I'm looking for a simple way to convert a string of 1's and 0's to its hex equivalent.
[string]$bintest = "1100110101011111"
[long]$testnumber = [System.Convert]::ToInt32($bintest,2)
"{0:x4}" -f $testnumber
The code above works as needed but it seems like too many steps.
Is there a way to avoid converting the string to decimal before convering it to hex?
the shortest answer I could create
'{0:x}' -f [Convert]::ToInt32('1100110101011111',2)
Hope it helps
Edit: As I refreshed I saw the comment of #Ansgar Wiechers, two persons one idea I guess.
Related
I have input with floats stored like 1000,50, ie. the decimal points are replaced by commas.
Is there an option in K to load these numbers directly into floats ?
When using
data:("SFF" ;";",";") 0:. filename
I get 0ns, of course, because the numbers are not recognized as floats.
I load them as strings now, and convert them using ssr like
c:.:' .q.ssr'[data;",";"."]
but that is extremely slow.
Is there an option somewhere to have K load these numbers in CCC,CC format as floats directly ? Normal format and ccc,cc format are not mixed, any file has just one of them.
If there is not, I imagine that it must by quite easy to replace a "." somewhere in the Q-binary where the load-function sits, with a ",", to get a version which loads these numbers. Has anybody tried that ? Or any other tip to load big files with these numbers in reasonable time ?
Cheers,
Co
If ssr' is slow for your task you may find this tiny function useful:
c2p:{c:-1_sums count each x;p:ss[r:raze x;","];r[p]:".";(0,c) _ r}
Update: an alternative version:
c2p:{p:ss[r:raze x;","];r[p]:".";(0,-1_sums count'[x])_r}
It concatenates all strings into a single long string, finds positions of commas, replaces commas with periods then splits that long string:
q)N:1000000
q)s:string[N?100000],'",",'string N?1000
q)\t r1:ssr'[s;",";"."]
4284
q)\t r2:c2p s
242
q)r1~r2
1b
I was thinking something like find (?) combined with indexing/applying
q)N:1000000
q)s:string[N?100000],'",",'string N?1000
q)\ts {s[x;y]:"."}./:flip(til count s;s?\:",")
967 52972144
q)s
"93912.794"
"57144.788"
"77809.659"
"7839.47"
"6363.523"
"44761.244"
"65699.712"
It's not perfect but that's the general idea. I'm sure there is an easier way...
I am trying to sort the following data in the Matlab, but not getting the expected output what I need.
Here is data:
'1B-3A-5A'
'1A-3A-19A'
'2A-2A-4A-5A'
'2B-2A-5A'
'2A-4A-5A'
'2C-5A-30A'
'11A-3A-19A
'3A-19A-42C'
'4A-4A-12A'
'19A-21A-42C'
'25A-41D'
'41C-41C'
'39C-41C'
'43E'
'39A-41D'
'1A-3A-5A-7A'
'7C-27A-28A'
I need the sorted list such that it considers the first number then the alphabet to sort the list like below
'1A-3A-19A'
'1A-3A-5A-7A'
'1B-3A-5A'
'2A-2A-4A-5A'
'2A-4A-5A'
'2B-2A-5A'
'2C-5A-30A'
'3A-19A-42C'
'4A-4A-12A'
'7C-27A-28A'
'11A-3A-19A
'19A-21A-42C'
'25A-41D'
'39A-41D'
'39C-41C'
'41C-41C'
'43E'
Can you please suggest a way to do it? I tried all ways but it doesn't sort it like I want. Thanks!!
How about using sort or sortrows? This does actually sort strings as well:
If A is a string, then sort(A) sorts according to the ASCII dictionary order. The sort is case sensitive with uppercase letters appearing in the output before the lowercase letters.
As #StewieGriffin pointed out, this sorts 11a before 1a. Conveniently Douglas Schwarz has already produced a code that overcomes exactly this problem of alphanumeric sorting on numerics first and characters after.
As the title suggests I'm looking to detect where the numbers are in a string and then to just take the substring from the larger string. EG
If I have say zero89 or eight78, I would just like zero or nine returned. When using the strsplit function I have:
strsplit('zero89', but what do I put here?)
Interested in regexp that will provide you more options to explore with?
Extract numeric digits -
regexp('zero89','\d','match')
Extract anything other than digits -
regexp('zero89','\d+','Split')
strsplit('zero89', '\d', 'DelimiterType', 'RegularExpression')
Or just using regexp:
regexp('zero89','\D+','match')
I got the \D+ from here
Assuming you mean this strsplit?
strsplit('zero89', '8')
I want to convert int to string and then concatenate dot with it. Here is the formula
totext({#SrNo})+ "."
It works perfectly but not what i want. I want to show at as
1.
but it shows me in this way
1.00.
it means that when i try to convert int to string it convert it into number with precision of two decimal zeros. Can someone tell me how can i show it in proper format. For information i want to tell you that SrNo is running total.
ToText(x, y, z, w) Function can use
x=The number to convert to text
y=The number of decimal places to include in result (optional). The value will be rounded to that decimal place.
z=The character to use as the thousands separator. If you don’t specify one, it will use your application default. (Optional.)
w=The character to use as the decimal separator. If you don’t specify one, it will use your application default. (Optional.)
Examples
ToText(12345.678) = > “12345.678″
ToText(12345.678,2) = > “12345.67″
ToText(12345.678,0) = > “12345″
You can try this :
totext({fieldname},0)
Ohhh I got the answer it was so simple.
totext takes 4 parameters
First parameter is value which is going to be converted
Second parameter is number of decimal previsions.
Third parameter is decimal separator. like (1,432.123) here dot(.) is third parameter.
Forth parameter is thousand separator. like (1,432) here comma(,) is forth parameter.
Example{
totext("1,432.1234",2) results 1,432.12
totext("1,432.1234",2,' " ') results 1,432"1234
totext("1,432.1234",2,' " ', ' : ') results 1:432,1234
}
Although i think this example may be not so good but i just want to give you an idea. This is for int conversion for date it has 2 parameters.
value to be converted and format of date.
i am relatively new to NSRegularExpression and just can't come up with a pattern to find a string within a string....
here is the string...
##$294#001#[12345-678[123-456-7#15665#2
I want to extract the string..
#001#[12345-678[123-456-7#
for more info I know that there will be 3 digits(like 001) between two # 's and 20 characters between the last two # 's..
I have tried n number of combinations but nothing seem to work. any help is appreciated.
How about something like this:
#[0-9]{3}#.{20}#
If you know that the 20 characters will always consist of digits, [ and -, your pattern would become:
#[0-9]{3}#[0-9\[\-]{20}#
Be careful with the backslashes: When you use create the pattern with a string literal (#"..."), you need to add an extra backslash before each backslash.
You can test NSRegularExpression patterns without recompiling each time by using RegexTester https://github.com/liyanage/regextester