Making a list with some strings only - python-3.7

Question

Okay so i have a string of data
data= "DTG: 20191005/0925Z VAAC: LONDON VOLCANO: ASKJA"
so i want to make it a dictionary like
{DTG:'20191005/0925Z',VAAC:'LONDON',VOLCANO:'ASKJA'}
i used split function to split these up and make a list but somehow i cant seem to make it
print(data.split(":"))
I have to make it as a list like:
{DTG:'20191005/0925Z',VAAC:'LONDON',VOLCANO:'ASKJA'}
Can anyone help?
ok so if u can do the above one how about data from the file
https://www.sendspace.com/file/zg0kmh

Answer 1

To begin with, {DTG:'20191005/0925Z',VAAC:'LONDON',VOLCANO:'ASKJA'}
is called a dictionary and not a list.
Now to create that dictionary, you woukd want to split the string on whitespace , rather than :, then you can zip alternate elements together to make a tuple of keys and values, then convert that zip to dict
Note that the below solution assumes that the each individual word is a key or a value. If you have a value or a key like hello world, this logic won't work, then perhaps another logic to split the string (another character instead of whitespace, or a regex split) will be more beneficial
data= "DTG: 20191005/0925Z VAAC: LONDON VOLCANO: ASKJA"
#Split string on whitespace
arr = data.split()
#Zip alternate elements together
arr_zip = zip(arr[::2], arr[1::2])
#Convert dict to zip and print it
dct = dict(arr_zip)
print(dct)
The output will be {'DTG:': '20191005/0925Z', 'VAAC:': 'LONDON', 'VOLCANO:': 'ASKJA'}

Answer 2

Assuming that your data is in exactly this format, you could use the following code:
data = "DTG: 20191005/0925Z VAAC: LONDON VOLCANO: ASKJA"
parts = data.split()
output = {
'DTG': parts[1],
'VAAC': parts[3],
'VOLCANO': parts[5],
}
However, this doesn't take into account spaces very well, if there are spaces in your data (e.g. "NEW YORK").

Answer 3

Using dict.update:
data = "DTG: 20191005/0925Z VAAC: LONDON VOLCANO: ASKJA"
d = dict()
d.update(s.split(':') for s in data.replace(': ', ':').split())
Output:
{'DTG': '20191005/0925Z', 'VAAC': 'LONDON', 'VOLCANO': 'ASKJA'}

Answer 4

data= "DTG: 20191005/0925Z VAAC: LONDON VOLCANO: ASKJA"
data = data.split()
dic = {}
for d in data:
if ":" in d:
key = d.replace(":","")
else:
dic[key] = d
print(dic)
Output:
{'DTG': '20191005/0925Z', 'VAAC': 'LONDON', 'VOLCANO': 'ASKJA'}