = Image.open(filename)
input_tensor = preprocess(input_image)
input_batch = input_tensor.unsqueeze(0)
#########################################################################################
#########################################################################################
#########################################################################################
#----First verify that the torchextractor class should not influent the inference outcome
# ofmp of layer1 before putting into torchextractor
a,b,c = quantize_tensor(input_batch)# to quantize the input tensor and return an int8 tensor, scale and zero point
input_qa = torch.quantize_per_tensor(torch.tensor(input_batch.clone().detach()), b, c, torch.quint8)# Using quantize_per_tensor method of torch
# Load a quantized mobilenet_v2 model
model_quantized = torchvision.models.quantization.mobilenet_v2(pretrained=True, quantize=True)
model_quantized.eval()
with torch.no_grad():
output = model_quantized.features[0][0](input_qa)# Ofmp of layer1, datatype : quantized_tensor
# print("FM of layer1 before tx_extractor:\n",output.int_repr())# Ofmp of layer1, datatype : int8 tensor
output1_clone = output.int_repr().detach().numpy()# Clone ofmp of layer1, datatype : ndarray
#########################################################################################
#########################################################################################
#########################################################################################
# ofmp of layer1 after adding torchextractor
model_quantized_ex = tx.Extractor(model_quantized, ["features.0.0"])#Capture of the module inside first layer
model_output, features = model_quantized_ex(input_batch)# Forward propagation
# feature_shapes = {name: f.shape for name, f in features.items()}
# print(features['features.0.0']) # Ofmp of layer1, datatype : quantized_tensor
out1_clone = features['features.0.0'].int_repr().numpy() # Clone ofmp of layer1, datatype : ndarray
if(out1_clone.all() == output1_clone.all()):
print('Model with torchextractor attached output the same value as the original model')
else:
print('Torchextractor method influence the outcome')
Here I define a numpy quantization scheme based on the quantization scheme proposed by
Quantization and Training of Neural Networks for Efficient
Integer-Arithmetic-Only Inference
# Convert a normal regular tensor to a quantized tensor with scale and zero_point
def quantize_tensor(x, num_bits=8):# to quantize the input tensor and return an int8 tensor, scale and zero point
qmin = 0.
qmax = 2.**num_bits - 1.
min_val, max_val = x.min(), x.max()
scale = (max_val - min_val) / (qmax - qmin)
initial_zero_point = qmin - min_val / scale
zero_point = 0
if initial_zero_point < qmin:
zero_point = qmin
elif initial_zero_point > qmax:
zero_point = qmax
else:
zero_point = initial_zero_point
# print(zero_point)
zero_point = int(zero_point)
q_x = zero_point + x / scale
q_x.clamp_(qmin, qmax).round_()
q_x = q_x.round().byte()
return q_x, scale, zero_point
#%%
# #############################################################################################
# --------- Simulate the inference process of layer0: conv33 using numpy
# #############################################################################################
# get the input_batch quantized buffer data
input_scale = b.item()
input_zero = c
input_quantized = a[0].detach().numpy()
# get the layer0 output scale and zero_point
output_scale = model_quantized.features[0][0].state_dict()['scale'].item()
output_zero = model_quantized.features[0][0].state_dict()['zero_point'].item()
# get the quantized weight with scale and zero_point
weight_scale = model_quantized.features[0][0].state_dict()["weight"].q_scale()
weight_zero = model_quantized.features[0][0].state_dict()["weight"].q_zero_point()
weight_quantized = model_quantized.features[0][0].state_dict()["weight"].int_repr().numpy()
# print(weight_quantized)
# print(weight_quantized.shape)
# bias_quantized,bias_scale,bias_zero= quantize_tensor(model_quantized.features[0][0].state_dict()["bias"])# to quantize the input tensor and return an int8 tensor, scale and zero point
# print(bias_quantized.shape)
bias = model_quantized.features[0][0].state_dict()["bias"].detach().numpy()
# print(input_quantized)
print(type(input_scale))
print(type(output_scale))
print(type(weight_scale))
Then I write a quantized 2D convolution using numpy, hope to figure out every details in pytorch data flow during the inference.
