I've got a table of different transactions with the according timestamps:
Table: Transactions
Recipient Amount Date
--------------------------------------------------
Bob 52 2019-04-21 11:06:32
Jack 12 2019-06-26 12:08:11
Jill 50 2019-04-19 24:50:26
Bob 90 2019-03-20 16:34:35
Jack 81 2019-03-25 12:26:54
Jenny 53 2019-04-20 09:07:02
Jenny 5 2019-03-29 06:15:35
Now I want to get all of Jack's transactions for today and overall:
Result
Person Amount_Today Amount_Overall
-----------------------------------------------
Jack 12 93
What's the most performant way to archieve this in postgresql? At the moment I run two queries - this one is for Amount_Today:
select Recipient, sum(Amount)
from Transactions
where Recipient = 'Jack'
and created_at > NOW() - INTERVAL '1 day'
But that doesn't seem like the right way.
You can use the filter clause:
select Recipient,
sum(Amount) as Amount_Overall,
sum(Amount) FILTER (WHERE created_at > NOW() - INTERVAL '1 day') as Amount_Today
from Transactions
where Recipient = 'Jack'
GROUP BY recipient;
You have probably realized this, but now() - interval '1 day' is not really today, it is the last 24 hours. You could use date_trunc if you want just today.
Related
I have a table like below (tablename: sales)
sales_datetime
sales
salesman
2022-08-01 09:00:00
100
John
2022-08-01 11:00:00
200
John
2022-08-02 10:00:00
100
Peter
2022-08-02 13:00:00
300
John
2022-08-04 14:00:00
300
Peter
2022-08-05 12:00:00
100
John
2022-08-05 16:00:00
200
John
From that table I want to make a summary sales for 5 days period for each salesman. So the summary table that I want is look like this
periode
total_sales
salesman
2022-08-01
300
John
2022-08-01
0
Peter
2022-08-02
300
John
2022-08-02
100
Peter
2022-08-03
0
John
2022-08-03
0
Peter
2022-08-04
0
John
2022-08-04
300
Peter
2022-08-05
300
John
2022-08-05
0
Peter
I have created following query (PSQL) but the results were not same as I want. Assume today is 2022-08-05
with dateseries as
(select generate_series(current_date-'4 days'::interval,
current_date::date,
'1 day'::interval)::date as periode)
select d.periode,coalesce(sum(s.sales),0) as total_sales,s.salesman from dateseries d
left outer join sales s
on d.periode=s.sales_datetime::date
group by d.periode, s.salesman order by d.periode
results:
periode
total_sales
salesman
2022-08-01
300
John
2022-08-02
300
John
2022-08-02
100
Peter
2022-08-03
0
(NULL)
2022-08-04
300
Peter
2022-08-05
300
John
Any advices would be so great. Thank you
Step by step first aggregate the daily sales per salesperson (aggregated_sales CTE), create a list of days to report (days CTE), create a list of salesmen (salesmen CTE) and then query the sales for each day/salesman pair.
with aggregated_sales as
(
select sales_datetime::date sales_date, sum(sales) sales, salesman
from sales group by sales_datetime::date, salesman
),
days(sales_date) as
(
select d::date
from generate_series('2022-08-01', '2022-08-08', interval '1 day') d
),
salesmen (salesman) as
(
select distinct salesman from sales
)
select sales_date, coalesce(sales, 0) sales, salesman
from (select * from days cross join salesmen) fl
left outer join aggregated_sales ags using (sales_date, salesman);
The query may be shorter if CTEs are inlined yet I think that clarity and readability are more important than mere size.
In order to "make a summary sales for 5 days period for each salesman" replace generate_series('2022-08-01', '2022-08-08', interval '1 day') with generate_series(current_date - 4, current_date, interval '1 day').
the results were not same as I want. Assume today is 2022-08-05
Please note that '2022-08-05'::date - '5 days'::interval will give you 2022-07-31, and not 2022-08-01 as you assume. Because of that, I think you meant it to be current_date - '4 days'::interval.
With that out of the way, here is one possible query:
with sales_by_date as (
select
salesman,
sales_datetime::date,
sum(sales) total_sales
from sales
where
-- assuming you need to have totals for salesmen that had sales in specified period only
sales_datetime::date between current_date-'4 days'::interval and current_date
group by
salesman,
sales_datetime::date),
dateseries as (
select
distinct salesman,
generate_series(current_date-'4 days'::interval, current_date, '1 day'::interval)::date as periode
from sales_by_date)
select
d.periode,
coalesce(s.total_sales, 0) total_sales,
d.salesman
from dateseries d
left join sales_by_date s
on d.periode = s.sales_datetime
and d.salesman = s.salesman
order by d.periode, d.salesman;
But you still have to figure out some requirements for this problem. E.g. what if for the specified period there are no sales at all in the sales table?
