I want to update a file on remote linux server. For this i am using sed command. in that i have to first search that line then update value
i have file with following content:
GRUB_DEFAULT=saved
GRUB_DISABLE_SUBMENU=true
GRUB_TERMINAL_OUTPUT="console"
GRUB_CMDLINE_LINUX="ankur"
GRUB_DISABLE_RECOVERY="true"
so using sed command i have to append sharma in double qoutes
means after execution line will be grub_cmdline_linux = "ankur sharma"
i have tried this command
sed -i 's+\(GRUB_CMDLINE_LINUX.*\)+\1 sharma+g' '/etc/default/grub.bak'
by this command sharma is appending at the end of the line but it should be append inside the double qoutes
Expected output:
GRUB_DEFAULT=saved
GRUB_DISABLE_SUBMENU=true
GRUB_TERMINAL_OUTPUT="console"
GRUB_CMDLINE_LINUX="ankur sharma"
GRUB_DISABLE_RECOVERY="true"
Wouldn't it be something like
sed '/^GRUB_CMDLINE_LINUX=/s/"$/ sharma"/' /etc/default/grub.bak
?
$ sed 's/GRUB_CMDLINE_LINUX="[^"]*/& sharma/' file
GRUB_DEFAULT=saved
GRUB_DISABLE_SUBMENU=true
GRUB_TERMINAL_OUTPUT="console"
GRUB_CMDLINE_LINUX="ankur sharma"
GRUB_DISABLE_RECOVERY="true"
Related
I need to replace a version string in a file. My search pattern is regex
and my replacement is a variable.
String search = "\\d+.\\d+.\\d+-.\\d+"
String replace = "1.0.0-${BUILD_ID}"
MyFile = "foo"
sh ("""
sed -i -r "s/($search/$replace/g)" $MyFile
""")
The result I am getting
+ sed -i -r s/(\d+.\d+.\d+-.\d+/1.0.0-25/g) foo
sed: bad option in substitution expression
I found the issue with my code. If I remove parenthesis (), the string replacement works as a charm.
My file contains x number of lines, I would like to remove the string before and after the reference string at the beginning and end of each line.
The reference string and string to remove are separated by space.
The file contains :
test.user.passs
test.user.location
global.user
test.user.tel
global.pass
test.user.email string_err
#ttt...> test.user.car ->
test.user.address
è_ 788 test.user.housse
test.user.child
{kl78>&é} global.email
global.foo
test.user.foo
How to remove the string at the start of each line which contain "test" string and also the end of each line separated by space or tab with sed?
The desired result is :
test.user.passs
test.user.location
global.user
test.user.tel
global.pass
test.user.email
test.user.car
test.user.address
test.user.housse
test.user.child
{kl78>&é} global.email
global.foo
test.user.foo
I interpret your question as: find the first word that is "word characters and at least one dots"
Tcl:
echo '
set fh [open [lindex $argv 1] r]
while {[gets $fh line] != -1} {puts [regexp -inline {\w+(?:\.\w+)+} $line]}
' | tclsh - file
sed
sed -r 's/.*\<([[:alpha:]]+(\.[[:alpha:]]+)).*/\1/' file
perl
perl -nE '/(\w+(\.\w+)+)/ and say $1' file
using sed like
sed -r 's/^[^ ]+[ ]+([^ ]+)[ ]+[^ ]*/\1/' file
This might work for you (GNU sed):
sed -r 's/.*(test\S+).*/\1/' file
I have the following header :
#SRR1561197.1/1
#SRR1561197.2/1
#SRR1561197.3/1
#SRR1561197.4/1
I want to Add few letters after # and before SRR like this:
#MexD1SRR1561197.1/1
#MexD1SRR1561197.2/1
#MexD1SRR1561197.3/1
#MexD1SRR1561197.4/1
I tried:
sed 's/#/#MexD1/File,fastq > change.fastq
This results in empty file..
Use sed with the in file replacement option. The g at the end makes it global.
sed -i 's/#/#MexD1/g' file
To fix your code.
sed 's/#/#MexD1/g' File.fastq > change.fastq
You have to escape it: sed s/\#/\#MexD1/g source-file-name > change.fastq
My actual text document contains the following lines.
san.20140226.sbc.UTM
san.201402261.UTM
san.2014022613.UTM
I want the below output:
'san.20140226.sbc.UTM',
'san.201402261.UTM',
'san.2014022613.UTM',
You could try this sed command,
sed "s/.*/'&',/g" file
Example:
$ echo 'san.20140226.sbc.UTM' | sed "s/.*/'&',/g"
'san.20140226.sbc.UTM',
OR
$ echo 'san.20140226.sbc.UTM' | sed "s/^/'/;s/$/',/"
'san.20140226.sbc.UTM',
^ matches the start of a line and $ matches the end of a line.
When I want to print an output like this
./myScript (prints some lines)
or
cat myFile
I want the output to show with linebreakers , for example each line will include not more than 100 chars.
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaffffff
vbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbf
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
there is something I can add to the command line to get this result ?
Thanks.
You can use sed if you want the line terminator as ,.
$ cat myfile
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaffffffvbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbfaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
$ sed -r 's/.{50}/&,\n/g' myfile
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa,
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaffffffvbbb,
bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbfaaaaaa,
aaaaaaaaaaaaaaaaaaaaaaaaaaaaa
fold is another utility but won't add a , at the end
$ fold -w50 myfile
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaffffffvbbb
bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbfaaaaaa
aaaaaaaaaaaaaaaaaaaaaaaaaaaaa