#%% numpy simulated layer0 convolution function define
def conv_cal(input_quantized, weight_quantized, kernel_size, stride, out_i, out_j, out_k):
weight = weight_quantized[out_i]
input = np.zeros((input_quantized.shape[0], kernel_size, kernel_size))
for i in range(weight.shape[0]):
for j in range(weight.shape[1]):
for k in range(weight.shape[2]):
input[i][j][k] = input_quantized[i][stride*out_j+j][stride*out_k+k]
# print(np.dot(weight,input))
# print(input,"\n")
# print(weight)
return np.multiply(weight,input).sum()
def QuantizedConv2D(input_scale, input_zero, input_quantized, output_scale, output_zero, weight_scale, weight_zero, weight_quantized, bias, kernel_size, stride, padding, ofm_size):
output = np.zeros((weight_quantized.shape[0],ofm_size,ofm_size))
input_quantized_padding = np.full((input_quantized.shape[0],input_quantized.shape[1]+2*padding,input_quantized.shape[2]+2*padding),0)
zero_temp = np.full(input_quantized.shape,input_zero)
input_quantized = input_quantized - zero_temp
for i in range(input_quantized.shape[0]):
for j in range(padding,padding + input_quantized.shape[1]):
for k in range(padding,padding + input_quantized.shape[2]):
input_quantized_padding[i][j][k] = input_quantized[i][j-padding][k-padding]
zero_temp = np.full(weight_quantized.shape, weight_zero)
weight_quantized = weight_quantized - zero_temp
for i in range(output.shape[0]):
for j in range(output.shape[1]):
for k in range(output.shape[2]):
# output[i][j][k] = (weight_scale*input_scale)*conv_cal(input_quantized_padding, weight_quantized, kernel_size, stride, i, j, k) + bias[i] #floating_output
output[i][j][k] = weight_scale*input_scale/output_scale*conv_cal(input_quantized_padding, weight_quantized, kernel_size, stride, i, j, k) + bias[i]/output_scale + output_zero
output[i][j][k] = round(output[i][j][k])
# int_output
return output
Here I input the same image, weight, and bias together with their zero_point and scale, then compare this "numpy simulated" result to the PyTorch calculated one.
quantized_model_out1_int8 = np.squeeze(features['features.0.0'].int_repr().numpy())
print(quantized_model_out1_int8.shape)
print(quantized_model_out1_int8)
out1_np = QuantizedConv2D(input_scale, input_zero, input_quantized, output_scale, output_zero, weight_scale, weight_zero, weight_quantized, bias, 3, 2, 1, 112)
np.save("out1_np.npy",out1_np)
for i in range(quantized_model_out1_int8.shape[0]):
for j in range(quantized_model_out1_int8.shape[1]):
for k in range(quantized_model_out1_int8.shape[2]):
if(out1_np[i][j][k] < 0):
out1_np[i][j][k] = 0
print(out1_np)
flag = np.zeros(quantized_model_out1_int8.shape)
for i in range(quantized_model_out1_int8.shape[0]):
for j in range(quantized_model_out1_int8.shape[1]):
for k in range(quantized_model_out1_int8.shape[2]):
if(quantized_model_out1_int8[i][j][k] == out1_np[i][j][k]):
flag[i][j][k] = 1
out1_np[i][j][k] = 0
quantized_model_out1_int8[i][j][k] = 0
# Compare the simulated result to extractor fetched result, gain the total hit rate
print(flag.sum()/(112*112*32)*100,'%')
If the "numpy simulated" results are the same as the extracted one, call it a hit. Print the total hit rate, it shows that numpy gets 92% of the values right. Now the problem is, I have no idea why the rest 8% of values come out wrong.
