I have vertex "office" and property "name" on OrientDB. I want to find the offices, by name, where the name does not have a "-" as the third character of the string. I imagine this would require some java code within the gremlin query.This is my best attempt, but it is resulting in office names that do in fact have a "-" as their third character.
g.V().hasLabel('office')
.where(values('name').map{it.get().charAt(2)}.is(neq('-')))
.project('Office Name')
.by(values('name'))
Since Gremlin doesn't support String operations (like split, charAt, etc.), your only chance is a lambda. Seems like you figured that out already, but your solution looks too overcomplicated to me. You can use something much simpler, like:
g.V().hasLabel('office').
has('name', filter {it.get()[2] != '-'}).
project('Office Name').
by('name')
However, note, that this filter will throw an exception if the office namer has less than 3 characters. Thus, you should better check that the String is long enough:
g.V().hasLabel('office').
has('name', filter {it.get().length() > 2 && it.get()[2] != '-'}).
project('Office Name').
by('name')
...or use RegEx pattern matching (which is pretty nice and easy in Groovy):
g.V().hasLabel('office').
has('name', filter {it.get() ==~ /.{2}-.*/}).
project('Office Name').
by('name')
The main reason why your traversal didn't work though, is that charAt returns a Character which is then compared to the String -, hence every office name will pass the neq filter.
Related
I have two arrays of strings and I want to check if a string of array a matches a string from array b. Those strings are phone numbers that might come in different formats. For example:
Array a might have a phone number with prefix like so +44123123123 or 0044123123123
Array b have a standard format without prefixes like so 123123123
So I'm looking for a regex that can match a part of a string like +44123123123 with 123123123
Btw I'm using Swift but I don't think there's a native way to do it (at least a more straightforward solution)
EDIT
I decided to reactivate the question after experimenting with the library #Larme mentioned because of inconsistent results.
I'd prefer a simper solution as I've stated earlier.
SOLUTION
Thanks guys for the responses. I saw many comments saying that Regex is not the right solution for this problem. And this is partly true. It could be true (or false) depending on my current setup/architecture ( which thinking about it now I realise that I should've explained better).
So I ended up using the native solution (hasSuffix/contains) but to do that I had to do some refactoring on the way the entire flow was structured. In the end I think it was the least complicated solution and more performant of the two. I'll give the bounty to #Alexey Inkin for being the first to mention the native solution and the right answer to #Ωmega for providing a more complete solution.
I believe regex is not the right approach for this task.
Instead, you should do something like this:
var c : [String] = b.filter ({ (short : String) -> Bool in
var result = false
for full in a {
result = result || full.hasSuffix(short)
}
return result
})
Check this demo.
...or similar solution like this:
var c : [String] = b.filter ({ (short : String) -> Bool in
for full in a {
if full.hasSuffix(short) { return true }
}
return false
})
Check this demo.
As you do not mention requirements to prefixes, the simplest solution is to check if string in a ends with a string in b. For this, take a look at https://developer.apple.com/documentation/swift/string/1541149-hassuffix
Then, if you have to check if the prefix belongs to a country, you may replace ^00 with + and then run a whitelist check against known prefixes. And the prefix itself can be obtained as a substring by cutting b's length of characters. Not really a regex's job.
I agree with Alexey Inkin that this can also nicely be solved without regex. If you really want a regex, you can try something like the following:
(?:(\+|00)(93|355|213|1684|376))?(\d+)
^^^^^^^^^^^^^^^^^^^^^ Add here all your expected country prefixes (see below)
^^^ ^^ Match a country prefix if it exists but don't give it a group number
^^^^^^^ Match the "prefix-prefix" (+ or 00)
^^^^ Match the local phone number
Unfortunatly with this regex, you have to provide all the expected country prefixes. But you can surely get this list online, e.g. here: https://www.countrycode.org
With this regex above you will get the local phone number in matching group 3 (and the "prefix-prefix" in group 1 and the country code in group 2).
Using Kapacitor 1.3 and I am trying to use the following where node to keep measurements with an empty tag. Nothing is passing through and I get the same result with ==''.
| where(lambda: 'process-cpu__process-name' =~ /^$/)
I can workaround this issue using a default value for missing tags and filter on this default tag, in the following node but I am wondering if there is a better way structure the initial where statement and avoid an extra node.
| default()
.tag('process-cpu__process-name','system')
| where(lambda: \"process-cpu__process-name\" == 'system' )
Sure it doesn't pass, 'cause this
'process-cpu__process-name'
is a string literal it TICKScript, not a reference to a field, which is
"process-cpu__process-name"
You obviously got the condition always false in this case.
Quite common mistake though, especially for someone with previous experience with the languages that tolerates both single & double quote for mere string. :-)
Also, there's a function in TICKScript lambda called strLength(), find the doc here, please.