I want to count %days when a user was active. A query like this
select
a.id,
a.created_at,
CURRENT_DATE - a.created_at::date as days_since_registration,
NOW() as current_d
from public.accounts a where a.id = 3257
returns
id created_at days_since_registration current_d tot_active
3257 2022-04-01 22:59:00.000 1 2022-04-02 12:00:0.000 +0400 2
The person registered less than 24 hours ago (less than a day ago), but there are two distinct dates between the registration and now. Hence, if a user was active one hour before midnight and one hour after midnight, he is two days active in less than a day (active 200% of days)
What is the right way to count distinct dates and get 2 for a user, who registered at 23:00:00 two hours ago?
WITH cte as (
SELECT 42 as userID,'2022-04-01 23:00:00' as d
union
SELECT 42,'2022-04-02 01:00:00' as d
)
SELECT
userID,
count(d),
max(d)::date-min(d)::date+1 as NrOfDays,
count(d)/(max(d)::date-min(d)::date+1) *100 as PercentageOnline
FROM cte
GROUP BY userID;
output:
userid
count
nrofdays
percentageonline
42
2
2
100
I have two tables, today's_table and yeterday's_table.
I need to compare the data for an interval of 15 mins at exact same times for today and yesterday.
For example, for below data let's I need to check from 00:00:00 and 00:15:00 on 20201202 and 20201202. So difference should come out as '3' since the yesterday's_table has 8 records and today's_table has 5 records.
today's_table:
Yesterday's table:
I tried something like; (consider now() is 00:15:00)
select count(*) from yeterday's_table where time between now() - interval "24 hours" and now() - interval "23 hours 45 mins"
minus
select count(*) from today's_table where time = now() - interval "15 minutes";
is there any other way to do this?
You can easily do this with subqueries:
SELECT b.c - a.c
FROM (select count(*) as c from yeterdays_table where time between now() - interval '24 hours' and now() - interval '23 hours 45 mins') a,
(select count(*) as c from todays_table where time = now() - interval '15 minutes') b;
Bear in mind you need to single-quote your intervals, and your table names cannot have quotes in them.
Currently I need to send an Email to all users that have 5 days with their payment due_date expired and are status=1 (pending to pay) for the current month and year because they might have future dates or past dates. example
due_date= 27/06/2018 send email after 5 days 1/05/2018
my Query to grab all users with a interval within 5 days is the following:
SELECT payments_payment.id, payments_payment.due_date
FROM payments_payment
WHERE payments_payment.due_date < NOW() - '5 day'::interval
AND payments_payment.status = 1
AND EXTRACT(year FROM payments_payment.due_date) = EXTRACT(year FROM NOW())
AND EXTRACT(month FROM payments_payment.due_date) = EXTRACT(month FROM NOW())
ORDER BY payments_payment.due_date ASC;
Need to make a different approach since the question is inverse for that reason I need to get the difference between 2 dates and see if it matches my day limit here is the Query.
PostgreSQL Query:
SELECT due_date
FROM payments_payment
WHERE payments_payment.due_date + interval '5 day' < current_date
AND payments_payment.status = 1
Explanation
Get all payment dates where status equals 1 and month equals current month and year where the due_date substracted by current date is equals to 5 days.
Ive been searching for something like that using PostgreSQL, but havent found yet.
Lets suppose i have the following table:
id order amount created_at
2 527837 10.0 2014-12-01T...
3 527838 50.0 2014-12-02T...
4 527839 30.0 2014-12-02T...
5 527840 40.0 2014-12-10T...
6 527841 80.0 2014-12-13T...
And i want to have a query that returns the sum of all amounts for each full week of 7 days (even if some day had no orders):
Example:
week total_amount
Dec/01 - Dec/07 90.0
Dec/08 - Dec/15 120.0
Dec/16 - Dec/23 0.0
//...and so on until current date
Also, lets suppose, that January has 30 days, and February has 28 days, i want the weeks to be grouped like that:
Jan/01-Jan/08
Jan/09-Jan/16
Jan/17-Jan/24
Jan/25-Feb/02 (theres no problem on crossing months)
Feb/03-Feb/10
What is the best way to do this?
EDIT 1:
I have found a way to build a query to generate a temporary table with the days i need for my grouping, i just having dificult grouping this and joining it with my original table...
(SELECT TO_CHAR(generate_series, 'YYYY-MM-DD') as "day" FROM generate_series('2013-06-01 00:00'::timestamp,
'2015-06-01 00:00'::timestamp, '1 Day'))
select date_trunc('week', created_At),date_trunc('week', created_At)+ INTERVAL '6' DAY,
SUM(amount)
from t
GROUP BY date_trunc('week', created_At)
ORDER BY MIN(created_At);
FIDDLE