Comparison of two outcomes:
The picture below shows the different values between Numpy one and PyTorch one, the sample channel is index[1]. The left upper corner is Numpy one, and the upright corner is PyTorch one, I have set all values that are the same between them to 0, as you can see, most of the values just have a difference of 1(This can be view as the error brought by the precision loss of fixed point arithmetics), but some have large differences, e.g. the value[1][4], 121 vs. 76 (I don't know why)
Focus on one strange value:
This code is used to replay the calculation process of the value[1][4], originally I was expecting a trial and error process could lead me to solve this problem, to get my wanted number of 76, but no matter how I tried, it didn't output 76. If you want to try this, I paste this code for your convenience.
#%% A test code to check the calculation process
weight_quantized_sample = weight_quantized[2]
M_t = input_scale * weight_scale / output_scale
ifmap_t = np.int32(input_quantized[:,1:4,7:10])
weight_t = np.int32(weight_quantized_sample)
bias_t = bias[2]
bias_q = bias_t/output_scale
res_t = 0
for ch in range(3):
ifmap_offset = ifmap_t[ch]-np.int32(input_zero)
weight_offset = weight_t[ch]-np.int32(weight_zero)
res_ch = np.multiply(ifmap_offset, weight_offset)
res_ch = res_ch.sum()
res_t = res_t + res_ch
res_mul = M_t*res_t
# for n in range(1, 30):
# res_mul = multiply(n, M_t, res_t)
res_t = round(res_mul + output_zero + bias_q)
print(res_t)
Could you help me out of this, have been stuck here for a long time.
I implemented my own version of quantized convolution and got from 99.999% to 100% hitrate (and mismatch of a single value is by 1 that I can consider to be a rounding issue). The link on the paper in the question helped a lot.
But I found that your formulas are the same as mine. So I don't know what was your issue. As I understand quantization in pytorch is hardware dependent.
Here is my code:
def my_Conv2dRelu_b2(input_q, conv_layer, output_shape):
'''
Args:
input_q: quantized tensor
conv_layer: quantized tensor
output_shape: the pre-computed shape of the result
Returns:
'''
output = np.zeros(output_shape)
# extract needed float numbers from quantized operations
weights_scale = conv_layer.weight().q_per_channel_scales()
input_scale = input_q.q_scale()
weights_zp = conv_layer.weight().q_per_channel_zero_points()
input_zp = input_q.q_zero_point()
# extract needed convolution parameters
padding = conv_layer.padding
stride = conv_layer.stride
# extract float numbers for results
output_zp = conv_layer.zero_point
output_scale = conv_layer.scale
conv_weights_int = conv_layer.weight().int_repr()
input_int = input_q.int_repr()
biases = conv_layer.bias().numpy()
for k in range(input_q.shape[0]):
for i in range(conv_weights_int.shape[0]):
output[k][i] = manual_convolution_quant(
input_int[k].numpy(),
conv_weights_int[i].numpy(),
biases[i],
padding=padding,
stride=stride,
image_zp=input_zp, image_scale=input_scale,
kernel_zp=weights_zp[i].item(), kernel_scale=weights_scale[i].item(),
result_zp=output_zp, result_scale=output_scale
)
return output
def manual_convolution_quant(image, kernel, b, padding, stride, image_zp, image_scale, kernel_zp, kernel_scale,
result_zp, result_scale):
H = image.shape[1]
W = image.shape[2]
new_H = H // stride[0]
new_W = W // stride[1]
results = np.zeros([new_H, new_W])
M = image_scale * kernel_scale / result_scale
bias = b / result_scale
paddedIm = np.pad(
image,
[(0, 0), (padding[0], padding[0]), (padding[1], padding[1])],
mode="constant",
constant_values=image_zp,
)
s = kernel.shape[1]
for i in range(new_H):
for j in range(new_W):
patch = paddedIm[
:, i * stride[0]: i * stride[0] + s, j * stride[1]: j * stride[1] + s
]
res = M * ((kernel - kernel_zp) * (patch - image_zp)).sum() + result_zp + bias
if res < 0:
res = 0
results[i, j] = round(res)
return results
Code to compare pytorch and my own version.
def calc_hit_rate(array1, array2):
good = (array1 == array2).astype(np.int).sum()
all = array1.size
return good / all
# during inference
y2 = model.conv1(y1)
y2_int = torch.int_repr(y2)
y2_int_manual = my_Conv2dRelu_b2(y1, model.conv1, y2.shape)
print(f'y2 hit rate= {calc_hit_rate(y2.int_repr().numpy(), y2_int_manual)}') #hit_rate=1.0
I would like to perform some multivariant regression using gaussian process regression as implemented in GPflow using version 2.