I'm a total erlang noob and I just want to see what's in a particular table I have. I want to just "select *" from a particular table to start with. The examples I'm seeing, such as the official documentation, all have column restrictions which I don't really want. I don't really know how to form the MatchHead or Guard to match anything (aka "*").
A very simple primer on how to just get everything out of a table would be very appreciated!
For example, you can use qlc:
F = fun() ->
Q = qlc:q([R || R <- mnesia:table(foo)]),
qlc:e(Q)
end,
mnesia:transaction(F).
The simplest way to do it is probably mnesia:dirty_match_object:
mnesia:dirty_match_object(foo, #foo{_ = '_'}).
That is, match everything in the table foo that is a foo record, regardless of the values of the fields (every field is '_', i.e. wildcard). Note that since it uses record construction syntax, it will only work in a module where you have included the record definition, or in the shell after evaluating rr(my_module) to make the record definition available.
(I expected mnesia:dirty_match_object(foo, '_') to work, but that fails with a bad_type error.)
To do it with select, call it like this:
mnesia:dirty_select(foo, [{'_', [], ['$_']}]).
Here, MatchHead is _, i.e. match anything. The guards are [], an empty list, i.e. no extra limitations. The result spec is ['$_'], i.e. return the entire record. For more information about match specs, see the match specifications chapter of the ERTS user guide.
If an expression is too deep and gets printed with ... in the shell, you can ask the shell to print the entire thing by evaluating rp(EXPRESSION). EXPRESSION can either be the function call once again, or v(-1) for the value returned by the previous expression, or v(42) for the value returned by the expression preceded by the shell prompt 42>.
I have a Mongo search set up that goes through my entries based on numerous criteria.
Currently the easiest way (I know it's not performance-friendly due to using wildcards, but I can't figure out a better way to do this due to case insensitivity and users not putting in whole words) is to use regex wildcards in the search. The search ends up looking like this:
{ gender: /Womens/i, designer: /Voodoo Girl/i } // Should return ~200 results
{ gender: /Mens/i, designer: /Voodoo Girl/i } // Should return 0 results
In the example above, both searches are returning ~200 results ("Voodoo Girl" is a womenswear label and all corresponding entries have a gender: "Womens" field.). Bizarrely, when I do other searches, like:
{ designer: /Voodoo Girl/i, store: /Store XYZ/i } // should return 0 results
I get the correct number of results (0). Is this an order thing? How can I ensure that my search only returns results that match all of my wildcarded queries?
For reference, the queries are being made in nodeJS through a simple db.products.find({criteria}) lookup.
To answer the aside real fast, something like ElasticSearch is a wonderful way to get more powerful, performant searching capabilities in your app.
Now, the reason that your searches are returning results is that "mens" is a substring of "womens"! You probably want either /^Mens/i and /^Womens/i (if Mens starts the gender field), or /\bMens\b/ if it can appear in the middle of the field. The first form will only match the given field from the beginning of the string, while the second form looks for the given word surrounded by word boundaries (that is, not as a substring of another word).
If you can use the /^Mens/ form (note the lack of the /i), it's advisable, as anchored case-sensitive regex queries can use indexes, while other regex forms cannot.
$regex can only use an index efficiently when the regular expression has an anchor for the beginning (i.e. ^) of a string and is a case-sensitive match.
Sql query:
select * from test_mart
where replace(replace(replace(replace(replace(replace(lower(name),'+'),'_'),'the '),' the'),'a '),' a')='tariq'
I can fire following query very easy, if I have to use simply Sqlite... but In current project I am using Core Data so not familiar about NSPredicate much.
The functionality talks about removing all BUT alphanumeric characters, which means removing special characters.
The characters that should be valid in the comparison would be
ABCDEFGHIJKLMNOPQRESTUVWXYZ1234567890
But we should not fail the comparison for the following characters
:;,~`!##$%^&*()_-+="'/?.>,<|\
Or for the following words
'the' 'an' 'a'
Some examples:
'Walmart' would be seen as the same payee as 'Wal-Mart'
'The Shoe Store' would be seen as the same payee as 'Shoe Store'
'Domino's Pizza' would be seen as the same payee as 'Dominos Pizza'
'Test Payee;' would be seen as the same payee as 'Test Payee'
Can any one suggest appropriate Predicates/Regular Expression ?
Thanks
I would have an extra field in the data base which would be a processed version of the original with all the irrelevant characters stripped out. Then use that for comparisons.
You might want to look at the soundex algorithm which may suite your purposes better... Soundex
It seems to me that you would want to normalize your data before it every gets set into the core data store. So if you're given "Wal-Mart", normalize it to "walmart" once, and then save it. Then you won't be doing all of this expensive on-the-fly comparison many many times.
The normalization would be fairly simple, given your rules:
Strip the words "a", "an", and "the"
Remove punctuation