Installed with pip install gpflow==2.0.0rc1
Below is some example code that generates some 2D data and then attempts to fit it with using GPR and the finally computes the difference
between the true input data and the GPR prediction.
Eventually I would like to extend to higher dimensions
and do tests against a validation set to check for over-fitting
and experiment with other kernels and "Automatic Relevance Determination"
but understanding how to get this to work is the first step.
Thanks!
The following code snippet will work in a jupyter notebook.
import gpflow
import numpy as np
import matplotlib
from gpflow.utilities import print_summary
%matplotlib inline
matplotlib.rcParams['figure.figsize'] = (12, 6)
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
def gen_data(X, Y):
"""
make some fake data.
X, Y are np.ndarrays with shape (N,) where
N is the number of samples.
"""
ys = []
for x0, x1 in zip(X,Y):
y = x0 * np.sin(x0*10)
y = x1 * np.sin(x0*10)
y += 1
ys.append(y)
return np.array(ys)
# generate some fake data
x = np.linspace(0, 1, 20)
X, Y = np.meshgrid(x, x)
X = X.ravel()
Y = Y.ravel()
z = gen_data(X, Y)
#note X.shape, Y.shape and z.shape
#are all (400,) for this case.
# if you would like to plot the data you can do the following
fig = plt.figure()
ax = Axes3D(fig)
ax.scatter(X, Y, z, s=100, c='k')
# had to set this
# to avoid the following error
# tensorflow.python.framework.errors_impl.InvalidArgumentError: Cholesky decomposition was not successful. The input might not be valid. [Op:Cholesky]
gpflow.config.set_default_positive_minimum(1e-7)
# setup the kernel
k = gpflow.kernels.Matern52()
# set up GPR model
# I think the shape of the independent data
# should be (400, 2) for this case
XY = np.column_stack([[X, Y]]).T
print(XY.shape) # this will be (400, 2)
m = gpflow.models.GPR(data=(XY, z), kernel=k, mean_function=None)
# optimise hyper-parameters
opt = gpflow.optimizers.Scipy()
def objective_closure():
return - m.log_marginal_likelihood()
opt_logs = opt.minimize(objective_closure,
m.trainable_variables,
options=dict(maxiter=100)
)
# predict training set
mean, var = m.predict_f(XY)
print(mean.numpy().shape)
# (400, 400)
# I would expect this to be (400,)
# If it was then I could compute the difference
# between the true data and the GPR prediction
# `diff = mean - z`
# but because the shape is not as expected this of course
# won't work.
The shape of z must be (N, 1), whereas in your case it is (N,). However, this is a missing check in GPflow and not your fault.
After reading about how to solve an ODE with neural networks following the paper Neural Ordinary Differential Equations and the blog that uses the library JAX I tried to do the same thing with "plain" Pytorch but found a point rather "obscure": How to properly use the partial derivative of a function (in this case the model) w.r.t one of the input parameters.
To resume the problem at hand as shown in 2 it is intended to solve the ODE y' = -2*x*y with the condition y(x=0) = 1 in the domain -2 <= x <= 2. Instead of using finite differences the solution is replaced by a NN as y(x) = NN(x) with a single layer with 10 nodes.
I managed to (more or less) replicate the blog with the following code
import torch
import torch.nn as nn
from torch import optim
import matplotlib.pyplot as plt
import numpy as np
# Define the NN model to solve the problem
class Model(nn.Module):
def __init__(self):
super(Model, self).__init__()
self.lin1 = nn.Linear(1,10)
self.lin2 = nn.Linear(10,1)
def forward(self, x):
x = torch.sigmoid(self.lin1(x))
x = torch.sigmoid(self.lin2(x))
return x
model = Model()
# Define loss_function from the Ordinary differential equation to solve
def ODE(x,y):
dydx, = torch.autograd.grad(y, x,
grad_outputs=y.data.new(y.shape).fill_(1),
create_graph=True, retain_graph=True)
eq = dydx + 2.* x * y # y' = - 2x*y
ic = model(torch.tensor([0.])) - 1. # y(x=0) = 1
return torch.mean(eq**2) + ic**2
loss_func = ODE
# Define the optimization
# opt = optim.SGD(model.parameters(), lr=0.1, momentum=0.99,nesterov=True) # Equivalent to blog
opt = optim.Adam(model.parameters(),lr=0.1,amsgrad=True) # Got faster convergence with Adam using amsgrad
# Define reference grid
x_data = torch.linspace(-2.0,2.0,401,requires_grad=True)
x_data = x_data.view(401,1) # reshaping the tensor
# Iterative learning
epochs = 1000
for epoch in range(epochs):
opt.zero_grad()
y_trial = model(x_data)
loss = loss_func(x_data, y_trial)
loss.backward()
opt.step()
if epoch % 100 == 0:
print('epoch {}, loss {}'.format(epoch, loss.item()))
# Plot Results
plt.plot(x_data.data.numpy(), np.exp(-x_data.data.numpy()**2), label='exact')
plt.plot(x_data.data.numpy(), y_data.data.numpy(), label='approx')
plt.legend()
plt.show()
From here I manage to get the results as shown in the fig.
enter image description here
The problems is that at the definition of the ODE functional, instead of passing (x,y) I would rather prefer to pass something like (x,fun) (where fun is my model) such that the partial derivative and specific evaluations of the model can be done with a call . So, something like
def ODE(x,fun):
dydx, = "grad of fun w.r.t x as a function"
eq = dydx(x) + 2.* x * fun(x) # y' = - 2x*y
ic = fun( torch.tensor([0.]) ) - 1. # y(x=0) = 1
return torch.mean(eq**2) + ic**2
Any ideas? Thanks in advance
EDIT:
After some trials I found a way to pass the model as an input but found another strange behavior... The new problem is to solve the ODE y'' = -2 with the BC y(x=-2) = -1 and y(x=2) = 1, for which the analytical solution is y(x) = -x^2+x/2+4
Let's modify a bit the previous code as:
import torch
import torch.nn as nn
from torch import optim
import matplotlib.pyplot as plt
import numpy as np
# Define the NN model to solve the equation
class Model(nn.Module):
def __init__(self):
super(Model, self).__init__()
self.lin1 = nn.Linear(1,10)
self.lin2 = nn.Linear(10,1)
def forward(self, x):
y = torch.sigmoid(self.lin1(x))
z = torch.sigmoid(self.lin2(y))
return z
model = Model()
# Define loss_function from the Ordinary differential equation to solve
def ODE(x,fun):
y = fun(x)
dydx = torch.autograd.grad(y, x,
grad_outputs=y.data.new(y.shape).fill_(1),
create_graph=True, retain_graph=True)[0]
d2ydx2 = torch.autograd.grad(dydx, x,
grad_outputs=dydx.data.new(dydx.shape).fill_(1),
create_graph=True, retain_graph=True)[0]
eq = d2ydx2 + torch.tensor([ 2.]) # y'' = - 2
bc1 = fun(torch.tensor([-2.])) - torch.tensor([-1.]) # y(x=-2) = -1
bc2 = fun(torch.tensor([ 2.])) - torch.tensor([ 1.]) # y(x= 2) = 1
return torch.mean(eq**2) + bc1**2 + bc2**2
loss_func = ODE
So, here I passed the model as argument and managed to derive twice... so far so good. BUT, using the sigmoid function for this case is not only not necessary but also gives a result that is far from the analytical one.
If I change the NN for:
class Model(nn.Module):
def __init__(self):
super(Model, self).__init__()
self.lin1 = nn.Linear(1,1)
self.lin2 = nn.Linear(1,1)
def forward(self, x):
y = self.lin1(x)
z = self.lin2(y)
return z
In which case I would expect to optimize a double pass through two linear functions that would retrieve a 2nd order function ... I get the error:
RuntimeError: One of the differentiated Tensors appears to not have been used in the graph. Set allow_unused=True if this is the desired behavior.
Adding the option to the definition of dydx doesn't solve the problem, and adding it to d2ydx2 gives a NoneType definition.
Is there something wrong with the layers as they are?
Quick Solution:
add allow_unused=True to .grad functions. So, change
dydx = torch.autograd.grad(
y, x,
grad_outputs=y.data.new(y.shape).fill_(1),
create_graph=True, retain_graph=True)[0]
d2ydx2 = torch.autograd.grad(dydx, x, grad_outputs=dydx.data.new(
dydx.shape).fill_(1), create_graph=True, retain_graph=True)[0]
To
dydx = torch.autograd.grad(
y, x,
grad_outputs=y.data.new(y.shape).fill_(1),
create_graph=True, retain_graph=True, allow_unused=True)[0]
d2ydx2 = torch.autograd.grad(dydx, x, grad_outputs=dydx.data.new(
dydx.shape).fill_(1), create_graph=True, retain_graph=True, allow_unused=True)[0]
More explanation:
See what allow_unused do:
allow_unused (bool, optional): If ``False``, specifying inputs that were not
used when computing outputs (and therefore their grad is always zero)
is an error. Defaults to ``False``.
So, if you try to differentiate w.r.t to a variable that is not in being used to compute the value, it will give an error. Also, note that error only occurs when you use linear layers.
This is because when you use linear layers, you have y=W1*W2*x + b = Wx+b and dy/dx is not a function of x, it is simply W. So when you try to differentiate dy/dx w.r.t x it throws an error. This error goes away as soon as you use sigmoid because then dy/dx will be a function of x. To avoid the error, either make sure dy/dx is a function of x or use allow_unused=True
I'm trying to convolve two 1D tensors in Keras.
I get two inputs from other models:
x - of length 100
ker - of length 5
I would like to get the 1D convolution of x using the kernel ker.
I wrote a Lambda layer to do it:
import tensorflow as tf
def convolve1d(x):
y = tf.nn.conv1d(value=x[0], filters=x[1], padding='VALID', stride=1)
return y
x = Input(shape=(100,))
ker = Input(shape=(5,))
y = Lambda(convolve1d)([x,ker])
model = Model([x,ker], [y])
I get the following error:
ValueError: Shape must be rank 4 but is rank 3 for 'lambda_67/conv1d/Conv2D' (op: 'Conv2D') with input shapes: [?,1,100], [1,?,5].
Can anyone help me understand how to fix it?
It was much harder than I expected because Keras and Tensorflow don't expect any batch dimension in the convolution kernel so I had to write the loop over the batch dimension myself, which requires to specify batch_shape instead of just shape in the Input layer. Here it is :
import numpy as np
import tensorflow as tf
import keras
from keras import backend as K
from keras import Input, Model
from keras.layers import Lambda
def convolve1d(x):
input, kernel = x
output_list = []
if K.image_data_format() == 'channels_last':
kernel = K.expand_dims(kernel, axis=-2)
else:
kernel = K.expand_dims(kernel, axis=0)
for i in range(batch_size): # Loop over batch dimension
output_temp = tf.nn.conv1d(value=input[i:i+1, :, :],
filters=kernel[i, :, :],
padding='VALID',
stride=1)
output_list.append(output_temp)
print(K.int_shape(output_temp))
return K.concatenate(output_list, axis=0)
batch_input_shape = (1, 100, 1)
batch_kernel_shape = (1, 5, 1)
x = Input(batch_shape=batch_input_shape)
ker = Input(batch_shape=batch_kernel_shape)
y = Lambda(convolve1d)([x,ker])
model = Model([x, ker], [y])
a = np.ones(batch_input_shape)
b = np.ones(batch_kernel_shape)
c = model.predict([a, b])
In the current state :
It doesn't work for inputs (x) with multiple channels.
If you provide several filters, you get as many outputs, each being the convolution of the input with the corresponding kernel.
From given code it is difficult to point out what you mean when you say
is it possible
But if what you mean is to merge two layers and feed merged layer to convulation, yes it is possible.
x = Input(shape=(100,))
ker = Input(shape=(5,))
merged = keras.layers.concatenate([x,ker], axis=-1)
y = K.conv1d(merged, 'same')
model = Model([x,ker], y)
EDIT:
#user2179331 thanks for clarifying your intention. Now you are using Lambda Class incorrectly, that is why the error message is showing.
But what you are trying to do can be achieved using keras.backend layers.
Though be noted that when using lower level layers you will lose some higher level abstraction. E.g when using keras.backend.conv1d you need to have input shape of (BATCH_SIZE,width, channels) and kernel with shape of (kernel_size,input_channels,output_channels). So in your case let as assume the x has channels of 1(input channels ==1) and y also have the same number of channels(output channels == 1).
So your code now can be refactored as follows
from keras import backend as K
def convolve1d(x,kernel):
y = K.conv1d(x,kernel, padding='valid', strides=1,data_format="channels_last")
return y
input_channels = 1
output_channels = 1
kernel_width = 5
input_width = 100
ker = K.variable(K.random_uniform([kernel_width,input_channels,output_channels]),K.floatx())
x = Input(shape=(input_width,input_channels)
y = convolve1d(x,ker)
I guess I have understood what you mean. Given the wrong example code below:
input_signal = Input(shape=(L), name='input_signal')
input_h = Input(shape=(N), name='input_h')
faded= Lambda(lambda x: tf.nn.conv1d(input, x))(input_h)
You want to convolute each signal vector with different fading coefficients vector.
The 'conv' operation in TensorFlow, etc. tf.nn.conv1d, only support a fixed value kernel. Therefore, the code above can not run as you want.
I have no idea, too. The code you given can run normally, however, it is too complex and not efficient. In my idea, another feasible but also inefficient way is to multiply with the Toeplitz matrix whose row vector is the shifted fading coefficients vector. When the signal vector is too long, the matrix will be extremely large.
I'm using tensorflow to replicate a neural network for the MNIST dataset, previously programmed in skflow. Here is the model in skflow:
import tensorflow.contrib.learn as skflow
from sklearn import metrics
from sklearn.datasets import fetch_mldata
from sklearn.cross_validation import train_test_split
mnist = fetch_mldata('MNIST original')
train_dataset, test_dataset, train_labels, test_labels = train_test_split( mnist.data, mnist.target, test_size=10000, random_state=42)
classifier = skflow.TensorFlowDNNClassifier(hidden_units=[1200, 1200], n_classes=10, optimizer="SGD", learning_rate=0.01, batch_size=128, steps=1000)
classifier.fit(train_dataset, train_labels)
score = metrics.accuracy_score(test_labels, classifier.predict(test_dataset))
print("Accuracy: %f" % score)
This model get 0.950600 of accuracy.
But the model replicated in tensorflow gets nan in the loss fuction and fails to improve (I think it's not related with Tensorflow NaN bug? since I'm using tf.nn.softmax_cross_entropy_with_logits).
I can't figure out why, since the setup of the model in tensorflow is the same than in the model in skflow. The only thing I'm unsure if it's the same, is on how skflow initializes the weights of the network, I searched that part in the code of skflow but I have not found it.
Here is the code in tensorflow:
import numpy as np
import tensorflow as tf
from sklearn.cross_validation import train_test_split
from sklearn.datasets import fetch_mldata
mnist = fetch_mldata('MNIST original')
num_labels = len(np.unique(mnist.target))
num_pixels = mnist.data.shape[1]
#reshape labels to one hot encoding
labels = (np.arange(num_labels) == mnist.target[:, None]).astype(np.float32)
#create train_dataset of 60000 and test_dataset of 10000 elem
train_dataset, test_dataset, train_labels, test_labels = train_test_split(mnist.data, labels, test_size=10000, random_state=42)
def accuracy(predictions, labels):
return (100.0 * np.sum(np.argmax(predictions, 1) == np.argmax(labels, 1)) / predictions.shape[0])
batch_size = 128
graph = tf.Graph()
with graph.as_default():
# Input data.
tf_train_dataset = tf.placeholder(tf.float32,
shape=(batch_size, num_pixels))
tf_train_labels = tf.placeholder(tf.float32, shape=(batch_size, num_labels))
tf_test_dataset = tf.cast(tf.constant(test_dataset), tf.float32)
w_hidden = tf.Variable(tf.truncated_normal([num_pixels, 1200]))
b_hidden = tf.Variable(tf.zeros([1200]))
hidden = tf.nn.relu(tf.matmul(tf_train_dataset, w_hidden) + b_hidden)
w_hidden_2 = tf.Variable(tf.truncated_normal([1200, 1200]))
b_hidden_2 = tf.Variable(tf.zeros([1200]))
hidden2 = tf.nn.relu(tf.matmul(hidden, w_hidden_2) + b_hidden_2)
w = tf.Variable(tf.truncated_normal([1200, num_labels]))
b = tf.Variable(tf.zeros([num_labels]))
logits = tf.matmul(hidden2, w) + b
loss = tf.reduce_mean(tf.nn.softmax_cross_entropy_with_logits(
logits, tf_train_labels))
# Optimizer.
optimizer = tf.train.GradientDescentOptimizer(0.01).minimize(loss)
# Predictions for the training, and test data.
train_prediction = tf.nn.softmax(logits)
test_prediction = tf.nn.softmax(tf.matmul(tf.nn.relu(tf.matmul(tf.nn.relu(tf.matmul(tf_test_dataset, w_hidden) + b_hidden), w_hidden_2) + b_hidden_2), w) + b)
num_steps = 1001
with tf.Session(graph=graph) as session:
tf.initialize_all_variables().run()
print("Initialized")
for step in range(num_steps):
# Pick an offset within the training data, which has been randomized.
offset = (step * batch_size) % (train_labels.shape[0] - batch_size)
# Generate a minibatch.
batch_data = train_dataset[offset:(offset + batch_size), :]
batch_labels = train_labels[offset:(offset + batch_size), :]
# Prepare a dictionary telling the session where to feed the minibatch.
feed_dict = {tf_train_dataset: batch_data, tf_train_labels: batch_labels}
_, l, predictions = session.run( [optimizer, loss, train_prediction], feed_dict=feed_dict)
if (step % 100 == 0):
print("Minibatch loss at step %d: %f" % (step, l))
print("Minibatch accuracy: %.1f%%" % accuracy(predictions, batch_labels))
print("Test accuracy: %.1f%%" % accuracy(test_prediction.eval(), test_labels))
I'm clueless on what might be the issue. Any suggestions?
Edited 1: As I was suggested, I tried replacing tf.Variable calls with tf.get_variable("w_hidden", [num_pixels, 1200]), but I got Nans.
Also, I used skflow.ops.dnn op for doing the layers and used my own loss and etc, and still got Nans.
Edited 2: Turns out it is not a problem of weight initialization. It seems that the gradients are too unstable (in the tensorflow model) and that lead the loss to become NaN. As in Adding multiple layers to TensorFlow causes loss function to become Nan, I slowed the learning rate by an order of magnitude, and it worked out.
Now what I don't understand is what differs between the SGD optimizer of skflow and the one above. Or what is the explanation that they "seem" equal, but they need different learning rates?
Initialization in skflow relies on tf.get_variable default initialization - uniform_unit_scaling_initializer (see this for detailed description).
You can try replacing your tf.Variable calls with something like tf.get_variable("w_hidden", [num_pixels, 1200]).
Alternative, is to start with using skflow.ops.dnn op that will do the layers for you but you still do your own loss and etc.
Also please let me know if you there a clear usecase that forced you to rewrite things in pure TensorFlow instead of using skflow - I would love to address it. You can always write custom model via passing model_fn into TensorFlowEstimator and still use training / batching / saving and etc functionality.